Flip / mirror an image horizontally + vertically with css

Im trying to flip an image to display it 4 ways : original (no changes), flipped horizontally, flipped vertically, flipped horizontally + verticly.

To do this Im doing the below, it works fine apart from the flip horizontally + vertically, any idea why this wouldnt be working ?

Ive made a JS fiddle of the issue here : https://jsfiddle.net/7vg2tn83/

.img-hor {
-moz-transform: scaleX(-1);
-o-transform: scaleX(-1);
-webkit-transform: scaleX(-1);
transform: scaleX(-1);
filter: FlipH;
-ms-filter: "FlipH";
}


.img-vert {
-moz-transform: scaleY(-1);
-o-transform: scaleY(-1);
-webkit-transform: scaleY(-1);
transform: scaleY(-1);
filter: FlipV;
-ms-filter: "FlipV";
}


.img-hor-vert {
-moz-transform: scaleX(-1);
-o-transform: scaleX(-1);
-webkit-transform: scaleX(-1);
transform: scaleX(-1);
filter: FlipH;
-ms-filter: "FlipH";


-moz-transform: scaleY(-1);
-o-transform: scaleY(-1);
-webkit-transform: scaleY(-1);
transform: scaleY(-1);
filter: FlipV;
-ms-filter: "FlipV";
}
139247 次浏览
小开

You can apply only a single transform rule for any selector. Use

.img-hor-vert {
-moz-transform: scaleX(-1) scaleY(-1);
-o-transform: scaleX(-1) scaleY(-1);
-webkit-transform: scaleX(-1) scaleY(-1);
transform: scaleX(-1) scaleY(-1);
filter: FlipH FlipV;
-ms-filter: "FlipH FlipV";
}

I am unsure which IE will accept multiple filters though.

小开
最佳答案

Try this:

.img-hor-vert {
-moz-transform: scale(-1, -1);
-o-transform: scale(-1, -1);
-webkit-transform: scale(-1, -1);
transform: scale(-1, -1);
}

Updated fiddle: https://jsfiddle.net/7vg2tn83/1/

It wasn't working before because you were overriding the transform in your css. So instead of doing both, it just did the last one. Sort of like if you did background-color twice, it would override the first one.

小开

You may do a transform: rotate(180deg); for the horizontal+vertical flip.

小开

To perform a reflection you can use, the transform CSS property along with the rotate() CSS function in this format:

transform: rotateX() rotateY();

The function rotateX() will rotate an element along the x-axis and the function rotateY() will rotate an element along the y-axis. I find my approach intuitive in that one can visualize the rotation mentally. In your example, the solution using my approach would be:

.img-hor {
transform: rotateY(180deg); // Rotate 180 degrees along the y-axis
}


.img-vert {
transform: rotateX(180deg); // Rotate 180 degrees along the x-axis
}


.img-hor-vert {
transform: rotateX(180deg) rotateY(180deg); // Rotate 180 degrees on both
}

The JS fiddle to demonstrate the solution is https://jsfiddle.net/n20196us/1/


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