检查 value isset 和 null

我需要检查 value 是否定义为任何值,包括 null。isset将空值视为未定义值并返回 false。以下面的例子为例:

$foo = null;


if(isset($foo)) // returns false
if(isset($bar)) // returns false
if(isset($foo) || is_null($foo)) // returns true
if(isset($bar) || is_null($bar)) // returns true, raises a notice

请注意,$bar是未定义的。

我需要找到一个满足以下条件的条件:

if(something($bar)) // returns false;
if(something($foo)) // returns true;

有什么想法吗?

72575 次浏览

You could use is_null and empty instead of isset(). Empty doesn't print an error message if the variable doesn't exist.

See Best way to test for a variable's existence in PHP; isset() is clearly broken

 if( array_key_exists('foo', $GLOBALS) && is_null($foo)) // true & true => true
if( array_key_exists('bar', $GLOBALS) && is_null($bar)) // false &  => false

is_null($bar) returns true, since it has no values at all. Alternatively, you can use:

if(isset($bar) && is_null($bar)) // returns false

to check if $bar is defined and will only return true if:

$bar = null;
if(isset($bar) && is_null($bar)) // returns true

Here some silly workaround using xdebug. ;-)

function is_declared($name) {
ob_start();
xdebug_debug_zval($name);
$content = ob_get_clean();


return !empty($content);
}


$foo = null;
var_dump(is_declared('foo')); // -> true


$bla = 'bla';
var_dump(is_declared('bla')); // -> true


var_dump(is_declared('bar')); // -> false

IIRC, you can use get_defined_vars() for this:

$foo = NULL;
$vars = get_defined_vars();
if (array_key_exists('bar', $vars)) {}; // Should evaluate to FALSE
if (array_key_exists('foo', $vars)) {}; // Should evaluate to TRUE

The following code written as PHP extension is equivalent to array_key_exists($name, get_defined_vars()) (thanks to Henrik and Hannes).

// get_defined_vars()
// https://github.com/php/php-src/blob/master/Zend/zend_builtin_functions.c#L1777
// array_key_exists
// https://github.com/php/php-src/blob/master/ext/standard/array.c#L4393


PHP_FUNCTION(is_defined_var)
{


char *name;
int name_len;


if (zend_parse_parameters(ZEND_NUM_ARGS() TSRMLS_CC, "s", &name, &name_len) == FAILURE) {
return;
}


if (!EG(active_symbol_table)) {
zend_rebuild_symbol_table(TSRMLS_C);
}


if (zend_symtable_exists(EG(active_symbol_table), name, name_len + 1)) {
RETURN_TRUE;
}


}

If you are dealing with object properties which might have a value of NULL you can use: property_exists() instead of isset()

<?php


class myClass {
public $mine;
private $xpto;
static protected $test;


function test() {
var_dump(property_exists($this, 'xpto')); //true
}
}


var_dump(property_exists('myClass', 'mine'));   //true
var_dump(property_exists(new myClass, 'mine')); //true
var_dump(property_exists('myClass', 'xpto'));   //true, as of PHP 5.3.0
var_dump(property_exists('myClass', 'bar'));    //false
var_dump(property_exists('myClass', 'test'));   //true, as of PHP 5.3.0
myClass::test();


?>

As opposed with isset(), property_exists() returns TRUE even if the property has the value NULL.

I have found that compact is a function that ignores unset variables but does act on ones set to null, so when you have a large local symbol table I would imagine you can get a more efficient solution over checking array_key_exists('foo', get_defined_vars()) by using array_key_exists('foo', compact('foo')):

$foo = null;
echo isset($foo) ? 'true' : 'false'; // false
echo array_key_exists('foo', compact('foo')) ? 'true' : 'false'; // true
echo isset($bar) ? 'true' : 'false'; // false
echo array_key_exists('bar', compact('bar')) ? 'true' : 'false'; // false

Update

As of PHP 7.3 compact() will give a notice for unset values, so unfortunately this alternative is no longer valid.

compact() now issues an E_NOTICE level error if a given string refers to an unset variable. Formerly, such strings have been silently skipped.

At risk of being downvoted, I wouldn't even bother - clearly PHP wanted you to logically think of NULL and Undef as the same. I just ran with it - I created a function:

bool isEmpty(& $davar);

that checks for isset (handles both null and undef), "", and array(). Note that this is purposefully not dealing with falseness; just empty. The & 'reference-izer' allows the variable to be passed even though undefined without an error message, and if you check for isset and return false first, your next checks against "" and array() can be made without error.

The next function takes advantage of this function and is used where you would use

$davar || some-default.

and that is:

mixed defaultForEmpty(& $daVar, $default);

which just has the condition:

if (isEmpty($daVar))
return $default;
else
return $daVar;

BTW, these work with object references, array indexes, $_GET, $_POST, etc..

I found this topic when I was looking for a solution for an array. to check for the presence of an array element that contains NULL, this construction helped me

    $arr= [];
$foo = 'foo';
$arr[$foo]= NULL;
if (array_key_exists('bar', $arr)) {}; // Should evaluate to FALSE
if (array_key_exists('foo', $arr)) {}; // Should evaluate to TRUE
if (array_key_exists($foo, $arr)) {}; // Should evaluate to TRUE

In my case I had the following code:

class SomeClass {


private $cachedInstance;


public instance()
{
if (! isset($this->cachedInstance)) {
$this->cachedInstance = GetCachedInstanceFromDb(); // long operation, that could return Null if the record not found
}


return $this->cachedInstance;
}
}

And it failed in a way that GetCachedInstanceFromDb() got called multiple times if it returned null. All because isset() would return false even if the property was explicitly set to Null.

So, I had to do the following changes:

  1. Declare the property with initial value set to False;

  2. Use strict (type-safe) comparison when checking for the current variable value;

class SomeClass {


private $cachedInstance = false; // #1


public instance()
{
if ($this->cachedInstance === false) { // #2
$this->cachedInstance = GetCachedInstanceFromDb();
}


return $this->cachedInstance;
}
}