VisualStudio 中的多行正则表达式

有没有办法让 VisualStudio 跨多行执行正则表达式替换(让匹配跨行边界) ?我知道有许多编辑器可以用于此,但是这个特性被 VisualStudio 忽略似乎有些奇怪。我错过了什么吗?

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Note: this answer is using the regex syntax used in Visual Studio up to and including VS 2012. In VS 2013 and later, the regex syntax has changed.

You can include \n in the expression. As an example, here is a regex that I use to "clean" auto-generated SQL scripts from anything that is not a stored procedure (it will match text blocks that start with a line containing "Object: " followed by something that is not "StoredProcedure", then matching the following lines up to a line consists of the word "GO"):

/\*+ Object\::b:b~(StoredProcedure)(.*\n)#GO\n

you may need to use \r\n at the end of your expression.

This works today in Visual Studio 2012:

fooPatternToStart.*(.*\n)+?.*barPatternToEnd

See how the (.*\n)+? part does the match across multiple lines, non-greedy.
fooPatternToStart is some regex pattern on your start line, while barPatternToEnd is your pattern to find on another line below, possibly many lines below...

Example found here.

Simple and effective :)

Note: before VS2012, the pattern that worked was: fooPatternToStart.(.\n)+@.*barPatternToEnd

Regular expressions have changed in Visual Studio 2013. https://msdn.microsoft.com/en-us/library/2k3te2cs(v=vs.120).aspx

To match an expression over two lines the code would now be:

StartOfExpression.*\r?\n.*EndOfExpression

Use (.*\n)*? to skip zero or more lines between your expressions.

start(.*\n)*?end

finds

start
two
three
end

? is the non-greedy operator, used to skip as few lines as possible.

If end is not the first word in the line, add .* to match the extra characters. I.e.: start(.*\n)*?.*end finds

start
two
three
four end end

If you only want to replace until the first end, add another non-greedy operator: start(.*\n)*?.*?end.

Historic: In Visual Studio 2017 (and early versions of 2019) you can also use the single line option in the Find and Replace dialog Ctrl-Shift-F like this:

(?s)start.*end

For more see the version history of this answer.

Non-greedy multi-line any character capture, Visual Studio 2013+:

.*?\r?\n.*?

Greedy version in Giles Roberts's answer.

For everyone coming here while searching for VS Code, I use this to match anything from script to anywhere with 2 newlines (newlines excluded):

script(.|\n)+?(?=\n\n)

replace script and \n\n to match everything between them.