如何在 PowerShell 中将字符串转换为整数

我有一份目录列表，上面有数字。我必须找到最高的数字并将其递增1，然后创建一个具有该递增值的新目录。我能够对下面的数组进行排序，但是我不能递增最后一个元素，因为它是一个字符串。

如何将下面的数组元素转换为整数？

PS C:\Users\Suman\Desktop> $FileList


Name
----
11
2
1
329585 次浏览
小开

Once you have selected the highest value, which is "12" in my example, you can then declare it as integer and increment your value:

$FileList = "1", "2", "11"
$foldername = [int]$FileList[2] + 1
$foldername
小开
最佳答案

You can specify the type of a variable before it to force its type. It's called (dynamic) casting (more information is here):

$string = "1654"
$integer = [int]$string


$string + 1
# Outputs 16541


$integer + 1
# Outputs 1655

As an example, the following snippet adds, to each object in $fileList, an IntVal property with the integer value of the Name property, then sorts $fileList on this new property (the default is ascending), takes the last (highest IntVal) object's IntVal value, increments it and finally creates a folder named after it:

# For testing purposes
#$fileList = @([PSCustomObject]@{ Name = "11" }, [PSCustomObject]@{ Name = "2" }, [PSCustomObject]@{ Name = "1" })
# OR
#$fileList = New-Object -TypeName System.Collections.ArrayList
#$fileList.AddRange(@([PSCustomObject]@{ Name = "11" }, [PSCustomObject]@{ Name = "2" }, [PSCustomObject]@{ Name = "1" })) | Out-Null


$highest = $fileList |
Select-Object *, @{ n = "IntVal"; e = { [int]($_.Name) } } |
Sort-Object IntVal |
Select-Object -Last 1


$newName = $highest.IntVal + 1


New-Item $newName -ItemType Directory

Sort-Object IntVal is not needed so you can remove it if you prefer.

[int]::MaxValue = 2147483647 so you need to use the [long] type beyond this value ([long]::MaxValue = 9223372036854775807).

小开

Use:

$filelist = @(11, 1, 2)
$filelist | sort @{expression={$_[0]}} |
% {$newName = [string]([int]$($_[0]) + 1)}
New-Item $newName -ItemType Directory
小开

Use:

$filelist = @("11", "1", "2")
$filelist | sort @{expression={[int]$_}} | % {$newName = [string]([int]$_ + 1)}
New-Item $newName -ItemType Directory
小开

Example:

2.032 MB (2,131,022 bytes)

$u=($mbox.TotalItemSize.value).tostring()


$u=$u.trimend(" bytes)") #yields 2.032 MB (2,131,022


$u=$u.Split("(") #yields `$u[1]` as 2,131,022


$uI=[int]$u[1]

The result is 2131022 in integer form.

小开

If someone is looking for how this can be run from command line, as a single command, this is one way it can be done:

$FileList | ` # Writes array to pipeline
Select-Object -Last 1 | ` # Selects last item in array
ConvertFrom-String -TemplateContent "{[int]NameTmp:12}" | ` # Converts string to number and names the variable "NameTmp"
Add-Member -Name "Name" -Value { $this.NameTmp + 1 } -MemberType ScriptProperty -PassThru | ` # Increments variable "NameTmp" by one and adds new variable named "Name" to pipeline object
New-Item -Type Directory # Creates new directy in current folder. Takes directory name from pipelined "Name" variable

提交答案