Django 如何知道呈现表单字段的顺序?

如果我有一个 Django 表单,比如:

class ContactForm(forms.Form):
subject = forms.CharField(max_length=100)
message = forms.CharField()
sender = forms.EmailField()

我调用这个表单的一个实例的 as _ table ()方法,Django 将按照上面指定的顺序呈现字段。

我的问题是 Django 如何知道类变量定义的顺序?

(还有如何覆盖这个顺序,例如,当我想从类的 Init方法中添加一个字段时?)

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It has to do with the meta class that is used in defining the form class. I think it keeps an internal list of the fields and if you insert into the middle of the list it might work. It has been a while since I looked at that code.

Form fields have an attribute for creation order, called creation_counter. .fields attribute is a dictionary, so simple adding to dictionary and changing creation_counter attributes in all fields to reflect new ordering should suffice (never tried this, though).

I went ahead and answered my own question. Here's the answer for future reference:

In Django form.py does some dark magic using the __new__ method to load your class variables ultimately into self.fields in the order defined in the class. self.fields is a Django SortedDict instance (defined in datastructures.py).

So to override this, say in my example you wanted sender to come first but needed to add it in an init method, you would do:

class ContactForm(forms.Form):
subject = forms.CharField(max_length=100)
message = forms.CharField()
def __init__(self,*args,**kwargs):
forms.Form.__init__(self,*args,**kwargs)
#first argument, index is the position of the field you want it to come before
self.fields.insert(0,'sender',forms.EmailField(initial=str(time.time())))

Use a counter in the Field class. Sort by that counter:

import operator
import itertools


class Field(object):
_counter = itertools.count()
def __init__(self):
self.count = Field._counter.next()
self.name = ''
def __repr__(self):
return "Field(%r)" % self.name


class MyForm(object):
b = Field()
a = Field()
c = Field()


def __init__(self):
self.fields = []
for field_name in dir(self):
field = getattr(self, field_name)
if isinstance(field, Field):
field.name = field_name
self.fields.append(field)
self.fields.sort(key=operator.attrgetter('count'))


m = MyForm()
print m.fields # in defined order

Output:

[Field('b'), Field('a'), Field('c')]

[NOTE: this answer is now pretty completely outdated - please see the discussion below it, and more recent answers].

If f is a form, its fields are f.fields, which is a django.utils.datastructures.SortedDict (it presents the items in the order they are added). After form construction f.fields has a keyOrder attribute, which is a list containing the field names in the order they should be presented. You can set this to the correct ordering (though you need to exercise care to ensure you don't omit items or add extras).

Here's an example I just created in my current project:

class PrivEdit(ModelForm):
def __init__(self, *args, **kw):
super(ModelForm, self).__init__(*args, **kw)
self.fields.keyOrder = [
'super_user',
'all_districts',
'multi_district',
'all_schools',
'manage_users',
'direct_login',
'student_detail',
'license']
class Meta:
model = Privilege

For future reference: things have changed a bit since newforms. This is one way of reordering fields from base formclasses you have no control over:

def move_field_before(form, field, before_field):
content = form.base_fields[field]
del(form.base_fields[field])
insert_at = list(form.base_fields).index(before_field)
form.base_fields.insert(insert_at, field, content)
return form

Also, there's a little bit of documentation about the SortedDict that base_fields uses here: http://code.djangoproject.com/wiki/SortedDict

Fields are listed in the order they are defined in ModelClass._meta.fields. But if you want to change order in Form, you can do by using keyOrder function. For example :

class ContestForm(ModelForm):
class Meta:
model = Contest
exclude=('create_date', 'company')


def __init__(self, *args, **kwargs):
super(ContestForm, self).__init__(*args, **kwargs)
self.fields.keyOrder = [
'name',
'description',
'image',
'video_link',
'category']

Using fields in inner Meta class is what worked for me on Django==1.6.5:

#!/usr/bin/env python
# -*- coding: utf-8 -*-


"""
Example form declaration with custom field order.
"""


from django import forms


from app.models import AppModel




class ExampleModelForm(forms.ModelForm):
"""
An example model form for ``AppModel``.
"""
field1 = forms.CharField()
field2 = forms.CharField()


class Meta:
model = AppModel
fields = ['field2', 'field1']

As simple as that.

I've used this to move fields about:

def move_field_before(frm, field_name, before_name):
fld = frm.fields.pop(field_name)
pos = frm.fields.keys().index(before_name)
frm.fields.insert(pos, field_name, fld)

This works in 1.5 and I'm reasonably sure it still works in more recent versions.

If either fields = '__all__':

class AuthorForm(ModelForm):
class Meta:
model = Author
fields = '__all__'

or exclude are used:

class PartialAuthorForm(ModelForm):
class Meta:
model = Author
exclude = ['title']

Then Django references the order of fields as defined in the model. This just caught me out, so I thought I'd mention it. It's referenced in the ModelForm docs:

If either of these are used, the order the fields appear in the form will be the order the fields are defined in the model, with ManyToManyField instances appearing last.

With Django >= 1.7 your must modify ContactForm.base_fields as below:

from collections import OrderedDict


...


class ContactForm(forms.Form):
...


ContactForm.base_fields = OrderedDict(
(k, ContactForm.base_fields[k])
for k in ['your', 'field', 'in', 'order']
)

This trick is used in Django Admin PasswordChangeForm: Source on Github

As of Django 1.7 forms use OrderedDict which does not support the append operator. So you have to rebuild the dictionary from scratch...

class ChecklistForm(forms.ModelForm):


class Meta:
model = Checklist
fields = ['name', 'email', 'website']


def __init__(self, guide, *args, **kwargs):
self.guide = guide
super(ChecklistForm, self).__init__(*args, **kwargs)


new_fields = OrderedDict()
for tier, tasks in guide.tiers().items():
questions = [(t['task'], t['question']) for t in tasks if 'question' in t]
new_fields[tier.lower()] = forms.MultipleChoiceField(
label=tier,
widget=forms.CheckboxSelectMultiple(),
choices=questions,
help_text='desired set of site features'
)


new_fields['name'] = self.fields['name']
new_fields['email'] = self.fields['email']
new_fields['website'] = self.fields['website']
self.fields = new_fields

New to Django 1.9 is Form.field_order and Form.order_fields().

# forms.Form example
class SignupForm(forms.Form):


password = ...
email = ...
username = ...


field_order = ['username', 'email', 'password']




# forms.ModelForm example
class UserAccount(forms.ModelForm):


custom_field = models.CharField(max_length=254)


def Meta:
model = User
fields = ('username', 'email')


field_order = ['username', 'custom_field', 'password']

The easiest way to order fields in django 1.9 forms is to use field_order in your form Form.field_order

Here is a small example

class ContactForm(forms.Form):
subject = forms.CharField(max_length=100)
message = forms.CharField()
sender = forms.EmailField()
field_order = ['sender','message','subject']

This will show everything in the order you specified in field_order dict.

None of these answers worked for me, Actually, you do not have to do anything custom, you can just order the fields in the order you want in your Model class. For eg ... the below code

from django.db import models




class Student(models.Model):
class Meta:
verbose_name_plural = "categories"


id = models.AutoField(primary_key=True)
name = models.CharField(max_length=300)
nick_name = models.CharField(max_length=300)
created_at = models.DateTimeField(auto_now_add=True)
updated_at = models.DateTimeField(auto_now=True)


def __str__(self):
return self.name

Your admin interface for model Will display the fields exactly in the same order in which you have declared in this case it will be (id, name, nick_name )

To add something, you can use this (Django 3+):

class ...(forms.ModelForm):
field = ...


class Meta:
model = Xxxxxx
fields = '__all__'
    

field_order = ['field', '__all__']

__all__ works