OpenCV & Python-图像太大,无法显示

我有一个6400 × 3200的图像,而我的屏幕是1280 × 800。因此,图像只需调整大小以便显示。我使用的是 Python 和 OpenCV 2.4.9。 根据 OpenCV 文档,

如果需要显示大于屏幕分辨率的图像,则需要在 imshow 之前调用 namedWindow (“”,WINDOW _ NORMAL)。

这就是我正在做的,但图像不适合在屏幕上,只有一部分显示,因为它太大了。我也试过使用 cv2.resizeWindow,但它没有任何区别。

import cv2
cv2.namedWindow("output", cv2.WINDOW_NORMAL)        # Create window with freedom of dimensions
# cv2.resizeWindow("output", 400, 300)              # Resize window to specified dimensions
im = cv2.imread("earth.jpg")                        # Read image
cv2.imshow("output", im)                            # Show image
cv2.waitKey(0)                                      # Display the image infinitely until any keypress
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Although I was expecting an automatic solution (fitting to the screen automatically), resizing solves the problem as well.

import cv2
cv2.namedWindow("output", cv2.WINDOW_NORMAL)    # Create window with freedom of dimensions
im = cv2.imread("earth.jpg")                    # Read image
imS = cv2.resize(im, (960, 540))                # Resize image
cv2.imshow("output", imS)                       # Show image
cv2.waitKey(0)                                  # Display the image infinitely until any keypress

In OpenCV, cv2.namedWindow() just creates a window object, but doesn't resize the original image. You can use cv2.resize(img, resolution) to solve the problem.

Here's what it displays, a 740 * 411 resolution image. The original image

image = cv2.imread("740*411.jpg")
cv2.imshow("image", image)
cv2.waitKey(0)
cv2.destroyAllWindows()

Here, it displays a 100 * 200 resolution image after resizing. Remember the resolution parameter use column first then is row.

Image after resizing

image = cv2.imread("740*411.jpg")
image = cv2.resize(image, (200, 100))
cv2.imshow("image", image)
cv2.waitKey(0)
cv2.destroyAllWindows()

Try this:

image = cv2.imread("img/Demo.jpg")
image = cv2.resize(image,(240,240))

The image is now resized. Displaying it will render in 240x240.

The other answers perform a fixed (width, height) resize. If you wanted to resize to a specific size while maintaining aspect ratio, use this

def ResizeWithAspectRatio(image, width=None, height=None, inter=cv2.INTER_AREA):
dim = None
(h, w) = image.shape[:2]


if width is None and height is None:
return image
if width is None:
r = height / float(h)
dim = (int(w * r), height)
else:
r = width / float(w)
dim = (width, int(h * r))


return cv2.resize(image, dim, interpolation=inter)

Example

image = cv2.imread('img.png')
resize = ResizeWithAspectRatio(image, width=1280) # Resize by width OR
# resize = ResizeWithAspectRatio(image, height=1280) # Resize by height


cv2.imshow('resize', resize)
cv2.waitKey()

Try with this code:

from PIL import Image


Image.fromarray(image).show()

Use this for example:

cv2.namedWindow('finalImg', cv2.WINDOW_NORMAL)
cv2.imshow("finalImg",finalImg)

Looks like opencv lib is pretty sensitive to parameters passed to the methods. The following code worked for me using opencv 4.3.0:

win_name = "visualization"  #  1. use var to specify window name everywhere
cv2.namedWindow(win_name, cv2.WINDOW_NORMAL)  #  2. use 'normal' flag
img = cv2.imread(filename)
h,w = img.shape[:2]  #  suits for image containing any amount of channels
h = int(h / resize_factor)  #  one must compute beforehand
w = int(w / resize_factor)  #  and convert to INT
cv2.resizeWindow(win_name, w, h)  #  use variables defined/computed BEFOREHAND
cv2.imshow(win_name, img)

The only way resizeWindow worked for me was to have it after imshow. This is the order I'm using:

# Create a Named Window
cv2.namedWindow(win_name, cv2.WINDOW_NORMAL)


# Move it to (X,Y)
cv2.moveWindow(win_name, X, Y)
    

# Show the Image in the Window
cv2.imshow(win_name, image)
    

# Resize the Window
cv2.resizeWindow(win_name, width, height)
    

# Wait for <> miliseconds
cv2.waitKey(wait_time)

The cv2.WINDOW_NORMAL option works correctly but the first time it displays the window in an standard size.

If you resize the window like any other windows in your computer, by position the mouse over the edge of the window you want to resize and then drag the mouse to the position you want. If you do this to both width and height of the window to the size you want to obtain.

The following times you refresh the window, by executing the code, OpenCV will generate the window with the size of the last time it was shown or modified.

This code will resize the image so that it can retain it's aspect ratio and only ever take up a specified fraction of the screen area.

It will automatically adjust depending on your screen size and the size of the image.

Use the area variable to change the max screen area you want the image to be able to take up. The example shows it displayed at quarter the screen size.

import cv2
import tkinter as tk
from math import *


img = cv2.imread("test.jpg")
area = 0.25


h, w = img.shape[:2]
root = tk.Tk()
screen_h = root.winfo_screenheight()
screen_w = root.winfo_screenwidth()
vector = sqrt(area)
window_h = screen_h * vector
window_w = screen_w * vector


if h > window_h or w > window_w:
if h / window_h >= w / window_w:
multiplier = window_h / h
else:
multiplier = window_w / w
img = cv2.resize(img, (0, 0), fx=multiplier, fy=multiplier)


cv2.imshow("output", img)
cv2.waitKey(0)

I've also made a similar function where area is still a parameter but so is window height and window width.

If no area is input then it will use a defined height and width (window_h, window_w) of the window size you would like the image to fit inside.

If an input is given for all parameters then 'area' is prioritised.

import cv2
import tkinter as tk
from math import *


def resize_image(img, area=0.0, window_h=0, window_w=0):
h, w = img.shape[:2]
root = tk.Tk()
screen_h = root.winfo_screenheight()
screen_w = root.winfo_screenwidth()


if area != 0.0:
vector = math.sqrt(area)
window_h = screen_h * vector
window_w = screen_w * vector


if h > window_h or w > window_w:
if h / window_h >= w / window_w:
multiplier = window_h / h
else:
multiplier = window_w / w
img = cv2.resize(img, (0, 0), fx=multiplier, fy=multiplier)


return img


# using area
initial_image = cv2.imread("test.jpg")
resized_image = resize_image(initial_image, area=0.25))
cv2.imshow("output", resized_image)
cv2.waitKey(0)


# using window height and width
initial_image = cv2.imread("test.jpg")
resized_image = resize_image(initial_image, window_h = 480, window_w = 270))
cv2.imshow("output", resized_image)
cv2.waitKey(0)

Try this code:

img = cv2.imread("Fab2_0.1 X 1.03MM GRID.jpg", cv2.IMREAD_GRAYSCALE)
image_scale_down = 3
x = (int)(img.shape[0]/image_scale_down)
y = (int)(img.shape[1]/image_scale_down)
image = cv2.resize(img, (x,y))
cv2.imshow("image_title", image)
cv2.waitKey(5000)
cv2.destroyAllWindows()

The most upvote answer is perfect ! I just add my code for those who want some "dynamic" resize handling depending of the ratio.

import cv2
from win32api import GetSystemMetrics


def get_resized_for_display_img(img):
screen_w, screen_h = GetSystemMetrics(0), GetSystemMetrics(1)
print("screen size",screen_w, screen_h)
h,w,channel_nbr = img.shape
# img get w of screen and adapt h
h = h * (screen_w / w)
w = screen_w
if h > screen_h: #if img h still too big
# img get h of screen and adapt w
w = w * (screen_h / h)
h = screen_h
w, h = w*0.9, h*0.9 # because you don't want it to be that big, right ?
w, h = int(w), int(h) # you need int for the cv2.resize
return cv2.resize(img, (w, h))

Try this code

img = cv2.resize(img,(1280,800))