This works on Python 2 (but not Python 3):

>>> 'foobar'.encode('rot13')
'sbbone'

Try this:

import codecs
codecs.encode("text to be rot13()'ed", "rot_13")

The maketrans and translate methods of str are handy for this type of thing.

Here's a general solution:

import string


def make_rot_n(n):
lc = string.ascii_lowercase
uc = string.ascii_uppercase
trans = str.maketrans(lc + uc,
lc[n:] + lc[:n] + uc[n:] + uc[:n])
return lambda s: str.translate(s, trans)


rot13 = make_rot_n(13)


rot13('foobar')
# 'sbbone'

maketrans()/translate() solutions…

Python 2.x

import string
rot13 = string.maketrans(
"ABCDEFGHIJKLMabcdefghijklmNOPQRSTUVWXYZnopqrstuvwxyz",
"NOPQRSTUVWXYZnopqrstuvwxyzABCDEFGHIJKLMabcdefghijklm")
string.translate("Hello World!", rot13)
# 'Uryyb Jbeyq!'

Python 3.x

rot13 = str.maketrans(
'ABCDEFGHIJKLMabcdefghijklmNOPQRSTUVWXYZnopqrstuvwxyz',
'NOPQRSTUVWXYZnopqrstuvwxyzABCDEFGHIJKLMabcdefghijklm')
'Hello World!'.translate(rot13)
# 'Uryyb Jbeyq!'

It's very simple:

>>> import codecs
>>> codecs.encode('foobar', 'rot_13')
'sbbone'

From the builtin module this.py (import this):

s = "foobar"


d = {}
for c in (65, 97):
for i in range(26):
d[chr(i+c)] = chr((i+13) % 26 + c)


print("".join([d.get(c, c) for c in s]))  # sbbone

As of Python 3.1, string.translate and string.maketrans no longer exist. However, these methods can be used with bytes instead.

Thus, an up-to-date solution directly inspired from Paul Rubel's one, is:

rot13 = bytes.maketrans(
b"abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ",
b"nopqrstuvwxyzabcdefghijklmNOPQRSTUVWXYZABCDEFGHIJKLM")
b'Hello world!'.translate(rot13)

Conversion from string to bytes and vice-versa can be done with the encode and decode built-in functions.

For arbitrary values, something like this works for 2.x

from string import ascii_uppercase as uc, ascii_lowercase as lc, maketrans


rotate = 13 # ROT13
rot = "".join([(x[:rotate][::-1] + x[rotate:][::-1])[::-1] for x in (uc,lc)])


def rot_func(text, encode=True):
ascii = uc + lc
src, trg = (ascii, rot) if encode else (rot, ascii)
trans = maketrans(src, trg)
return text.translate(trans)


text = "Text to ROT{}".format(rotate)
encode = rot_func(text)
decode = rot_func(encode, False)

This works for uppercase and lowercase. I don't know how elegant you deem it to be.

def rot13(s):
rot=lambda x:chr(ord(x)+13) if chr(ord(x.lower())+13).isalpha()==True else chr(ord(x)-13)
s=[rot(i) for i in filter(lambda x:x!=',',map(str,s))]
return ''.join(s)

def rot13(s):
lower_chars = ''.join(chr(c) for c in range (97,123)) #ASCII a-z
upper_chars = ''.join(chr(c) for c in range (65,91)) #ASCII A-Z
lower_encode = lower_chars[13:] + lower_chars[:13] #shift 13 bytes
upper_encode = upper_chars[13:] + upper_chars[:13] #shift 13 bytes
output = "" #outputstring
for c in s:
if c in lower_chars:
output = output + lower_encode[lower_chars.find(c)]
elif c in upper_chars:
output = output + upper_encode[upper_chars.find(c)]
else:
output = output + c
return output

Another solution with shifting. Maybe this code helps other people to understand rot13 better. Haven't tested it completely.

You can support uppercase letters on the original code posted by Mr. Walter by alternating the upper case and lower case letters.

chars = "AaBbCcDdEeFfGgHhIiJjKkLlMmNnOoPpQqRrSsTtUuVvWwXxYyZz"

If you notice the index of the uppercase letters are all even numbers while the index of the lower case letters are odd.

• A = 0 a = 1,
• B = 2, b = 3,
• C = 4, c = 4,
• ...

This odd-even pattern allows us to safely add the amount needed without having to worry about the case.

trans = chars[26:] + chars[:26]

The reason you add 26 is because the string has doubled in letters due to the upper case letters. However, the shift is still 13 spaces on the alphabet.

The full code:

def rot13(s):
chars = "AaBbCcDdEeFfGgHhIiJjKkLlMmNnOoPpQqRrSsTtUuVvWwXxYyZz"
trans = chars[26:]+chars[:26]
rot_char = lambda c: trans[chars.find(c)] if chars.find(c) > -1 else c
return ''.join(rot_char(c) for c in s)

OUTPUT (Tested with python 2.7):

print rot13("Hello World!") --> Uryyb Jbeyq!

from string import maketrans, lowercase, uppercase


def rot13(message):
lower = maketrans(lowercase, lowercase[13:] + lowercase[:13])
upper = maketrans(uppercase, uppercase[13:] + uppercase[:13])
return message.translate(lower).translate(upper)

Interesting exercise ;-) i think i have the best solution because:

1. no modules needed, uses only built-in functions --> no deprecation
2. it can be used as a one liner
3. based on ascii, no mapping dicts/strings etc.

Python 2 & 3 (probably Python 1):

def rot13(s):
return ''.join([chr(ord(n) + (13 if 'Z' < n < 'n' or n < 'N' else -13)) if n.isalpha() else n for n in s])


def rot13_verbose(s):
x = []
for n in s:
if n.isalpha():
# 'n' is the 14th character in the alphabet so if a character is bigger we can subtract 13 to get rot13
ort = 13 if 'Z' < n < 'n' or n < 'N' else -13
x.append(chr(ord(n) + ort))
else:
x.append(n)
return ''.join(x)






# crazy .min version (99 characters) disclaimer: not pep8 compatible^


def r(s):return''.join([chr(ord(n)+(13if'Z'<n<'n'or'N'>n else-13))if n.isalpha()else n for n in s])

I found this post when I started wondering about the easiest way to implement rot13 into Python myself. My goals were:

• Works in both Python 2.7.6 and 3.3.
• Handle both upper and lower case.
• Not use any external libraries.

This meets all three of those requirements. That being said, I'm sure it's not winning any code golf competitions.

def rot13(string):
CLEAR = 'ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz'
ROT13 = 'NOPQRSTUVWXYZABCDEFGHIJKLMnopqrstuvwxyzabcdefghijklm'
TABLE = {x: y for x, y in zip(CLEAR, ROT13)}


return ''.join(map(lambda x: TABLE.get(x, x), string))






if __name__ == '__main__':
CLEAR = 'Hello, World!'
R13 = 'Uryyb, Jbeyq!'


r13 = rot13(CLEAR)
assert r13 == R13


clear = rot13(r13)
assert clear == CLEAR

This works by creating a lookup table and simply returning the original character for any character not found in the lookup table.

Update

I got to worrying about someone wanting to use this to encrypt an arbitrarily-large file (say, a few gigabytes of text). I don't know why they'd want to do this, but what if they did? So I rewrote it as a generator. Again, this has been tested in both Python 2.7.6 and 3.3.

def rot13(clear):
CLEAR = 'ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz'
ROT13 = 'NOPQRSTUVWXYZABCDEFGHIJKLMnopqrstuvwxyzabcdefghijklm'
TABLE = {x: y for x, y in zip(CLEAR, ROT13)}


for c in clear:
yield TABLE.get(c, c)






if __name__ == '__main__':
CLEAR = 'Hello, World!'
R13 = 'Uryyb, Jbeyq!'


r13 = ''.join(rot13(CLEAR))
assert r13 == R13


clear = ''.join(rot13(r13))
assert clear == CLEAR

The following function rot(s, n) encodes a string s with ROT-n encoding for any integer n, with n defaulting to 13. Both upper- and lowercase letters are supported. Values of n over 26 or negative values are handled appropriately, e.g., shifting by 27 positions is equal to shifting by one position. Decoding is done with invrot(s, n).

import string


def rot(s, n=13):
'''Encode string s with ROT-n, i.e., by shifting all letters n positions.
When n is not supplied, ROT-13 encoding is assumed.
'''
upper = string.ascii_uppercase
lower = string.ascii_lowercase
upper_start = ord(upper[0])
lower_start = ord(lower[0])
out = ''
for letter in s:
if letter in upper:
out += chr(upper_start + (ord(letter) - upper_start + n) % 26)
elif letter in lower:
out += chr(lower_start + (ord(letter) - lower_start + n) % 26)
else:
out += letter
return(out)


def invrot(s, n=13):
'''Decode a string s encoded with ROT-n-encoding
When n is not supplied, ROT-13 is assumed.
'''
return(rot(s, -n))

In python-3 the str-codec that @amber mentioned has moved to codecs standard-library:

> import codecs
> codecs.encode('foo', 'rot13')
sbb

You can also use this also

def n3bu1A(n):
o=""
key = {
'a':'n', 'b':'o', 'c':'p', 'd':'q', 'e':'r', 'f':'s', 'g':'t', 'h':'u',
'i':'v', 'j':'w', 'k':'x', 'l':'y', 'm':'z', 'n':'a', 'o':'b', 'p':'c',
'q':'d', 'r':'e', 's':'f', 't':'g', 'u':'h', 'v':'i', 'w':'j', 'x':'k',
'y':'l', 'z':'m', 'A':'N', 'B':'O', 'C':'P', 'D':'Q', 'E':'R', 'F':'S',
'G':'T', 'H':'U', 'I':'V', 'J':'W', 'K':'X', 'L':'Y', 'M':'Z', 'N':'A',
'O':'B', 'P':'C', 'Q':'D', 'R':'E', 'S':'F', 'T':'G', 'U':'H', 'V':'I',
'W':'J', 'X':'K', 'Y':'L', 'Z':'M'}
for x in n:
v = x in key.keys()
if v == True:
o += (key[x])
else:
o += x
return o


Yes = n3bu1A("N zhpu fvzcyre jnl gb fnl Guvf vf zl Zragbe!!")
print(Yes)

A one-liner to rot13 a string S:

S.translate({a : a + (lambda x: 1 if x>=0 else -1)(77 - a) * 13 for a in range(65, 91)})

I couldn't leave this question here with out a single statement using the modulo operator.

def rot13(s):
return ''.join([chr(x.islower() and ((ord(x) - 84) % 26) + 97
or x.isupper() and ((ord(x) - 52) % 26) + 65
or ord(x))
for x in s])

This is not pythonic nor good practice, but it works!

>> rot13("Hello World!")
Uryyb Jbeyq!

Short solution:

def rot13(text):
return "".join([x if ord(x) not in range(65, 91)+range(97, 123) else
chr(((ord(x)-97+13)%26)+97) if x.islower() else
chr(((ord(x)-65+13)%26)+65) for x in text])