最佳答案
我的回答是:
{
"id":"decaa828741611e58bcffeff819cdc9f",
"statement":"question statement",
"exercise_type":"QUESTION"
}
然后,基于 练习 _ 类型属性,我想实例化不同的对象实例(ExerciseResponseDTO
的子类) ,所以我在以下内容中创建了这个组合:
@JsonTypeInfo(
use = JsonTypeInfo.Id.NAME,
include = JsonTypeInfo.As.PROPERTY,
property = "exercise_type")
@JsonSubTypes({
@Type(value = ExerciseChoiceResponseDTO.class, name = "CHOICE"),
@Type(value = ExerciseQuestionResponseDTO.class, name = "QUESTION")})
public abstract class ExerciseMixIn
{}
public abstract class ExerciseResponseDTO {
private String id;
private String statement;
@JsonProperty(value = "exercise_type") private String exerciseType;
// Getters and setters
}
public class ExerciseQuestionResponseDTO
extends ExerciseResponseDTO {}
public class ExerciseChoiceResponseDTO
extends ExerciseResponseDTO {}
因此,我创建我的 ObjectMapper
如下所示
ObjectMapper mapper = new ObjectMapper();
mapper.addMixIn(ExerciseResponseDTO.class, ExerciseMixIn.class);
我的测试:
ExerciseResponseDTO exercise = mapper.readValue(serviceResponse, ExerciseResponseDTO.class)
Assert.assertTrue(exercise.getClass() == ExerciseQuestionResponseDTO.class); // OK
Assert.assertEquals("decaa828741611e58bcffeff819cdc9f" exercise.getId()); // OK
Assert.assertEquals("question statement", exercise.getStatement()); // OK
Assert.assertEquals("QUESTION", exercise.getExerciseType()); // FAIL. Expected: "QUESTION", actual: null
问题是,由于某种原因,在 @JsonTypeInfo
上作为属性使用的 练习 _ 类型属性被映射为 无效。
知道我该怎么解决吗?