左外连接在LINQ - 开卷题库

小开

看看这个例子。

var leftFinal = from left in lefts
join right in rights on left equals right.Left into leftRights
from leftRight in leftRights.DefaultIfEmpty()
select new { LeftId = left.Id, RightId = left.Key==leftRight.Key ? leftRight.Id : 0 };

小开

如“执行左外接合”;所述:

var q =
from c in categories
join pt in products on c.Category equals pt.Category into ps_jointable
from p in ps_jointable.DefaultIfEmpty()
select new { Category = c, ProductName = p == null ? "(No products)" : p.ProductName };

小开

使用lambda表达式

db.Categories
.GroupJoin(db.Products,
Category => Category.CategoryId,
Product => Product.CategoryId,
(x, y) => new { Category = x, Products = y })
.SelectMany(
xy => xy.Products.DefaultIfEmpty(),
(x, y) => new { Category = x.Category, Product = y })
.Select(s => new
{
CategoryName = s.Category.Name,
ProductName = s.Product.Name
});

小开

通过扩展方法的左外连接的实现如下所示

public static IEnumerable<Result> LeftJoin<TOuter, TInner, TKey, Result>(
this IEnumerable<TOuter> outer, IEnumerable<TInner> inner
, Func<TOuter, TKey> outerKeySelector, Func<TInner, TKey> innerKeySelector
, Func<TOuter, TInner, Result> resultSelector, IEqualityComparer<TKey> comparer)
{
if (outer == null)
throw new ArgumentException("outer");


if (inner == null)
throw new ArgumentException("inner");


if (outerKeySelector == null)
throw new ArgumentException("outerKeySelector");


if (innerKeySelector == null)
throw new ArgumentException("innerKeySelector");


if (resultSelector == null)
throw new ArgumentException("resultSelector");


return LeftJoinImpl(outer, inner, outerKeySelector, innerKeySelector, resultSelector, comparer ?? EqualityComparer<TKey>.Default);
}


static IEnumerable<Result> LeftJoinImpl<TOuter, TInner, TKey, Result>(
IEnumerable<TOuter> outer, IEnumerable<TInner> inner
, Func<TOuter, TKey> outerKeySelector, Func<TInner, TKey> innerKeySelector
, Func<TOuter, TInner, Result> resultSelector, IEqualityComparer<TKey> comparer)
{
var innerLookup = inner.ToLookup(innerKeySelector, comparer);


foreach (var outerElment in outer)
{
var outerKey = outerKeySelector(outerElment);
var innerElements = innerLookup[outerKey];


if (innerElements.Any())
foreach (var innerElement in innerElements)
yield return resultSelector(outerElment, innerElement);
else
yield return resultSelector(outerElment, default(TInner));
}
}

然后，resultselector必须处理空元素。外汇。

   static void Main(string[] args)
{
var inner = new[] { Tuple.Create(1, "1"), Tuple.Create(2, "2"), Tuple.Create(3, "3") };
var outer = new[] { Tuple.Create(1, "11"), Tuple.Create(2, "22") };


var res = outer.LeftJoin(inner, item => item.Item1, item => item.Item1, (it1, it2) =>
new { Key = it1.Item1, V1 = it1.Item2, V2 = it2 != null ? it2.Item2 : default(string) });


foreach (var item in res)
Console.WriteLine(string.Format("{0}, {1}, {2}", item.Key, item.V1, item.V2));
}

小开

如果使用数据库驱动的LINQ提供程序，则可以这样编写可读性明显更好的左外连接:

from c in categories
from p in products.Where(c == p.Category).DefaultIfEmpty()

如果您省略了DefaultIfEmpty()，您将有一个内连接。

拿一个公认的答案来说:

  from c in categories
join p in products on c equals p.Category into ps
from p in ps.DefaultIfEmpty()

这个语法非常混乱，当你想要左连接MULTIPLE表时，它是如何工作的并不清楚。

< p > # EYZ0
应该注意的是，from alias in Repo.whatever.Where(condition).DefaultIfEmpty()与外部应用/左连接-横向相同，任何(像样的)数据库优化器都完全能够将其转换为左连接，只要您不引入逐行值(即实际的外部应用)。不要在Linq-2-Objects中这样做(因为当你使用Linq-to-Objects时没有DB-optimizer)

详细的例子

var query2 = (
from users in Repo.T_User
from mappings in Repo.T_User_Group
.Where(mapping => mapping.USRGRP_USR == users.USR_ID)
.DefaultIfEmpty() // <== makes join left join
from groups in Repo.T_Group
.Where(gruppe => gruppe.GRP_ID == mappings.USRGRP_GRP)
.DefaultIfEmpty() // <== makes join left join


// where users.USR_Name.Contains(keyword)
// || mappings.USRGRP_USR.Equals(666)
// || mappings.USRGRP_USR == 666
// || groups.Name.Contains(keyword)


select new
{
UserId = users.USR_ID
,UserName = users.USR_User
,UserGroupId = groups.ID
,GroupName = groups.Name
}


);




var xy = (query2).ToList();

当与LINQ 2 SQL一起使用时，它将很好地翻译为以下非常清晰的SQL查询:

SELECT
users.USR_ID AS UserId
,users.USR_User AS UserName
,groups.ID AS UserGroupId
,groups.Name AS GroupName
FROM T_User AS users


LEFT JOIN T_User_Group AS mappings
ON mappings.USRGRP_USR = users.USR_ID


LEFT JOIN T_Group AS groups
ON groups.GRP_ID == mappings.USRGRP_GRP

编辑:

参见also; # EYZ0“; 对于一个更复杂的例子

此外，如果你在LINQ -2- objects(而不是LINQ -2-SQL)中这样做，你应该用老式的方式来做(因为LINQ to SQL正确地将此转换为连接操作，但在对象上，这种方法强制完全扫描，并且不利用索引搜索，无论如何…):

    var query2 = (
from users in Repo.T_Benutzer
join mappings in Repo.T_Benutzer_Benutzergruppen on mappings.BEBG_BE equals users.BE_ID into tmpMapp
join groups in Repo.T_Benutzergruppen on groups.ID equals mappings.BEBG_BG into tmpGroups
from mappings in tmpMapp.DefaultIfEmpty()
from groups in tmpGroups.DefaultIfEmpty()
select new
{
UserId = users.BE_ID
,UserName = users.BE_User
,UserGroupId = mappings.BEBG_BG
,GroupName = groups.Name
}


);

小开

这是一个与LINQ语法比较的SQL语法，用于内连接和左外连接。左外连接:

http://www.ozkary.com/2011/07/linq-to-entity-inner-and-left-joins.html

下面的示例在产品和类别之间进行组连接。这本质上是左连接。即使类别表为空，into表达式也会返回数据。要访问类别表的属性，现在必须通过在catList.DefaultIfEmpty()语句中添加from cl从可枚举结果中进行选择。

小开

下面是一个例子，如果你需要连接2个以上的表:

from d in context.dc_tpatient_bookingd
join bookingm in context.dc_tpatient_bookingm
on d.bookingid equals bookingm.bookingid into bookingmGroup
from m in bookingmGroup.DefaultIfEmpty()
join patient in dc_tpatient
on m.prid equals patient.prid into patientGroup
from p in patientGroup.DefaultIfEmpty()

裁判:# EYZ0

小开

有三个表:persons, schools和persons_schools，它将人与他们所学习的学校联系起来。表persons_schools中没有对id=6的person的引用。但是id=6的人显示在左连接的结果网格中。

List<Person> persons = new List<Person>
{
new Person { id = 1, name = "Alex", phone = "4235234" },
new Person { id = 2, name = "Bob", phone = "0014352" },
new Person { id = 3, name = "Sam", phone = "1345" },
new Person { id = 4, name = "Den", phone = "3453452" },
new Person { id = 5, name = "Alen", phone = "0353012" },
new Person { id = 6, name = "Simon", phone = "0353012" }
};


List<School> schools = new List<School>
{
new School { id = 1, name = "Saint. John's school"},
new School { id = 2, name = "Public School 200"},
new School { id = 3, name = "Public School 203"}
};


List<PersonSchool> persons_schools = new List<PersonSchool>
{
new PersonSchool{id_person = 1, id_school = 1},
new PersonSchool{id_person = 2, id_school = 2},
new PersonSchool{id_person = 3, id_school = 3},
new PersonSchool{id_person = 4, id_school = 1},
new PersonSchool{id_person = 5, id_school = 2}
//a relation to the person with id=6 is absent
};


var query = from person in persons
join person_school in persons_schools on person.id equals person_school.id_person
into persons_schools_joined
from person_school_joined in persons_schools_joined.DefaultIfEmpty()
from school in schools.Where(var_school => person_school_joined == null ? false : var_school.id == person_school_joined.id_school).DefaultIfEmpty()
select new { Person = person.name, School = school == null ? String.Empty : school.name };


foreach (var elem in query)
{
System.Console.WriteLine("{0},{1}", elem.Person, elem.School);
}

小开

现在作为一个扩展方法:

public static class LinqExt
{
public static IEnumerable<TResult> LeftOuterJoin<TLeft, TRight, TKey, TResult>(this IEnumerable<TLeft> left, IEnumerable<TRight> right, Func<TLeft, TKey> leftKey, Func<TRight, TKey> rightKey,
Func<TLeft, TRight, TResult> result)
{
return left.GroupJoin(right, leftKey, rightKey, (l, r) => new { l, r })
.SelectMany(
o => o.r.DefaultIfEmpty(),
(l, r) => new { lft= l.l, rght = r })
.Select(o => result.Invoke(o.lft, o.rght));
}
}

像平常使用join一样使用:

var contents = list.LeftOuterJoin(list2,
l => l.country,
r => r.name,
(l, r) => new { count = l.Count(), l.country, l.reason, r.people })

希望这能为您节省一些时间。

小开

看看这个例子

class Person
{
public int ID { get; set; }
public string FirstName { get; set; }
public string LastName { get; set; }
public string Phone { get; set; }
}


class Pet
{
public string Name { get; set; }
public Person Owner { get; set; }
}


public static void LeftOuterJoinExample()
{
Person magnus = new Person {ID = 1, FirstName = "Magnus", LastName = "Hedlund"};
Person terry = new Person {ID = 2, FirstName = "Terry", LastName = "Adams"};
Person charlotte = new Person {ID = 3, FirstName = "Charlotte", LastName = "Weiss"};
Person arlene = new Person {ID = 4, FirstName = "Arlene", LastName = "Huff"};


Pet barley = new Pet {Name = "Barley", Owner = terry};
Pet boots = new Pet {Name = "Boots", Owner = terry};
Pet whiskers = new Pet {Name = "Whiskers", Owner = charlotte};
Pet bluemoon = new Pet {Name = "Blue Moon", Owner = terry};
Pet daisy = new Pet {Name = "Daisy", Owner = magnus};


// Create two lists.
List<Person> people = new List<Person> {magnus, terry, charlotte, arlene};
List<Pet> pets = new List<Pet> {barley, boots, whiskers, bluemoon, daisy};


var query = from person in people
where person.ID == 4
join pet in pets on person equals pet.Owner  into personpets
from petOrNull in personpets.DefaultIfEmpty()
select new { Person=person, Pet = petOrNull};






foreach (var v in query )
{
Console.WriteLine("{0,-15}{1}", v.Person.FirstName + ":", (v.Pet == null ? "Does not Exist" : v.Pet.Name));
}
}


// This code produces the following output:
//
// Magnus:        Daisy
// Terry:         Barley
// Terry:         Boots
// Terry:         Blue Moon
// Charlotte:     Whiskers
// Arlene:

现在你可以使用include elements from the left，即使元素has no matches in the right，在我们的例子中，我们检索了Arlene，即使他在右边没有匹配

这是参考资料

如何:执行左外连接(c#编程指南)

小开

如果需要连接和筛选某些东西，可以在连接之外完成。可以在创建集合之后进行筛选。

在这种情况下，如果我在连接条件中这样做，我减少了返回的行。

三元条件使用(= n == null ? "__" : n.MonDayNote,)

如果对象是null(因此不匹配)，则返回?之后的内容。__，在这种情况下。

否则，返回:， n.MonDayNote之后的内容。

感谢其他贡献者，这是我开始自己的问题。

        var schedLocations = (from f in db.RAMS_REVENUE_LOCATIONS
join n in db.RAMS_LOCATION_PLANNED_MANNING on f.revenueCenterID equals


n.revenueCenterID into lm


from n in lm.DefaultIfEmpty()


join r in db.RAMS_LOCATION_SCHED_NOTE on f.revenueCenterID equals r.revenueCenterID
into locnotes


from r in locnotes.DefaultIfEmpty()
where f.LocID == nLocID && f.In_Use == true && f.revenueCenterID > 1000


orderby f.Areano ascending, f.Locname ascending
select new
{
Facname = f.Locname,
f.Areano,
f.revenueCenterID,
f.Locabbrev,


//  MonNote = n == null ? "__" : n.MonDayNote,
MonNote = n == null ? "__" : n.MonDayNote,
TueNote = n == null ? "__" : n.TueDayNote,
WedNote = n == null ? "__" : n.WedDayNote,
ThuNote = n == null ? "__" : n.ThuDayNote,


FriNote = n == null ? "__" : n.FriDayNote,
SatNote = n == null ? "__" : n.SatDayNote,
SunNote = n == null ? "__" : n.SunDayNote,
MonEmpNbr = n == null ? 0 : n.MonEmpNbr,
TueEmpNbr = n == null ? 0 : n.TueEmpNbr,
WedEmpNbr = n == null ? 0 : n.WedEmpNbr,
ThuEmpNbr = n == null ? 0 : n.ThuEmpNbr,
FriEmpNbr = n == null ? 0 : n.FriEmpNbr,
SatEmpNbr = n == null ? 0 : n.SatEmpNbr,
SunEmpNbr = n == null ? 0 : n.SunEmpNbr,
SchedMondayDate = n == null ? dMon : n.MondaySchedDate,
LocNotes = r == null ? "Notes: N/A" : r.LocationNote


}).ToList();
Func<int, string> LambdaManning = (x) => { return x == 0 ? "" : "Manning:" + x.ToString(); };
DataTable dt_ScheduleMaster = PsuedoSchedule.Tables["ScheduleMasterWithNotes"];
var schedLocations2 = schedLocations.Where(x => x.SchedMondayDate == dMon);

小开

(from a in db.Assignments
join b in db.Deliveryboys on a.AssignTo equals b.EmployeeId


//from d in eGroup.DefaultIfEmpty()
join  c in  db.Deliveryboys on a.DeliverTo equals c.EmployeeId into eGroup2
from e in eGroup2.DefaultIfEmpty()
where (a.Collected == false)
select new
{
OrderId = a.OrderId,
DeliveryBoyID = a.AssignTo,
AssignedBoyName = b.Name,
Assigndate = a.Assigndate,
Collected = a.Collected,
CollectedDate = a.CollectedDate,
CollectionBagNo = a.CollectionBagNo,
DeliverTo = e == null ? "Null" : e.Name,
DeliverDate = a.DeliverDate,
DeliverBagNo = a.DeliverBagNo,
Delivered = a.Delivered


});

小开

class Program
{
List<Employee> listOfEmp = new List<Employee>();
List<Department> listOfDepart = new List<Department>();


public Program()
{
listOfDepart = new List<Department>(){
new Department { Id = 1, DeptName = "DEV" },
new Department { Id = 2, DeptName = "QA" },
new Department { Id = 3, DeptName = "BUILD" },
new Department { Id = 4, DeptName = "SIT" }
};




listOfEmp = new List<Employee>(){
new Employee { Empid = 1, Name = "Manikandan",DepartmentId=1 },
new Employee { Empid = 2, Name = "Manoj" ,DepartmentId=1},
new Employee { Empid = 3, Name = "Yokesh" ,DepartmentId=0},
new Employee { Empid = 3, Name = "Purusotham",DepartmentId=0}
};


}
static void Main(string[] args)
{
Program ob = new Program();
ob.LeftJoin();
Console.ReadLine();
}


private void LeftJoin()
{
listOfEmp.GroupJoin(listOfDepart.DefaultIfEmpty(), x => x.DepartmentId, y => y.Id, (x, y) => new { EmpId = x.Empid, EmpName = x.Name, Dpt = y.FirstOrDefault() != null ? y.FirstOrDefault().DeptName : null }).ToList().ForEach
(z =>
{
Console.WriteLine("Empid:{0} EmpName:{1} Dept:{2}", z.EmpId, z.EmpName, z.Dpt);
});
}
}


class Employee
{
public int Empid { get; set; }
public string Name { get; set; }
public int DepartmentId { get; set; }
}


class Department
{
public int Id { get; set; }
public string DeptName { get; set; }
}

OUTPUT

小开

这是一般形式(已经在其他答案中提供了)

var c =
from a in alpha
join b in beta on b.field1 equals a.field1 into b_temp
from b_value in b_temp.DefaultIfEmpty()
select new { Alpha = a, Beta = b_value };

然而，这里有一个解释，我希望能澄清这实际上是什么意思!

join b in beta on b.field1 equals a.field1 into b_temp

本质上创建了一个单独的结果集b_temp，其中有效地包含了右边条目的空“rows”('b'中的条目)。

然后是下一行:

from b_value in b_temp.DefaultIfEmpty()

．．遍历该结果集，为右侧的'row'设置默认空值，并将右侧的行连接的结果设置为'b_value'的值(即，如果有匹配的记录，则为右侧的值，如果没有则为'null')。

现在，如果右边是一个单独的LINQ查询的结果，它将由匿名类型组成，它只能是'something'或'null'。如果它是一个可枚举的对象(例如，一个List -其中MyObjectB是一个有2个字段的类)，那么它可以具体说明它的属性使用什么默认的“null”值:

var c =
from a in alpha
join b in beta on b.field1 equals a.field1 into b_temp
from b_value in b_temp.DefaultIfEmpty( new MyObjectB { Field1 = String.Empty, Field2 = (DateTime?) null })
select new { Alpha = a, Beta_field1 = b_value.Field1, Beta_field2 = b_value.Field2 };

这确保了'b'本身不是空的(但它的属性可以是空的，使用您指定的默认空值)，这允许您检查b_value的属性，而不会得到b_value的空引用异常。注意，对于可空的DateTime， (DateTime?)类型，即。'nullable DateTime'必须在'DefaultIfEmpty'的规范中指定为null的'Type'(这也适用于'原生'不为空的类型，例如double, float)。

您可以通过简单地链接上述语法来执行多个左外连接。

小开

扩展方法，类似于使用join语法的左连接

public static class LinQExtensions
{
public static IEnumerable<TResult> LeftJoin<TOuter, TInner, TKey, TResult>(
this IEnumerable<TOuter> outer, IEnumerable<TInner> inner,
Func<TOuter, TKey> outerKeySelector,
Func<TInner, TKey> innerKeySelector,
Func<TOuter, TInner, TResult> resultSelector)
{
return outer.GroupJoin(
inner,
outerKeySelector,
innerKeySelector,
(outerElement, innerElements) => resultSelector(outerElement, innerElements.FirstOrDefault()));
}
}

我刚刚在。net内核中编写了它，它看起来像预期的那样工作。

小测试:

        var Ids = new List<int> { 1, 2, 3, 4};
var items = new List<Tuple<int, string>>
{
new Tuple<int, string>(1,"a"),
new Tuple<int, string>(2,"b"),
new Tuple<int, string>(4,"d"),
new Tuple<int, string>(5,"e"),
};


var result = Ids.LeftJoin(
items,
id => id,
item => item.Item1,
(id, item) => item ?? new Tuple<int, string>(id, "not found"));


result.ToList()
Count = 4
[0]: {(1, a)}
[1]: {(2, b)}
[2]: {(3, not found)}
[3]: {(4, d)}

小开

我想补充的是，如果您获得MoreLinq扩展，现在支持同质和异构左连接

http://morelinq.github.io/2.8/ref/api/html/Overload_MoreLinq_MoreEnumerable_LeftJoin.htm

例子:

//Pretend a ClientCompany object and an Employee object both have a ClientCompanyID key on them


return DataContext.ClientCompany
.LeftJoin(DataContext.Employees,                         //Table being joined
company => company.ClientCompanyID,                  //First key
employee => employee.ClientCompanyID,                //Second Key
company => new {company, employee = (Employee)null}, //Result selector when there isn't a match
(company, employee) => new { company, employee });   //Result selector when there is a match

编辑:

回想起来，这可能会起作用，但它将IQueryable转换为IEnumerable，因为morelinq不会将查询转换为SQL。

您可以使用如下所述的GroupJoin: https://stackoverflow.com/a/24273804/4251433

这将确保它仍然是一个IQueryable，以防您以后需要对它进行进一步的逻辑操作。

小开

在linq c#中执行左外连接 //执行左外连接

class Person
{
public string FirstName { get; set; }
public string LastName { get; set; }
}


class Child
{
public string Name { get; set; }
public Person Owner { get; set; }
}
public class JoinTest
{
public static void LeftOuterJoinExample()
{
Person magnus = new Person { FirstName = "Magnus", LastName = "Hedlund" };
Person terry = new Person { FirstName = "Terry", LastName = "Adams" };
Person charlotte = new Person { FirstName = "Charlotte", LastName = "Weiss" };
Person arlene = new Person { FirstName = "Arlene", LastName = "Huff" };


Child barley = new Child { Name = "Barley", Owner = terry };
Child boots = new Child { Name = "Boots", Owner = terry };
Child whiskers = new Child { Name = "Whiskers", Owner = charlotte };
Child bluemoon = new Child { Name = "Blue Moon", Owner = terry };
Child daisy = new Child { Name = "Daisy", Owner = magnus };


// Create two lists.
List<Person> people = new List<Person> { magnus, terry, charlotte, arlene };
List<Child> childs = new List<Child> { barley, boots, whiskers, bluemoon, daisy };


var query = from person in people
join child in childs
on person equals child.Owner into gj
from subpet in gj.DefaultIfEmpty()
select new
{
person.FirstName,
ChildName = subpet!=null? subpet.Name:"No Child"
};
// PetName = subpet?.Name ?? String.Empty };


foreach (var v in query)
{
Console.WriteLine($"{v.FirstName + ":",-25}{v.ChildName}");
}
}


// This code produces the following output:
//
// Magnus:        Daisy
// Terry:         Barley
// Terry:         Boots
// Terry:         Blue Moon
// Charlotte:     Whiskers
// Arlene:        No Child

< a href = " https://dotnetwithhamid.blogspot。In /" rel="nofollow noreferrer">https://dotnetwithhamid.blogspot.in/

小开

下面是使用方法语法的一个相当容易理解的版本:

IEnumerable<JoinPair> outerLeft =
lefts.SelectMany(l =>
rights.Where(r => l.Key == r.Key)
.DefaultIfEmpty(new Item())
.Select(r => new JoinPair { LeftId = l.Id, RightId = r.Id }));

小开

简单的方法是使用Let关键字。这对我很有用。

from AItem in Db.A
Let BItem = Db.B.Where(x => x.id == AItem.id ).FirstOrDefault()
Where SomeCondition
Select new YourViewModel
{
X1 = AItem.a,
X2 = AItem.b,
X3 = BItem.c
}

这是一个模拟左连接。如果B表中的每一项与A表中的每一项都不匹配，BItem返回null

小开

根据我对类似问题的回答，在这里:

Linq到SQL左外连接使用Lambda语法和连接2列(复合连接键)

获得代码，或克隆我的github回购，并播放!

查询:

        var petOwners =
from person in People
join pet in Pets
on new
{
person.Id,
person.Age,
}
equals new
{
pet.Id,
Age = pet.Age * 2, // owner is twice age of pet
}
into pets
from pet in pets.DefaultIfEmpty()
select new PetOwner
{
Person = person,
Pet = pet,
};

λ:

        var petOwners = People.GroupJoin(
Pets,
person => new { person.Id, person.Age },
pet => new { pet.Id, Age = pet.Age * 2 },
(person, pet) => new
{
Person = person,
Pets = pet,
}).SelectMany(
pet => pet.Pets.DefaultIfEmpty(),
(people, pet) => new
{
people.Person,
Pet = pet,
});

小开

概述:在这个代码片段中，我演示了如何按ID分组，其中Table1和Table2具有一对多关系。我集中在 Id, Field1和Field2。如果需要第三次查找表，并且需要左连接关系，那么子查询是有用的。我展示了一个左连接分组和一个子查询linq。

class MyView
{
public integer Id {get,set};
public String Field1  {get;set;}
public String Field2 {get;set;}
public String SubQueryName {get;set;}
}


IList<MyView> list = await (from ci in _dbContext.Table1
join cii in _dbContext.Table2
on ci.Id equals cii.Id


where ci.Field1 == criterion
group new
{
ci.Id
} by new { ci.Id, cii.Field1, ci.Field2}


into pg
select new MyView
{
Id = pg.Key.Id,
Field1 = pg.Key.Field1,
Field2 = pg.Key.Field2,
SubQueryName=
(from chv in _dbContext.Table3 where chv.Id==pg.Key.Id select chv.Field1).FirstOrDefault()
}).ToListAsync<MyView>();




Compared to using a Left Join and Group new


IList<MyView> list = await (from ci in _dbContext.Table1
join cii in _dbContext.Table2
on ci.Id equals cii.Id


join chv in _dbContext.Table3
on cii.Id equals chv.Id into lf_chv
from chv in lf_chv.DefaultIfEmpty()


where ci.Field1 == criterion
group new
{
ci.Id
} by new { ci.Id, cii.Field1, ci.Field2, chv.FieldValue}


into pg
select new MyView
{
Id = pg.Key.Id,
Field1 = pg.Key.Field1,
Field2 = pg.Key.Field2,
SubQueryName=pg.Key.FieldValue
}).ToListAsync<MyView>();

小开

下面是一个版本的扩展方法解决方案，使用IQueryable代替IEnumerable

public class OuterJoinResult<TLeft, TRight>
{
public TLeft LeftValue { get; set; }
public TRight RightValue { get; set; }
}


public static IQueryable<TResult> LeftOuterJoin<TLeft, TRight, TKey, TResult>(this IQueryable<TLeft> left, IQueryable<TRight> right, Expression<Func<TLeft, TKey>> leftKey, Expression<Func<TRight, TKey>> rightKey, Expression<Func<OuterJoinResult<TLeft, TRight>, TResult>> result)
{
return left.GroupJoin(right, leftKey, rightKey, (l, r) => new { l, r })
.SelectMany(o => o.r.DefaultIfEmpty(), (l, r) => new OuterJoinResult<TLeft, TRight> { LeftValue = l.l, RightValue = r })
.Select(result);
}

小开

这是我使用的LeftJoin实现。注意，resultSelector表达式接受2个参数:来自连接两侧的一个实例。在我所见过的大多数其他实现中，结果选择器只接受一个参数，即“join model”。具有左/右或外/内属性。我更喜欢这个实现，因为它与内置的Join方法具有相同的方法签名。它也适用于IQueryables和EF。

 var results = DbContext.Categories
.LeftJoin(
DbContext.Products, c => c.Id, p => p.CategoryId,
(c, p) => new { Category = c, ProductName = p == null ? "(No Products)" : p.ProductName })
.ToList();

public static class QueryableExtensions
{
public static IQueryable<TResult> LeftJoin<TOuter, TInner, TKey, TResult>(
this IQueryable<TOuter> outer,
IEnumerable<TInner> inner, Expression<Func<TOuter, TKey>> outerKeySelector,
Expression<Func<TInner, TKey>> innerKeySelector,
Expression<Func<TOuter, TInner, TResult>> resultSelector)
{
var query = outer
.GroupJoin(inner, outerKeySelector, innerKeySelector, (o, i) => new { o, i })
.SelectMany(o => o.i.DefaultIfEmpty(), (x, i) => new { x.o, i });
return ApplySelector(query, x => x.o, x => x.i, resultSelector);
}


private static IQueryable<TResult> ApplySelector<TSource, TOuter, TInner, TResult>(
IQueryable<TSource> source,
Expression<Func<TSource, TOuter>> outerProperty,
Expression<Func<TSource, TInner>> innerProperty,
Expression<Func<TOuter, TInner, TResult>> resultSelector)
{
var p = Expression.Parameter(typeof(TSource), $"param_{Guid.NewGuid()}".Replace("-", string.Empty));
Expression body = resultSelector?.Body
.ReplaceParameter(resultSelector.Parameters[0], outerProperty.Body.ReplaceParameter(outerProperty.Parameters[0], p))
.ReplaceParameter(resultSelector.Parameters[1], innerProperty.Body.ReplaceParameter(innerProperty.Parameters[0], p));
var selector = Expression.Lambda<Func<TSource, TResult>>(body, p);
return source.Select(selector);
}
}


public static class ExpressionExtensions
{
public static Expression ReplaceParameter(this Expression source, ParameterExpression toReplace, Expression newExpression)
=> new ReplaceParameterExpressionVisitor(toReplace, newExpression).Visit(source);
}


public class ReplaceParameterExpressionVisitor : ExpressionVisitor
{
public ReplaceParameterExpressionVisitor(ParameterExpression toReplace, Expression replacement)
{
this.ToReplace = toReplace;
this.Replacement = replacement;
}


public ParameterExpression ToReplace { get; }
public Expression Replacement { get; }
protected override Expression VisitParameter(ParameterExpression node)
=> (node == ToReplace) ? Replacement : base.VisitParameter(node);
}

小开

这是我用过的最漂亮的解决方案，试试吧!😉

(from c in categories
let product = products.Where(d=> d.Category == c.Category).FirstOrDefault()
select new { Category = c, ProductName = p == null ? "(No products)" : product.ProductName };