如何在 Python 3. x 中使用. trans()删除字符串中的句读?

我想删除文本文件中的所有句读。方法翻译()方法。它似乎在 Python 2.x 下工作得很好,但在 Python 3.4下似乎什么也做不了。

我的代码如下,输出与输入文本相同。

import string
fhand = open("Hemingway.txt")
for fline in fhand:
fline = fline.rstrip()
print(fline.translate(string.punctuation))
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The call signature of str.translate has changed and apparently the parameter deletechars has been removed. You could use

import re
fline = re.sub('['+string.punctuation+']', '', fline)

instead, or create a table as shown in the other answer.

You have to create a translation table using maketrans that you pass to the str.translate method.

In Python 3.1 and newer, maketrans is now a static-method on the str type, so you can use it to create a translation of each punctuation you want to None.

import string


# Thanks to Martijn Pieters for this improved version


# This uses the 3-argument version of str.maketrans
# with arguments (x, y, z) where 'x' and 'y'
# must be equal-length strings and characters in 'x'
# are replaced by characters in 'y'. 'z'
# is a string (string.punctuation here)
# where each character in the string is mapped
# to None
translator = str.maketrans('', '', string.punctuation)


# This is an alternative that creates a dictionary mapping
# of every character from string.punctuation to None (this will
# also work)
#translator = str.maketrans(dict.fromkeys(string.punctuation))


s = 'string with "punctuation" inside of it! Does this work? I hope so.'


# pass the translator to the string's translate method.
print(s.translate(translator))

This should output:

string with punctuation inside of it Does this work I hope so

I just compared the three methods by speed. translate is slower than re.sub (with precomilation) in about 10 times. And str.replace is faster than re.sub in about 3 times. By str.replace I mean:

for ch in string.punctuation:
s = s.replace(ch, "'")

In python3.x ,it can be done using :

import string
#make translator object
translator=str.maketrans('','',string.punctuation)
string_name=string_name.translate(translator)

Late answer, but to remove all punctuation on python >= 3.6, you can also use:

import re, string


clean_string = re.sub(rf"[{string.punctuation}]", "", dirty_string)

Demo

In Python 3.6 you can use the following to remove punctuation:

import string


your_string.translate(str.maketrans('', '',string.punctuation))

The .maketrans() method takes three arguments - the first two are empty strings, and the third is the list of punctuation we want to remove. This tells the function to replace all punctuation with 'None'.

Additionally, you can view the punctuation attribute that comes with the string library by running:

print(string.punctuation)