如何处理通知时，应用程序在后台的Firebase
这是我的舱单:
<service android:name=".fcm.PshycoFirebaseMessagingServices">
<intent-filter>
<action android:name="com.google.firebase.MESSAGING_EVENT" />
</intent-filter>
</service>
<service android:name=".fcm.PshycoFirebaseInstanceIDService">
<intent-filter>
<action android:name="com.google.firebase.INSTANCE_ID_EVENT" />
</intent-filter>
</service>
当应用程序在后台和通知到达时，默认通知来了，不运行我的onMessageReceived代码。
这是我的onMessageReceived代码。如果我的应用程序在前台运行，而不是在后台运行，就会调用这个函数。我怎么能运行这段代码时，应用程序是在后台太?
// [START receive_message]
@Override
public void onMessageReceived(RemoteMessage remoteMessage) {
// TODO(developer): Handle FCM messages here.
// If the application is in the foreground handle both data and notification messages here.
// Also if you intend on generating your own notifications as a result of a received FCM
// message, here is where that should be initiated. See sendNotification method below.
data = remoteMessage.getData();
String title = remoteMessage.getNotification().getTitle();
String message = remoteMessage.getNotification().getBody();
String imageUrl = (String) data.get("image");
String action = (String) data.get("action");
Log.i(TAG, "onMessageReceived: title : "+title);
Log.i(TAG, "onMessageReceived: message : "+message);
Log.i(TAG, "onMessageReceived: imageUrl : "+imageUrl);
Log.i(TAG, "onMessageReceived: action : "+action);
if (imageUrl == null) {
sendNotification(title,message,action);
} else {
new BigPictureNotification(this,title,message,imageUrl,action);
}
}
// [END receive_message]
最佳答案