创建一个非常简单的链表

我正在尝试创建一个链接列表,只是想看看我是否能做到这一点,但是我在这方面遇到了困难。有人有一个使用 C # 实现非常简单的 Linked list 的例子吗?到目前为止我发现的所有例子都有些夸大其词。

213845 次浏览

这个不错:

  namespace ConsoleApplication1
{


// T is the type of data stored in a particular instance of GenericList.
public class GenericList<T>
{
private class Node
{
// Each node has a reference to the next node in the list.
public Node Next;
// Each node holds a value of type T.
public T Data;
}


// The list is initially empty.
private Node head = null;


// Add a node at the beginning of the list with t as its data value.
public void AddNode(T t)
{
Node newNode = new Node();
newNode.Next = head;
newNode.Data = t;
head = newNode;
}


// The following method returns the data value stored in the last node in
// the list. If the list is empty, the default value for type T is
// returned.
public T GetFirstAdded()
{
// The value of temp is returned as the value of the method.
// The following declaration initializes temp to the appropriate
// default value for type T. The default value is returned if the
// list is empty.
T temp = default(T);


Node current = head;
while (current != null)
{
temp = current.Data;
current = current.Next;
}
return temp;
}
}
}

测试代码:

static void Main(string[] args)
{
// Test with a non-empty list of integers.
GenericList<int> gll = new GenericList<int>();
gll.AddNode(5);
gll.AddNode(4);
gll.AddNode(3);
int intVal = gll.GetFirstAdded();
// The following line displays 5.
System.Console.WriteLine(intVal);
}

我在 msdn 给你上看到的

链表的核心是一组连接在一起的节点。

因此,您需要从一个简单的 Node 类开始:

public class Node {
public Node next;
public Object data;
}

然后,您的链表将有一个表示列表头(开始)的节点作为成员:

public class LinkedList {
private Node head;
}

然后,您需要通过添加方法向列表中添加功能。它们通常涉及沿着所有节点进行某种遍历。

public void printAllNodes() {
Node current = head;
while (current != null)
{
Console.WriteLine(current.data);
current = current.next;
}
}

此外,插入新数据是另一种常见操作:

public void Add(Object data) {
Node toAdd = new Node();
toAdd.data = data;
Node current = head;
// traverse all nodes (see the print all nodes method for an example)
current.next = toAdd;
}

这应该是一个很好的起点。

我是个初学者,这对我很有帮助:

class List
{
private Element Root;
}

首先创建包含所有方法的类 List。 然后创建 Node-Class,我将它命名为 Element

class Element
{
public int Value;
public Element Next;
}

然后可以开始向 List 类添加方法。

public void Add(int value)
{
Element newElement = new Element();
newElement.Value = value;


Element rootCopy = Root;
Root = newElement;
newElement.Next = rootCopy;


Console.WriteLine(newElement.Value);
}
public class Node
{
private Object data;


public Node next {get;set;}


public Node(Object data)
{
this.data = data;
}


}


public class Linkedlist
{
Node head;


public void Add(Node n)
{
n.Next = this.Head;
this.Head = n;
}
}

使用:

LinkedList sample = new LinkedList();
sample.add(new Node("first"));
sample.Add(new Node("second"))

根据@jjnguy 的说法,下面是完整的控制台应用程序示例:

public class Node
{
public Node next;
public Object data;
}


public class LinkedList
{
private Node head;


public void printAllNodes()
{
Node current = head;
while (current != null)
{
Console.WriteLine(current.data);
current = current.next;
}
}


public void AddFirst(Object data)
{
Node toAdd = new Node();


toAdd.data = data;
toAdd.next = head;


head = toAdd;
}


public void AddLast(Object data)
{
if (head == null)
{
head = new Node();


head.data = data;
head.next = null;
}
else
{
Node toAdd = new Node();
toAdd.data = data;


Node current = head;
while (current.next != null)
{
current = current.next;
}


current.next = toAdd;
}
}
}


class Program
{
static void Main(string[] args)
{
Console.WriteLine("Add First:");
LinkedList myList1 = new LinkedList();
       

myList1.AddFirst("Hello");
myList1.AddFirst("Magical");
myList1.AddFirst("World");
myList1.printAllNodes();


Console.WriteLine();


Console.WriteLine("Add Last:");
LinkedList myList2 = new LinkedList();


myList2.AddLast("Hello");
myList2.AddLast("Magical");
myList2.AddLast("World");
myList2.printAllNodes();


Console.ReadLine();
}
}
public class DynamicLinkedList
{


private class Node
{
private object element;
private Node next;


public object Element
{
get { return this.element; }
set { this.element = value; }
}


public Node Next
{
get { return this.next; }
set { this.next = value; }
}


public Node(object element, Node prevNode)
{
this.element = element;
prevNode.next = this;
}


public Node(object element)
{
this.element = element;
next = null;
}
}


private Node head;
private Node tail;
private int count;


public DynamicLinkedList()
{
this.head = null;
this.tail = null;
this.count = 0;
}


public void AddAtLastPosition(object element)
{
if (head == null)
{
head = new Node(element);
tail = head;
}
else
{
Node newNode = new Node(element, tail);
tail = newNode;
}


count++;
}


public object GetLastElement()
{
object lastElement = null;
Node currentNode = head;


while (currentNode != null)
{
lastElement = currentNode.Element;
currentNode = currentNode.Next;
}


return lastElement;
}


}

测试:

static void Main(string[] args)
{
DynamicLinkedList list = new DynamicLinkedList();
list.AddAtLastPosition(1);
list.AddAtLastPosition(2);
list.AddAtLastPosition(3);
list.AddAtLastPosition(4);
list.AddAtLastPosition(5);


object lastElement = list.GetLastElement();
Console.WriteLine(lastElement);
}
public class Node<T>
{
public T item;
public Node<T> next;
public Node()
{
this.next = null;
}
}




class LinkList<T>
{
public Node<T> head { get; set; }
public LinkList()
{
this.head = null;
}




public void AddAtHead(T item)
{
Node<T> newNode = new Node<T>();
newNode.item = item;
if (this.head == null)
{
this.head = newNode;
}
else
{
newNode.next = head;
this.head = newNode;
}
}


public void AddAtTail(T item)
{
Node<T> newNode = new Node<T>();
newNode.item = item;
if (this.head == null)
{
this.head = newNode;
}
else
{
Node<T> temp = this.head;
while (temp.next != null)
{
temp = temp.next;
}
temp.next = newNode;
}
}


public void DeleteNode(T item)
{
if (this.head.item.Equals(item))
{
head = head.next;
}
else
{
Node<T> temp = head;
Node<T> tempPre = head;
bool matched = false;
while (!(matched = temp.item.Equals(item)) && temp.next != null)
{
tempPre = temp;
temp = temp.next;
}
if (matched)
{
tempPre.next = temp.next;
}
else
{
Console.WriteLine("Value not found!");
}
}
}


public bool searchNode(T item)
{
Node<T> temp = this.head;
bool matched = false;
while (!(matched = temp.item.Equals(item)) && temp.next != null)
{
temp = temp.next;
}
return matched;


}
public void DisplayList()
{
Console.WriteLine("Displaying List!");
Node<T> temp = this.head;
while (temp != null)
{
Console.WriteLine(temp.item);
temp = temp.next;
}
}


}

Dmytro 做得很好,但这里有一个更简洁的版本。

class Program
{
static void Main(string[] args)
{
LinkedList linkedList = new LinkedList(1);


linkedList.Add(2);
linkedList.Add(3);
linkedList.Add(4);


linkedList.AddFirst(0);


linkedList.Print();
}
}


public class Node
{
public Node(Node next, Object value)
{
this.next = next;
this.value = value;
}


public Node next;
public Object value;
}


public class LinkedList
{
public Node head;


public LinkedList(Object initial)
{
head = new Node(null, initial);
}


public void AddFirst(Object value)
{
head = new Node(head, value);
}


public void Add(Object value)
{
Node current = head;


while (current.next != null)
{
current = current.next;
}


current.next = new Node(null, value);
}


public void Print()
{
Node current = head;


while (current != null)
{
Console.WriteLine(current.value);
current = current.next;
}
}
}

添加 Node 类。
然后添加一个 LinkedList 类来实现链表
添加测试类以执行链表

namespace LinkedListProject
{
public class Node
{
public Node next;
public object data;
}


public class MyLinkedList
{
Node head;
public Node AddNodes(Object data)
{
Node node = new Node();


if (node.next == null)
{
node.data = data;
node.next = head;
head = node;
}
else
{
while (node.next != null)
node = node.next;


node.data = data;
node.next = null;


}
return node;
}


public void printnodes()
{
Node current = head;
while (current.next != null)
{
Console.WriteLine(current.data);
current = current.next;
}
Console.WriteLine(current.data);
}
}




[TestClass]
public class LinkedListExample
{
MyLinkedList linkedlist = new MyLinkedList();
[TestMethod]
public void linkedlisttest()
{
linkedlist.AddNodes("hello");
linkedlist.AddNodes("world");
linkedlist.AddNodes("now");
linkedlist.printnodes();
}
}
}

这是一个很好的实现。

  1. 它很短,但是实现了 Add (x)、 Delete (x)、 Contain (x)和 Print ()。
  2. 它避免了在添加到空列表或删除第一个元素时的特殊处理。 其他大多数例子在删除第一个元素时都进行了特殊处理。
  3. 列表可以包含任何数据类型。

    using System;
    
    
    class Node<Type> : LinkedList<Type>
    {   // Why inherit from LinkedList? A: We need to use polymorphism.
    public Type value;
    public Node(Type value) { this.value = value; }
    }
    class LinkedList<Type>
    {
    Node<Type> next;  // This member is treated as head in class LinkedList, but treated as next element in class Node.
    /// <summary> if x is in list, return previos pointer of x. (We can see any class variable as a pointer.)
    /// if not found, return the tail of the list. </summary>
    protected LinkedList<Type> Previos(Type x)
    {
    LinkedList<Type> p = this;      // point to head
    for (; p.next != null; p = p.next)
    if (p.next.value.Equals(x))
    return p;               // find x, return the previos pointer.
    return p;                       // not found, p is the tail.
    }
    /// <summary> return value: true = success ; false = x not exist </summary>
    public bool Contain(Type x) { return Previos(x).next != null ? true : false; }
    /// <summary> return value: true = success ; false = fail to add. Because x already exist.
    /// </summary> // why return value? If caller want to know the result, they don't need to call Contain(x) before, the action waste time.
    public bool Add(Type x)
    {
    LinkedList<Type> p = Previos(x);
    if (p.next != null)             // Find x already in list
    return false;
    p.next = new Node<Type>(x);
    return true;
    }
    /// <summary> return value: true = success ; false = x not exist </summary>
    public bool Delete(Type x)
    {
    LinkedList<Type> p = Previos(x);
    if (p.next == null)
    return false;
    //Node<Type> node = p.next;
    p.next = p.next.next;
    //node.Dispose();       // GC dispose automatically.
    return true;
    }
    public void Print()
    {
    Console.Write("List: ");
    for (Node<Type> node = next; node != null; node = node.next)
    Console.Write(node.value.ToString() + " ");
    Console.WriteLine();
    }
    }
    class Test
    {
    static void Main()
    {
    LinkedList<int> LL = new LinkedList<int>();
    if (!LL.Contain(0)) // Empty list
    Console.WriteLine("0 is not exist.");
    LL.Print();
    LL.Add(0);      // Add to empty list
    LL.Add(1); LL.Add(2); // attach to tail
    LL.Add(2);      // duplicate add, 2 is tail.
    if (LL.Contain(0))// Find existed element which is head
    Console.WriteLine("0 is exist.");
    LL.Print();
    LL.Delete(0);   // Delete head
    LL.Delete(2);   // Delete tail
    if (!LL.Delete(0)) // Delete non-exist element
    Console.WriteLine("0 is not exist.");
    LL.Print();
    Console.ReadLine();
    }
    }
    

By the way, the implementation in http://www.functionx.com/csharp1/examples/linkedlist.htm have some problem:

  1. Delete() will fail when there is only 1 element. (Throw exception at line "Head.Next = Current.Next;" because Current is null.)
  2. Delete(position) will fail when deleting first element, In other words, call Delete(0) will fail.

这里有一个 IEnumerable和递归反向方法,虽然它并不比 Reverse方法中的 while 循环快,但它们都是 O (n) :

   public class LinkedList<T> : IEnumerable
{
private Node<T> _head = null;


public Node<T> Add(T value)
{
var node = new Node<T> {Value = value};


if (_head == null)
{
_head = node;
}
else
{
var current = _head;
while (current.Next != null)
{
current = current.Next;
}
current.Next = node; //new head
}


return node;
}


public T Remove(Node<T> node)
{
if (_head == null)
return node.Value;


if (_head == node)
{
_head = _head.Next;
node.Next = null;
return node.Value;
}


var current = _head;
while (current.Next != null)
{
if (current.Next == node)
{
current.Next = node.Next;
return node.Value;
}


current = current.Next;
}


return node.Value;
}


public void Reverse()
{
Node<T> prev = null;
var current = _head;


if (current == null)
return;


while (current != null)
{
var next = current.Next;
current.Next = prev;
prev = current;
current = next;
}


_head = prev;
}


public void ReverseRecursive()
{
reverseRecursive(_head, null);
}


private void reverseRecursive(Node<T> current, Node<T> prev)
{
if (current.Next == null)
{
_head = current;
_head.Next = prev;
return;
}


var next = current.Next;
current.Next = prev;
reverseRecursive(next, current);
}


public IEnumerator<T> Enumerator()
{
var current = _head;
while (current != null)
{
yield return current.Value;
current = current.Next;
}
}


public IEnumerator GetEnumerator()
{
return Enumerator();
}
}


public class Node<T>
{
public T Value { get; set; }
public Node<T> Next { get; set; }
}

用操作 AddItemStart,AddItemEnd,RemoveItemStart,RemoveItemEnd 和 DisplayAllItems实现单链表的简单 c # 程序

 using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Threading.Tasks;


namespace SingleLinkedList
{
class Program
{
Node head;
Node current;
int counter = 0;
public Program()
{
head = new Node();
current = head;
}
public void AddStart(object data)
{
Node newnode = new Node();
newnode.next = head.next;
newnode.data = data;
head.next = newnode;
counter++;
}
public void AddEnd(object data)
{
Node newnode = new Node();
newnode.data = data;
current.next = newnode;
current = newnode;
counter++;
}
public void RemoveStart()
{
if (counter > 0)
{
head.next = head.next.next;
counter--;
}
else
{
Console.WriteLine("No element exist in this linked list.");
}
}
public void RemoveEnd()
{
if (counter > 0)
{
Node prevNode = new Node();
Node cur = head;
while (cur.next != null)
{
prevNode = cur;
cur = cur.next;
}
prevNode.next = null;
}
else
{
Console.WriteLine("No element exist in this linked list.");
}
}
public void Display()
{
Console.Write("Head ->");
Node curr = head;
while (curr.next != null)
{
curr = curr.next;
Console.WriteLine(curr.data.ToString());
}
}
public class Node
{
public object data;
public Node next;
}
static void Main(string[] args)
{
Program p = new Program();
p.AddEnd(2);
p.AddStart(1);
p.AddStart(0);
p.AddEnd(3);
p.Display();
p.RemoveStart();
Console.WriteLine("Removed node from Start");
p.Display();
Console.WriteLine("Removed node from End");
p.RemoveEnd();
p.Display();
Console.ReadKey();
}
}
}

所选择的答案没有迭代器; 它更基本,但可能没有那么有用。

下面是一个带有迭代器/枚举器的实现,我的实现基于 Sedgewick 的包,请参见 http://algs4.cs.princeton.edu/13stacks/Bag.java.html

void Main()
{
var b = new Bag<string>();
b.Add("bike");
b.Add("erasmus");
b.Add("kumquat");
b.Add("beaver");
b.Add("racecar");
b.Add("barnacle");


foreach (var thing in b)
{
Console.WriteLine(thing);
}
}


// Define other methods and classes here


public class Bag<T> : IEnumerable<T>
{
public Node<T> first;// first node in list


public class Node<T>
{
public T item;
public Node<T> next;


public Node(T item)
{
this.item = item;
}
}




public void Add(T item)
{
Node<T> oldFirst = first;
first = new Node<T>(item);
first.next = oldFirst;
}


IEnumerator IEnumerable.GetEnumerator()
{
return GetEnumerator();
}


public IEnumerator<T> GetEnumerator()
{
return new BagEnumerator<T>(this);
}


public class BagEnumerator<V> : IEnumerator<T>
{
private Node<T> _head;
private Bag<T> _bag;
private Node<T> _curNode;




public BagEnumerator(Bag<T> bag)
{


_bag = bag;
_head = bag.first;
_curNode = default(Node<T>);


}


public T Current
{
get { return _curNode.item; }
}




object IEnumerator.Current
{
get { return Current; }
}


public bool MoveNext()
{
if (_curNode == null)
{
_curNode = _head;
if (_curNode == null)
return false;
return true;
}
if (_curNode.next == null)
return false;
else
{
_curNode = _curNode.next;
return true;
}


}


public void Reset()
{
_curNode = default(Node<T>); ;
}




public void Dispose()
{
}
}
}

我给出了一段摘录,摘自约瑟夫 · 阿尔巴哈里和本 · 阿尔巴哈里的《坚果里的 C # 6.0》一书

下面是使用 LinkedList 的演示:

var tune = new LinkedList<string>();
tune.AddFirst ("do"); // do
tune.AddLast ("so"); // do - so
tune.AddAfter (tune.First, "re"); // do - re- so
tune.AddAfter (tune.First.Next, "mi"); // do - re - mi- so
tune.AddBefore (tune.Last, "fa"); // do - re - mi - fa- so
tune.RemoveFirst(); // re - mi - fa - so
tune.RemoveLast(); // re - mi - fa
LinkedListNode<string> miNode = tune.Find ("mi");
tune.Remove (miNode); // re - fa
tune.AddFirst (miNode); // mi- re - fa
foreach (string s in tune) Console.WriteLine (s);

我已经创建了以下具有许多特性的 LinkedList 代码。

NodeLinkedList

Getters and Setters: First and Last

功能 : AddFirst(data), AddFirst(node), AddLast(data), RemoveLast(), AddAfter(node, data), RemoveBefore(node), Find(node), Remove(foundNode), Print(LinkedList)

using System;
using System.Collections.Generic;


namespace Codebase
{
public class Node
{
public object Data { get; set; }
public Node Next { get; set; }


public Node()
{
}


public Node(object Data, Node Next = null)
{
this.Data = Data;
this.Next = Next;
}
}


public class LinkedList
{
private Node Head;
public Node First
{
get => Head;
set
{
First.Data = value.Data;
First.Next = value.Next;
}
}


public Node Last
{
get
{
Node p = Head;
//Based partially on https://en.wikipedia.org/wiki/Linked_list
while (p.Next != null)
p = p.Next; //traverse the list until p is the last node.The last node always points to NULL.


return p;
}
set
{
Last.Data = value.Data;
Last.Next = value.Next;
}
}


public void AddFirst(Object data, bool verbose = true)
{
Head = new Node(data, Head);
if (verbose) Print();
}


public void AddFirst(Node node, bool verbose = true)
{
node.Next = Head;
Head = node;
if (verbose) Print();
}


public void AddLast(Object data, bool Verbose = true)
{
Last.Next = new Node(data);
if (Verbose) Print();
}


public Node RemoveFirst(bool verbose = true)
{
Node temp = First;
Head = First.Next;
if (verbose) Print();
return temp;
}


public Node RemoveLast(bool verbose = true)
{
Node p = Head;
Node temp = Last;


while (p.Next != temp)
p = p.Next;


p.Next = null;
if (verbose) Print();


return temp;
}


public void AddAfter(Node node, object data, bool verbose = true)
{
Node temp = new Node(data);
temp.Next = node.Next;
node.Next = temp;


if (verbose) Print();
}


public void AddBefore(Node node, object data, bool verbose = true)
{
Node temp = new Node(data);


Node p = Head;


while (p.Next != node) //Finding the node before
{
p = p.Next;
}


temp.Next = p.Next; //same as  = node
p.Next = temp;


if (verbose) Print();
}


public Node Find(object data)
{
Node p = Head;


while (p != null)
{
if (p.Data == data)
return p;


p = p.Next;
}
return null;
}


public void Remove(Node node, bool verbose = true)
{
Node p = Head;


while (p.Next != node)
{
p = p.Next;
}


p.Next = node.Next;
if (verbose) Print();
}


public void Print()
{
Node p = Head;
while (p != null) //LinkedList iterator
{
Console.Write(p.Data + " ");
p = p.Next; //traverse the list until p is the last node.The last node always points to NULL.
}
Console.WriteLine();
}
}
}

当她使用微软内置的 LinkedList 和 LinkedListNode 来回答这个问题时,使用@yogihost 回答,你可以得到同样的结果:

using System;
using System.Collections.Generic;
using Codebase;


namespace Cmd
{
static class Program
{
static void Main(string[] args)
{
var tune = new LinkedList(); //Using custom code instead of the built-in LinkedList<T>
tune.AddFirst("do"); // do
tune.AddLast("so"); // do - so
tune.AddAfter(tune.First, "re"); // do - re- so
tune.AddAfter(tune.First.Next, "mi"); // do - re - mi- so
tune.AddBefore(tune.Last, "fa"); // do - re - mi - fa- so
tune.RemoveFirst(); // re - mi - fa - so
tune.RemoveLast(); // re - mi - fa
Node miNode = tune.Find("mi"); //Using custom code instead of the built in LinkedListNode
tune.Remove(miNode); // re - fa
tune.AddFirst(miNode); // mi- re - fa
}
}

链表是基于节点的数据结构。每个节点设计为两个部分(数据和节点引用)。实际上,数据总是存储在数据部分(可能是原始数据类型,例如 Int,Float)。等,或者我们也可以存储用户定义的数据类型。对象引用) ,同样节点引用也应该包含对下一个节点的引用,如果没有下一个节点,则链将结束。

这个链将继续到任何没有下一个节点的参考点的节点。

请从我的技术博客 -http://www.algonuts.info/linked-list-program-in-java.html中找到源代码

package info.algonuts;


import java.util.ArrayList;
import java.util.Arrays;
import java.util.Iterator;
import java.util.List;


class LLNode {
int nodeValue;
LLNode childNode;


public LLNode(int nodeValue) {
this.nodeValue = nodeValue;
this.childNode = null;
}
}


class LLCompute {
private static LLNode temp;
private static LLNode previousNode;
private static LLNode newNode;
private static LLNode headNode;


public static void add(int nodeValue) {
newNode = new LLNode(nodeValue);
temp = headNode;
previousNode = temp;
if(temp != null)
{   compute();  }
else
{   headNode = newNode; }   //Set headNode
}


private static void compute() {
if(newNode.nodeValue < temp.nodeValue) {    //Sorting - Ascending Order
newNode.childNode = temp;
if(temp == headNode)
{   headNode = newNode; }
else if(previousNode != null)
{   previousNode.childNode = newNode;   }
}
else
{
if(temp.childNode == null)
{   temp.childNode = newNode;   }
else
{
previousNode = temp;
temp = temp.childNode;
compute();
}
}
}


public static void display() {
temp = headNode;
while(temp != null) {
System.out.print(temp.nodeValue+" ");
temp = temp.childNode;
}
}
}


public class LinkedList {
//Entry Point
public static void main(String[] args) {
//First Set Input Values
List <Integer> firstIntList = new ArrayList <Integer>(Arrays.asList(50,20,59,78,90,3,20,40,98));
Iterator<Integer> ptr  = firstIntList.iterator();
while(ptr.hasNext())
{   LLCompute.add(ptr.next());  }
System.out.println("Sort with first Set Values");
LLCompute.display();
System.out.println("\n");


//Second Set Input Values
List <Integer> secondIntList = new ArrayList <Integer>(Arrays.asList(1,5,8,100,91));
ptr  = secondIntList.iterator();
while(ptr.hasNext())
{   LLCompute.add(ptr.next());  }
System.out.println("Sort with first & Second Set Values");
LLCompute.display();
System.out.println();
}
}

我有一个双向链表,可以用作堆栈或队列。如果你看看代码,想想它是做什么的,它是怎么做的,我敢打赌你会理解关于它的一切。我很抱歉,但是不知道为什么我不能在这里补充完整的代码,所以我在这里是链接列表的链接(我也得到了解决方案中的二叉树) : https://github.com/szabeast/LinkedList_and_BinaryTree