可以使用算术运算符在0和1之间切换吗

有没有办法不使用逻辑和位运算符，只使用算术运算符，在值为0和1的整数之间切换？

如果变量为0，variable ?= variable将使变量为1; 如果为1，则使变量为0。

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最佳答案 
x = 1 - x

Will switch between 0 and 1.

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int flip(int i){
return 1 - i;
};
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Assuming that it is initialized as a 0 or 1:

x = 1 - x
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Just for a bit of variety:

x = 1 / (x + 1);


x = (x == 0);


x = (x != 1);

Not sure whether you consider == and != to be arithmetic operators. Probably not, and obviously although they work in C, more strongly typed languages wouldn't convert the result to integer.

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Edit: I misread the question, thought the OP could use any operator

A Few more...(ignore these)

x ^= 1       // bitwise operator
x = !x       // logical operator
x = (x <= 0) // kinda the same as x != 1

Without using an operator?

int arr[] = {1,0}
x = arr[x]
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Yet another way:

x = (x + 1) % 2
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Comedy variation on st0le's second method

x = "\1"[x]
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you can simply try this

+(!0) // output:1


+(!1) // output:0
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Another way to flip a bit. 

x = ABS(x - 1) // the absolute of (x - 1)
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You can use simple: abs(x-1) or just: int(not x)


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