How to find average from array in php?

Example:

$a[] = '56';
$a[] = '66';
$a[] = '';
$a[] = '58';
$a[] = '85';
$a[] = '';
$a[] = '';
$a[] = '76';
$a[] = '';
$a[] = '57';

Actually how to find average value from this array excluding empty. please help to resolve this problem.

114454 次浏览
echo array_sum($a) / count(array_filter($a));

first you need to remove empty values, otherwise average will be not accurate.

so

$a = array_filter($a);
$average = array_sum($a)/count($a);
echo $average;

DEMO

More concise and recommended way

$a = array_filter($a);
if(count($a)) {
echo $average = array_sum($a)/count($a);
}

See here

The accepted answer works for the example values, but in general simply using array_filter($a) is probably not a good idea, because it will filter out any actual zero values as well as zero length strings.

Even '0' evaluates to false, so you should use a filter that explicitly excludes zero length strings.

$a = array_filter($a, function($x) { return $x !== ''; });
$average = array_sum($a) / count($a);

As a late look, item controls should be done with numeric check. Otherwise something like this $array = [1.2, 0.33, [123]] will corrupt the calculation:

// Get numerics only.
$array = array_filter($array, fn($v) => is_numeric($v));


// Get numerics only where value > 0.
$array = array_filter($array, fn($v) => is_numeric($v) && ($v > 0));

Finally:

public static function average(array $array, bool $includeEmpties = true): float
{
$array = array_filter($array, fn($v) => (
$includeEmpties ? is_numeric($v) : is_numeric($v) && ($v > 0)
));


return array_sum($array) / count($array);
}

Credits: froq.util.Arrays