如何检索 NumPy 的随机数生成器的当前种子？

The short answer is that you simply can't (at least not in general).

The Mersenne Twister RNG used by numpy has 2¹⁹⁹³⁷-1 possible internal states, whereas a single 64 bit integer has only 2⁶⁴ possible values. It's therefore impossible to map every RNG state to a unique integer seed.

You can get and set the internal state of the RNG directly using np.random.get_state and np.random.set_state. The output of get_state is a tuple whose second element is a (624,) array of 32 bit integers. This array has more than enough bits to represent every possible internal state of the RNG (2^{624 * 32} > 2¹⁹⁹³⁷-1).

The tuple returned by get_state can be used much like a seed in order to create reproducible sequences of random numbers. For example:

import numpy as np


# randomly initialize the RNG from some platform-dependent source of entropy
np.random.seed(None)


# get the initial state of the RNG
st0 = np.random.get_state()


# draw some random numbers
print(np.random.randint(0, 100, 10))
# [ 8 76 76 33 77 26  3  1 68 21]


# set the state back to what it was originally
np.random.set_state(st0)


# draw again
print(np.random.randint(0, 100, 10))
# [ 8 76 76 33 77 26  3  1 68 21]

Check the first element of the array returned by np.random.get_state(), it seems exactly the random seed to me.

This contribution is intended to serve as a clarification to the right answer from ali_m, and as an important correction to the suggestion from Dong Justin.

These are my findings:

1. After setting the random seed using np.random.seed(X) you can find it again using np.random.get_state()[1][0].
2. It will, however, be of little use to you.

The output from the following code sections will show you why both statements are correct.

Statement 1 - you can find the random seed using np.random.get_state()[1][0].

If you set the random seed using np.random.seed(123), you can retrieve the random state as a tuple using state = np.random.get_state(). Below is a closer look at state (I'm using the Variable explorer in Spyder). I'm using a screenshot since using print(state) will flood your console because of the size of the array in the second element of the tuple.

You can easily see 123 as the first number in the array contained in the second element. And using seed = np.random.get_state()[1][0] will give you 123. Perfect? Not quite, because:

Statement 2 - It will, however, be of little use to you:

It may not seem so at first though, because you could use np.random.seed(123), retrieve the same number with seed = np.random.get_state()[1][0], reset the seed with np.random.seed(444), and then (seemingly) set it back to the 123 scenario with np.random.seed(seed). But then you'd already know what your random seed was before, so you wouldn't need to do it that way. The next code section will also show that you can not take the first number of any random state using np.random.get_state()[1][0] and expect to recreate that exact scenario. Note that you'll most likely have to shut down and restart your kernel seed = np.random.get_state()[1][0]0 (or call np.random.seed(None)) in order to be able to see this.

The following snippet uses np.random.randint() to generate 5 random integers between -10 and 10, as well as storing some info about the process:

Snippet 1

# 1. Imports
import pandas as pd
import numpy as np


# 2. set random seed
#seedSet = None
seedSet = 123
np.random.seed(seedSet)


# 3. describe random state
state = np.random.get_state()
state5 = np.random.get_state()[1][:5]
seedState = np.random.get_state()[1][0]


# 4. generate random numbers
random = np.random.randint(-10, 10, size = 5)


# 5. organize and present findings
df = pd.DataFrame.from_dict({'seedSet':seedSet, 'seedState':seedState, 'state':state, 'random':random})
print(df)

Notice that the column named seedState is the same as the first number under state. I could have printed it as a stand-alone number, but I wanted to keep it all in the same place. Also notice that, seedSet = 123, and np.random.seed(seedSet) so far have been commented out. And because no random seed has been set, your numbers will differ from mine. But that is not what is important here, but rather the internal consisteny of your results:

Output 1:

   random seedSet   seedState       state
0       2    None  1558056443  1558056443
1      -1    None  1558056443  1808451632
2       4    None  1558056443   730968006
3      -4    None  1558056443  3568749506
4      -6    None  1558056443  3809593045

In this particular case seed = np.random.get_state()[1][0] equals 1558056443. And following the logic from Dong Justins answer (as well as my own answer prior to this edit), you could set the random seed with np.random.seed(1558056443) and obtain the same random state. The next snippet will show that you can not:

Snippet 2

# 1. Imports
import pandas as pd
import numpy as np


# 2. set random seed
#seedSet = None
seedSet = 1558056443
np.random.seed(seedSet)


# 3. describe random state
#state = np.random.get_state()
state = np.random.get_state()[1][:5]
seedState = np.random.get_state()[1][0]


# 4. generate random numbers
random = np.random.randint(-10, 10, size = 5)


# 5. organize and present findings
df = pd.DataFrame.from_dict({'seedSet':seedSet, 'seedState':seedState, 'state':state, 'random':random})
print(df)

Output 2:

   random     seedSet   seedState       state
0       8  1558056443  1558056443  1558056443
1       3  1558056443  1558056443  1391218083
2       7  1558056443  1558056443  2754892524
3      -8  1558056443  1558056443  1971852777
4       4  1558056443  1558056443  2881604748

See the difference? np.random.get_state()[1][0] is identical for Output 1 and Output 2, but the rest of the output is not (most importantly the random numbers are not the same). So, as ali_m already has clearly stated:

It's therefore impossible to map every RNG state to a unique integer seed.

This answer complements important details others missed. First, to rephrase the conclusion:

Original random seeds (set via np.random.seed) cannot be retrieved after generating numbers, but intermediates (current state) can.

Refer to @vestland's answer; it may, however, mislead: the generated numbers differ not due to inability to map states, but that an incomplete encoding is used: get_state()[1]. The complete representation includes pos = get_state()[2]. To illustrate:

import numpy as np


state0 = np.random.get_state()
rand0  = np.random.randint(0, 10, 1)
state1 = np.random.get_state()
rand1  = np.random.randint(0, 10, 1)


assert all(s0 == s1 for s0, s1 in zip(state0[1], state1[1]))

We generated a number, yet get_state()[1] remained identical. However:

np.random.set_state(state0)
assert np.random.randint(0, 10, 1) == rand0

and likewise for state1 & rand1. Hence, @vestland's numbers differ because when not setting a seed, pos = 623 - whereas if we use np.random.seed, pos = 624. Why the inconvenient discrepancy? No clue.

In summary on np.random.seed(s):

• get_state()[1][0] immediately after setting: retrieves s that exactly recreates the state
• get_state()[1][0] after generating numbers: may or may not retrieve s, but it will not recreate the current state (at get_state())
• get_state()[1][0] after generating many numbers: will not retrieve s. This is because pos exhausted its representation.
• get_state() at any point: will exactly recreate that point.

Lastly, behavior may also differ due to get_state()[3:] (and of course [0]).

While what the top answer says is generally true, in that it’s not possible in general, it is in fact possible. I would redirect you to this persons blog: https://kamila.akagi.moe/posts/mersenne-twister/

This individual developed a mersenne twister cracking algorithm to recover initial seeds, and provided the details and algorithm in full. I am not the author, and do not understand what the material in full, but anybody interested in doing this should check this out.

A simple solution to know the random seed could be to randomly generate one, and then seed the random number generator. Something like the following:

import numpy as np
seed = int(np.random.rand() * (2**32 - 1))
np.random.seed(seed)