如何以编程方式设置网格行和列的位置

我在一个堆栈面板里有两个栅格。 第一个网格名为 GridX。 最初，在网格内部有一个2D 文本框数组(RowDefs/ColumnDefs)。 XAML 中的 TextBox 定义为

<TextBox x:Name="A1" Grid.Row="4" Grid.Column="5" TextAlignment="Center" />

我想以编程方式在 GridX 的相同位置添加一个 文本块。

效果一定是这样的

<TextBlock Grid.Row="4" Grid.Column="5"
HorizontalAlignment="Left" VerticalAlignment="Top" Text="10" FontSize="8"/>

如何添加这个。 我试过这个:

TextBlock tblock = new TextBlock();
GridX.SetColumn(tblock, cIndex);
GridX.SetRow(tblock, rIndex);

但失败了。

我又试了一次:

int rIndex = Grid.GetRow(txtBox);
int cIndex = Grid.GetColumn(txtBox);


TextBlock tblock = new TextBlock();
tblock.VerticalAlignment = VerticalAlignment.Top;
tblock.HorizontalAlignment = HorizontalAlignment.Left;
tblock.FontSize = 8;
tblock.Text = rc[i, j - 1];


Grid.SetColumn(tblock, cIndex);
Grid.SetRow(tblock, rIndex);


txtBox.MaxLength = 1;

现在的问题是 TextBlock 不可见。 TextBox 隐藏了它。 谢谢你的帮助。

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最佳答案

For attached properties you can either call SetValue on the object for which you want to assign the value:

tblock.SetValue(Grid.RowProperty, 4);

Or call the static Set method (not as an instance method like you tried) for the property on the owner type, in this case SetRow:

Grid.SetRow(tblock, 4);
小开

Here is an example which might help someone:

Grid test = new Grid();
test.ColumnDefinitions.Add(new ColumnDefinition());
test.ColumnDefinitions.Add(new ColumnDefinition());
test.RowDefinitions.Add(new RowDefinition());
test.RowDefinitions.Add(new RowDefinition());
test.RowDefinitions.Add(new RowDefinition());


Label t1 = new Label();
t1.Content = "Test1";
Label t2 = new Label();
t2.Content = "Test2";
Label t3 = new Label();
t3.Content = "Test3";
Label t4 = new Label();
t4.Content = "Test4";
Label t5 = new Label();
t5.Content = "Test5";
Label t6 = new Label();
t6.Content = "Test6";


Grid.SetColumn(t1, 0);
Grid.SetRow(t1, 0);
test.Children.Add(t1);


Grid.SetColumn(t2, 1);
Grid.SetRow(t2, 0);
test.Children.Add(t2);


Grid.SetColumn(t3, 0);
Grid.SetRow(t3, 1);
test.Children.Add(t3);


Grid.SetColumn(t4, 1);
Grid.SetRow(t4, 1);
test.Children.Add(t4);


Grid.SetColumn(t5, 0);
Grid.SetRow(t5, 2);
test.Children.Add(t5);


Grid.SetColumn(t6, 1);
Grid.SetRow(t6, 2);
test.Children.Add(t6);
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for (int i = 0; i < 6; i++)
{
test.ColumnDefinitions.Add(new ColumnDefinition());


Label t1 = new Label();
t1.Content = "Test" + i;


Grid.SetColumn(t1, i);
Grid.SetRow(t1, 0);
test.Children.Add(t1);
}
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Try this:

                Grid grid = new Grid(); //Define the grid
for (int i = 0; i < 36; i++) //Add 36 rows
{
ColumnDefinition columna = new ColumnDefinition()
{
Name = "Col_" + i,
Width = new GridLength(32.5),
};
grid.ColumnDefinitions.Add(columna);
}


for (int i = 0; i < 36; i++) //Add 36 columns
{
RowDefinition row = new RowDefinition();
row.Height = new GridLength(40, GridUnitType.Pixel);
grid.RowDefinitions.Add(row);
}


for (int i = 0; i < 36; i++)
{
for (int j = 0; j < 36; j++)
{
Label t1 = new Label()
{
FontSize = 10,
FontFamily = new FontFamily("consolas"),
FontWeight = FontWeights.SemiBold,
BorderBrush = Brushes.LightGray,
BorderThickness = new Thickness(2),
HorizontalContentAlignment = HorizontalAlignment.Center,
VerticalContentAlignment = VerticalAlignment.Center,
};
Grid.SetRow(t1, i);
Grid.SetColumn(t1, j);
grid.Children.Add(t1); //Add the Label Control to the Grid created
}
}

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