How to combine the sequence of objects in jq into one object?

小开

If your input is a stream of objects, then unless your jq has inputs, the objects must be "slurped", e.g. using the -s command-line option, in order to combine them.

Thus one way to combine objects in the input stream is to use:

jq -s add

For the second problem, creating an array:

jq -s .

There are of course other alternatives, but these are simple and do not require the most recent version of jq. With jq 1.5 and later, you can use 'inputs', e.g. jq -n '[inputs]'

Efficient solution

For the first problem (reduction), rather than slurping (whether via the -s option, or using [inputs]), it would be more efficient to use reduce with inputs and the -n command-line option. For example, to combine the stream of objects into a single object:

jq -n 'reduce inputs as $in (null; . + $in)'

Equivalently, without --null-input:

jq 'reduce inputs as $in (.; . + $in)

小开

An alternative to slurping using the -s command-line option is to use the inputs filter. Like so:

jq -n '[inputs] | add'

This will produce an object with all the input objects combined.

小开

To combine objects into an array you can use the following:

$ echo '
{
"a": "green",
"b": "white"
}
{
"a": "red",
"c": "purple"
}' | jq -n '[inputs]'
[
{
"a": "green",
"b": "white"
},
{
"a": "red",
"c": "purple"
}
]

小开

If you got to this point via jq filter rather than external input, mwag's comment suggesting wrapping your jq filter in []s might be useful.

Example:

$ echo '[{"foo":42},{"foo":43}]' | jq '.[]'
{
"foo": 42
}
{
"foo": 43
}
$ echo '[{"foo":42},{"foo":43}]' | jq '[.[]]'
[
{
"foo": 42
},
{
"foo": 43
}
]