如何设置 cron 作业以每小时运行一个可执行文件？

我需要设置一个 cron 作业，它每小时运行一次使用 gcc 编译的可执行文件。

我以 root 用户身份登录并键入 crontab -e

然后我输入以下内容并保存文件。

0 * * * *  /path_to_executable

但是，cron 作业不工作。

我看到当我输入 abc 0的时候我得到了一个内存区段错误。我只能从它所在的文件夹中执行可执行文件。我有办法解决这个问题吗？

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小开

use

path_to_exe >> log_file

to see the output of your command also errors can be redirected with

path_to_exe &> log_file

also you can use

crontab -l

to check if your edits were saved.

小开

最佳答案

0 * * * * cd folder_containing_exe && ./exe_name

should work unless there is something else that needs to be setup for the program to run.

小开

Since I could not run the C executable that way, I wrote a simple shell script that does the following

cd /..path_to_shell_script
./c_executable_name

In the cron jobs list, I call the shell script.

小开

Did you mean the executable fails to run , if invoked from any other directory? This is rather a bug on the executable. One potential reason could be the executable requires some shared libraires from the installed folder. You may check environment variable LD_LIBRARY_PATH

小开

The solution to solve this is to find out why you're getting the segmentation fault, and fix that.

小开

You can also use @hourly instant of 0 * * * *

小开

If you're using Ubuntu, you can put a shell script in one of these directories: /etc/cron.daily, /etc/cron.hourly, /etc/cron.monthly or /etc/cron.weekly.

For more detail, check out this post: https://askubuntu.com/questions/2368/how-do-i-set-up-a-cron-job