Somewhat similar to your original attempt, but more Pythonic, is to use Python's standard negative-indexing convention to count backwards from the end:
These are few things which will help you in understanding everything... using iloc
In iloc, [initial row:ending row, initial column:ending column]
case 1: if you want only last column --- df.iloc[:,-1] & df.iloc[:,-1:]
this means that you want only the last column...
case 2: if you want all columns and all rows except the last column --- df.iloc[:,:-1]
this means that you want all columns and all rows except the last column...
case 3: if you want only last row --- df.iloc[-1:,:] & df.iloc[-1,:]
this means that you want only the last row...
case 4: if you want all columns and all rows except the last row --- df.iloc[:-1,:]
this means that you want all columns and all rows except the last column...
case 5: if you want all columns and all rows except the last row and last column --- df.iloc[:-1,:-1]
this means that you want all columns and all rows except the last column and last row...
When we split the dataframe to just get the last column:
If we split like:
y = df.iloc[:,-1:] - y remains a dataframe
However, if we split like
y = df.iloc[:,-1] - y becomes a Series.
This is a notable difference that I've found in the two approaches. If you don't care about the resultant type, you can use either of the two. Otherwise you need to take care of the above findings.
This is applicable for any number of rows you want to extract and not just the last row.
For example, if you want last n number of rows of a dataframe, where n is any integer less than or equal to the number of columns present in the dataframe, then you can easily do the following:
y = df.iloc[:,n:]
Replace n by the number of columns you want. Same is true for rows as well.