Python: 如何打印范围 a-z？

>>> import string
>>> string.ascii_lowercase[:14]
'abcdefghijklmn'
>>> string.ascii_lowercase[:14:2]
'acegikm'

要做网址，你可以使用这样的东西

[i + j for i, j in zip(list_of_urls, string.ascii_lowercase[:14])]

提示:

import string
print string.ascii_lowercase

还有

for i in xrange(0, 10, 2):
print i

还有

"hello{0}, world!".format('z')

for one in range(97,110):
print chr(one)

这是你的第二个问题: string.lowercase[ord('a')-97:ord('n')-97:2]，因为 97==ord('a')——如果你想学一点，你应该自己弄清楚剩下的; -)

假设这是一个家庭作业; ——不需要召唤库等——它可能希望你使用 range ()和 chr/ord，像这样:

for i in range(ord('a'), ord('n')+1):
print chr(i),

对于其余部分，只需使用 range ()进行更多操作

关于纳布勒的回答。

Zip 函数，完整的解释，返回 a list of tuples, where the i-th tuple contains the i-th element from each of the argument sequences or iterables.的 [...]构造被称为 列表内涵，非常酷的功能！

#1)
print " ".join(map(chr, range(ord('a'),ord('n')+1)))


#2)
print " ".join(map(chr, range(ord('a'),ord('n')+1,2)))


#3)
urls = ["hello.com/", "hej.com/", "hallo.com/"]
an = map(chr, range(ord('a'),ord('n')+1))
print [ x + y for x,y in zip(urls, an)]

获取具有所需值的列表

small_letters = map(chr, range(ord('a'), ord('z')+1))
big_letters = map(chr, range(ord('A'), ord('Z')+1))
digits = map(chr, range(ord('0'), ord('9')+1))

或者

import string
string.letters
string.uppercase
string.digits

该解决方案使用 ASCII 表.ord从字符获取 ascii 值，反之亦然。

应用你对列表的了解

>>> small_letters = map(chr, range(ord('a'), ord('z')+1))


>>> an = small_letters[0:(ord('n')-ord('a')+1)]
>>> print(" ".join(an))
a b c d e f g h i j k l m n


>>> print(" ".join(small_letters[0::2]))
a c e g i k m o q s u w y


>>> s = small_letters[0:(ord('n')-ord('a')+1):2]
>>> print(" ".join(s))
a c e g i k m


>>> urls = ["hello.com/", "hej.com/", "hallo.com/"]
>>> print([x + y for x, y in zip(urls, an)])
['hello.com/a', 'hej.com/b', 'hallo.com/c']

试试:

strng = ""
for i in range(97,123):
strng = strng + chr(i)
print(strng)

import string
print list(string.ascii_lowercase)
# ['a', 'b', 'c', 'd', 'e', 'f', 'g', 'h', 'i', 'j', 'k', 'l', 'm', 'n', 'o', 'p', 'q', 'r', 's', 't', 'u', 'v', 'w', 'x', 'y', 'z']

list(string.ascii_lowercase)


['a', 'b', 'c', 'd', 'e', 'f', 'g', 'h', 'i', 'j', 'k', 'l', 'm', 'n', 'o', 'p', 'q', 'r', 's', 't', 'u', 'v', 'w', 'x', 'y', 'z']

这个问题的答案很简单，只要像下面这样列一个名为 ABC 的清单:

ABC = ['abcdefghijklmnopqrstuvwxyz']

无论什么时候你需要提到它，只要做:

print ABC[0:9] #prints abcdefghij
print ABC       #prints abcdefghijklmnopqrstuvwxyz
for x in range(0,25):
if x % 2 == 0:
print ABC[x] #prints acegikmoqsuwy (all odd numbered letters)

也可以尝试这样破坏你的设备: D

##Try this and call it AlphabetSoup.py:


ABC = ['abcdefghijklmnopqrstuvwxyz']




try:
while True:
for a in ABC:
for b in ABC:
for c in ABC:
for d in ABC:
for e in ABC:
for f in ABC:
print a, b, c, d, e, f, '    ',
except KeyboardInterrupt:
pass

import string
print list(string.ascii_lowercase)
# ['a', 'b', 'c', 'd', 'e', 'f', 'g', 'h', 'i', 'j', 'k', 'l', 'm', 'n', 'o', 'p', 'q', 'r', 's', 't', 'u', 'v', 'w', 'x', 'y', 'z']

还有

for c in list(string.ascii_lowercase)[:5]:
...operation with the first 5 characters

另一种方法

import string


aalist = list(string.ascii_lowercase)
aaurls = ['alpha.com','bravo.com','chrly.com','delta.com',]
iilen  =  aaurls.__len__()


ans01 = "".join( (aalist[0:14]) )
ans02 = "".join( (aalist[0:14:2]) )
ans03 = "".join( "{vurl}/{vl}\n".format(vl=vlet,vurl=aaurls[vind % iilen]) for vind,vlet in enumerate(aalist[0:14]) )


print(ans01)
print(ans02)
print(ans03)

结果

abcdefghijklmn
acegikm
alpha.com/a
bravo.com/b
chrly.com/c
delta.com/d
alpha.com/e
bravo.com/f
chrly.com/g
delta.com/h
alpha.com/i
bravo.com/j
chrly.com/k
delta.com/l
alpha.com/m
bravo.com/n

这与其他答复有何不同

• 遍历任意数量的基 URL
• 使用同余关系循环遍历 url，直到字母用完为止
• 与列表内涵和 str.format 一起使用 enumerate

我希望这能有所帮助:

import string


alphas = list(string.ascii_letters[:26])
for chr in alphas:
print(chr)

myList = [chr(chNum) for chNum in list(range(ord('a'),ord('z')+1))]
print(myList)

输出

['a', 'b', 'c', 'd', 'e', 'f', 'g', 'h', 'i', 'j', 'k', 'l', 'm', 'n', 'o', 'p', 'q', 'r', 's', 't', 'u', 'v', 'w', 'x', 'y', 'z']

import string


string.printable[10:36]
# abcdefghijklmnopqrstuvwxyz
    

string.printable[10:62]
# abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ

# Assign the range of characters
first_char_start = 'a'
last_char = 'n'


# Generate a list of assigned characters (here from 'a' to 'n')
alpha_list = [chr(i) for i in range(ord(first_char), ord(last_char) + 1)]


# Print a-n with spaces: a b c d e f g h i j k l m n
print(" ".join(alpha_list))


# Every second in a-n: a c e g i k m
print(" ".join(alpha_list[::2]))


# Append a-n to index of urls{hello.com/, hej.com/, ..., hallo.com/}
# Ex.hello.com/a hej.com/b ... hallo.com/n


#urls: list of urls
results = [i+j for i, j in zip(urls, alpha_list)]


#print new url list 'results' (concatenated two lists element-wise)
print(results)