C + + 将字符串转换为十六进制,反之亦然

在 C + + 中,将字符串转换为十六进制或者将十六进制转换为十六进制的最佳方法是什么?

例如:

  • "Hello World"到十六进制格式的字符串: 48656C6C6F20576F726C64
  • 从十六进制到字符串: "Hello World"
256004 次浏览
string ToHex(const string& s, bool upper_case /* = true */)
{
ostringstream ret;


for (string::size_type i = 0; i < s.length(); ++i)
ret << std::hex << std::setfill('0') << std::setw(2) << (upper_case ? std::uppercase : std::nouppercase) << (int)s[i];


return ret.str();
}


int FromHex(const string &s) { return strtoul(s.c_str(), NULL, 16); }

使用标准库的最简单示例。

#include <iostream>
using namespace std;


int main()
{
char c = 'n';
cout << "HEX " << hex << (int)c << endl;  // output in hexadecimal
cout << "ASC" << c << endl; // output in ascii
return 0;
}

为了检查输出,密码本返回: 6e

一个在线 十六进制转换工具也能产生6e,所以它是有效的。

你也可以这样做:

template<class T> std::string toHexString(const T& value, int width) {
std::ostringstream oss;
oss << hex;
if (width > 0) {
oss << setw(width) << setfill('0');
}
oss << value;
return oss.str();
}

类似“ Hello World”的字符串转换为十六进制格式: 48656C6C6F20576F726C64。

给你:

#include <string>


std::string string_to_hex(const std::string& input)
{
static const char hex_digits[] = "0123456789ABCDEF";


std::string output;
output.reserve(input.length() * 2);
for (unsigned char c : input)
{
output.push_back(hex_digits[c >> 4]);
output.push_back(hex_digits[c & 15]);
}
return output;
}


#include <stdexcept>


int hex_value(unsigned char hex_digit)
{
static const signed char hex_values[256] = {
-1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1,
-1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1,
-1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1,
0,  1,  2,  3,  4,  5,  6,  7,  8,  9, -1, -1, -1, -1, -1, -1,
-1, 10, 11, 12, 13, 14, 15, -1, -1, -1, -1, -1, -1, -1, -1, -1,
-1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1,
-1, 10, 11, 12, 13, 14, 15, -1, -1, -1, -1, -1, -1, -1, -1, -1,
-1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1,
-1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1,
-1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1,
-1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1,
-1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1,
-1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1,
-1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1,
-1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1,
-1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1,
};
int value = hex_values[hex_digit];
if (value == -1) throw std::invalid_argument("invalid hex digit");
return value;
}


std::string hex_to_string(const std::string& input)
{
const auto len = input.length();
if (len & 1) throw std::invalid_argument("odd length");


std::string output;
output.reserve(len / 2);
for (auto it = input.begin(); it != input.end(); )
{
int hi = hex_value(*it++);
int lo = hex_value(*it++);
output.push_back(hi << 4 | lo);
}
return output;
}

(这里假设一个 char 有8位,所以它不是非常可移植的,但是你可以从这里开始。)

你可以试试这个,很有效。

#include <algorithm>
#include <sstream>
#include <iostream>
#include <iterator>
#include <iomanip>


namespace {
const std::string test="hello world";
}


int main() {
std::ostringstream result;
result << std::setw(2) << std::setfill('0') << std::hex << std::uppercase;
std::copy(test.begin(), test.end(), std::ostream_iterator<unsigned int>(result, " "));
std::cout << test << ":" << result.str() << std::endl;
}

为什么没有人使用 sprintf?

#include <string>
#include <stdio.h>


static const std::string str = "hello world!";


int main()
{
//copy the data from the string to a char array
char *strarr = new char[str.size()+1];
strarr[str.size()+1] = 0; //set the null terminator
memcpy(strarr, str.c_str(),str.size()); //memory copy to the char array


printf(strarr);
printf("\n\nHEX: ");


//now print the data
for(int i = 0; i < str.size()+1; i++)
{
char x = strarr[i];
sprintf("%x ", reinterpret_cast<const char*>(x));
}


//DO NOT FORGET TO DELETE
delete(strarr);


return 0;
}

这个稍微快一点:

static const char* s_hexTable[256] =
{
"00", "01", "02", "03", "04", "05", "06", "07", "08", "09", "0a", "0b", "0c", "0d", "0e", "0f", "10", "11",
"12", "13", "14", "15", "16", "17", "18", "19", "1a", "1b", "1c", "1d", "1e", "1f", "20", "21", "22", "23",
"24", "25", "26", "27", "28", "29", "2a", "2b", "2c", "2d", "2e", "2f", "30", "31", "32", "33", "34", "35",
"36", "37", "38", "39", "3a", "3b", "3c", "3d", "3e", "3f", "40", "41", "42", "43", "44", "45", "46", "47",
"48", "49", "4a", "4b", "4c", "4d", "4e", "4f", "50", "51", "52", "53", "54", "55", "56", "57", "58", "59",
"5a", "5b", "5c", "5d", "5e", "5f", "60", "61", "62", "63", "64", "65", "66", "67", "68", "69", "6a", "6b",
"6c", "6d", "6e", "6f", "70", "71", "72", "73", "74", "75", "76", "77", "78", "79", "7a", "7b", "7c", "7d",
"7e", "7f", "80", "81", "82", "83", "84", "85", "86", "87", "88", "89", "8a", "8b", "8c", "8d", "8e", "8f",
"90", "91", "92", "93", "94", "95", "96", "97", "98", "99", "9a", "9b", "9c", "9d", "9e", "9f", "a0", "a1",
"a2", "a3", "a4", "a5", "a6", "a7", "a8", "a9", "aa", "ab", "ac", "ad", "ae", "af", "b0", "b1", "b2", "b3",
"b4", "b5", "b6", "b7", "b8", "b9", "ba", "bb", "bc", "bd", "be", "bf", "c0", "c1", "c2", "c3", "c4", "c5",
"c6", "c7", "c8", "c9", "ca", "cb", "cc", "cd", "ce", "cf", "d0", "d1", "d2", "d3", "d4", "d5", "d6", "d7",
"d8", "d9", "da", "db", "dc", "dd", "de", "df", "e0", "e1", "e2", "e3", "e4", "e5", "e6", "e7", "e8", "e9",
"ea", "eb", "ec", "ed", "ee", "ef", "f0", "f1", "f2", "f3", "f4", "f5", "f6", "f7", "f8", "f9", "fa", "fb",
"fc", "fd", "fe", "ff"
};


// Convert binary data sequence [beginIt, endIt) to hexadecimal string
void dataToHexString(const uint8_t*const beginIt, const uint8_t*const endIt, string& str)
{
str.clear();
str.reserve((endIt - beginIt) * 2);
for(const uint8_t* it(beginIt); it != endIt; ++it)
{
str += s_hexTable[*it];
}
}

使用查找表之类的方法是可行的,但是有点过头了,这里有一些非常简单的方法可以把字符串变成十六进制,把十六进制变回字符串:

#include <stdexcept>
#include <sstream>
#include <iomanip>
#include <string>
#include <cstdint>


std::string string_to_hex(const std::string& in) {
std::stringstream ss;


ss << std::hex << std::setfill('0');
for (size_t i = 0; in.length() > i; ++i) {
ss << std::setw(2) << static_cast<unsigned int>(static_cast<unsigned char>(in[i]));
}


return ss.str();
}


std::string hex_to_string(const std::string& in) {
std::string output;


if ((in.length() % 2) != 0) {
throw std::runtime_error("String is not valid length ...");
}


size_t cnt = in.length() / 2;


for (size_t i = 0; cnt > i; ++i) {
uint32_t s = 0;
std::stringstream ss;
ss << std::hex << in.substr(i * 2, 2);
ss >> s;


output.push_back(static_cast<unsigned char>(s));
}


return output;
}

这将把“ Hello World”转换为“48656c6c6f20576f726c64”,并将这个十六进制值存储在 str1中,还将把“48656c6c6f20576f726c64”转换为“ Hello World”。

#include <iostream>
#include<sstream>


using namespace std;
int hexCharToInt(char);
string hexToString(string);
int main()
{
std::string str;
std::stringstream str1;


str="Hello World";
for(int i=0;i<str.length();i++){
str1 << std::hex << (int)str.at(i);
}
std::cout << str1.str() <<"\n";
string test = "48656c6c6f20576f726c64";
std::cout << hexToString(test) <<"\n";
return 0;
}
string hexToString(string str){
std::stringstream HexString;
for(int i=0;i<str.length();i++){
char a = str.at(i++);
char b = str.at(i);
int x = hexCharToInt(a);
int y = hexCharToInt(b);
HexString << (char)((16*x)+y);
}
return HexString.str();
}


int hexCharToInt(char a){
if(a>='0' && a<='9')
return(a-48);
else if(a>='A' && a<='Z')
return(a-55);
else
return(a-87);
}

这将把 Hello World 转换为48656c6c6f20576f726c64和 打印 it。

#include <iostream>
#include <cstring>


using namespace std;


int main()
{
char hello[20]="Hello World";


for(unsigned int i=0; i<strlen(hello); i++)
cout << hex << (int) hello[i];
return 0;
}

我认为有一个更简单、更优雅的解决方案。在某些情况下,上面提到的一些方法甚至可能抛出未处理的异常。这里有一个简单易用的代码(比如从不出错)和非常快的代码。试试看,比较一下速度和紧凑度的结果:

#include <string>


// Convert string of chars to its representative string of hex numbers
void stream2hex(const std::string str, std::string& hexstr, bool capital = false)
{
hexstr.resize(str.size() * 2);
const size_t a = capital ? 'A' - 1 : 'a' - 1;


for (size_t i = 0, c = str[0] & 0xFF; i < hexstr.size(); c = str[i / 2] & 0xFF)
{
hexstr[i++] = c > 0x9F ? (c / 16 - 9) | a : c / 16 | '0';
hexstr[i++] = (c & 0xF) > 9 ? (c % 16 - 9) | a : c % 16 | '0';
}
}


// Convert string of hex numbers to its equivalent char-stream
void hex2stream(const std::string hexstr, std::string& str)
{
str.resize((hexstr.size() + 1) / 2);


for (size_t i = 0, j = 0; i < str.size(); i++, j++)
{
str[i] = (hexstr[j] & '@' ? hexstr[j] + 9 : hexstr[j]) << 4, j++;
str[i] |= (hexstr[j] & '@' ? hexstr[j] + 9 : hexstr[j]) & 0xF;
}
}

测试代码 :

#include <iostream>
int main()
{
std::string s = "Hello World!";
std::cout << "original string: " << s << '\n';
stream2hex(s, s);
std::cout << "hex format: " << s << '\n';
hex2stream(s, s);
std::cout << "original one: " << s << '\n';
}

结果就是:

original string: Hello World!
hex format: 48656C6C6F20576F726C6421
original one: Hello World!

在 C + + 17中还有 From _ chars。下面的函数接受一个十六进制字符串并返回一个 T 的向量:

#include <charconv>


template<typename T>
std::vector<T> hexstr_to_vec(const std::string& str, unsigned char chars_per_num = 2)
{
std::vector<T> out(str.size() / chars_per_num, 0);


T value;
for (std::size_t i = 0; i < str.size() / chars_per_num; i++) {
std::from_chars<T>(
str.data() + (i * chars_per_num),
str.data() + (i * chars_per_num) + chars_per_num,
value,
16
);
out[i] = value;
}


return out;
}

这里是另一个解决方案,很大程度上受到@fredoverflow 的启发。

/**
* Return hexadecimal representation of the input binary sequence
*/
std::string hexitize(const std::vector<char>& input, const char* const digits = "0123456789ABCDEF")
{
std::ostringstream output;


for (unsigned char gap = 0, beg = input[gap]; gap < input.length(); beg = input[++gap])
output << digits[beg >> 4] << digits[beg & 15];


return output.str();
}

长度是预期用法中所需的参数。

#include "boost/algorithm/hex.hpp"
std::string hexed = boost::algorithm::hex(std::string("input"));

Https://www.boost.org/doc/libs/1_78_0/boost/algorithm/hex.hpp