You have to create a translation table using maketrans that you pass to the str.translate method.
In Python 3.1 and newer, maketrans is now a static-method on the str type, so you can use it to create a translation of each punctuation you want to None.
import string
# Thanks to Martijn Pieters for this improved version
# This uses the 3-argument version of str.maketrans
# with arguments (x, y, z) where 'x' and 'y'
# must be equal-length strings and characters in 'x'
# are replaced by characters in 'y'. 'z'
# is a string (string.punctuation here)
# where each character in the string is mapped
# to None
translator = str.maketrans('', '', string.punctuation)
# This is an alternative that creates a dictionary mapping
# of every character from string.punctuation to None (this will
# also work)
#translator = str.maketrans(dict.fromkeys(string.punctuation))
s = 'string with "punctuation" inside of it! Does this work? I hope so.'
# pass the translator to the string's translate method.
print(s.translate(translator))
This should output:
string with punctuation inside of it Does this work I hope so
I just compared the three methods by speed. translate is slower than re.sub (with precomilation) in about 10 times. And str.replace is faster than re.sub in about 3 times. By str.replace I mean:
for ch in string.punctuation:
s = s.replace(ch, "'")
The .maketrans() method takes three arguments - the first two are empty strings, and the third is the list of punctuation we want to remove. This tells the function to replace all punctuation with 'None'.
Additionally, you can view the punctuation attribute that comes with the string library by running: