生成字母表中的字母数组

I don't think there is a built in way, but I think the easiest would be

  char[] alpha = "ABCDEFGHIJKLMNOPQRSTUVWXYZ".ToCharArray();

You could do something like this, based on the ascii values of the characters:

char[26] alphabet;


for(int i = 0; i <26; i++)
{
alphabet[i] = (char)(i+65); //65 is the offset for capital A in the ascaii table
}

(See the table here.) You are just casting from the int value of the character to the character value - but, that only works for ascii characters not different languages etc.

EDIT: As suggested by Mehrdad in the comment to a similar solution, it's better to do this:

alphabet[i] = (char)(i+(int)('A'));

This casts the A character to it's int value and then increments based on this, so it's not hardcoded.

Assuming you mean the letters of the English alphabet...

    for ( int i = 0; i < 26; i++ )
{
Console.WriteLine( Convert.ToChar( i + 65 ) );
}
Console.WriteLine( "Press any key to continue." );
Console.ReadKey();

C# 3.0 :

char[] az = Enumerable.Range('a', 'z' - 'a' + 1).Select(i => (Char)i).ToArray();
foreach (var c in az)
{
Console.WriteLine(c);
}

yes it does work even if the only overload of Enumerable.Range accepts int parameters ;-)

Note also, the string has a operator[] which returns a Char, and is an IEnumerable<char>, so for most purposes, you can use a string as a char[]. Hence:

string alpha = "ABCDEFGHIJKLMNOPQRSTUVQXYZ";
for (int i =0; i < 26; ++i)
{
Console.WriteLine(alpha[i]);
}


foreach(char c in alpha)
{
Console.WriteLine(c);
}

char alphaStart = Char.Parse("A");
char alphaEnd = Char.Parse("Z");
for(char i = alphaStart; i <= alphaEnd; i++) {
string anchorLetter = i.ToString();
}

//generate a list of alphabet using csharp
//this recurcive function will return you
//a string with position of passed int
//say if pass 0 will return A ,1-B,2-C,.....,26-AA,27-AB,....,701-ZZ,702-AAA,703-AAB,...


static string CharacterIncrement(int colCount)
{
int TempCount = 0;
string returnCharCount = string.Empty;


if (colCount <= 25)
{
TempCount = colCount;
char CharCount = Convert.ToChar((Convert.ToInt32('A') + TempCount));
returnCharCount += CharCount;
return returnCharCount;
}
else
{
var rev = 0;


while (colCount >= 26)
{
colCount = colCount - 26;
rev++;
}


returnCharCount += CharacterIncrement(rev-1);
returnCharCount += CharacterIncrement(colCount);
return returnCharCount;
}
}


//--------this loop call this function---------//
int i = 0;
while (i <>
{
string CharCount = string.Empty;
CharCount = CharacterIncrement(i);


i++;
}

I wrote this to get the MS excel column code (A,B,C, ..., Z, AA, AB, ..., ZZ, AAA, AAB, ...) based on a 1-based index. (Of course, switching to zero-based is simply leaving off the column--; at the start.)

public static String getColumnNameFromIndex(int column)
{
column--;
String col = Convert.ToString((char)('A' + (column % 26)));
while (column >= 26)
{
column = (column / 26) -1;
col = Convert.ToString((char)('A' + (column % 26))) + col;
}
return col;
}

for (char letter = 'A'; letter <= 'Z'; letter++)
{
Debug.WriteLine(letter);
}

Surprised no one has suggested a yield solution:

public static IEnumerable<char> Alphabet()
{
for (char letter = 'A'; letter <= 'Z'; letter++)
{
yield return letter;
}
}

Example:

foreach (var c in Alphabet())
{
Console.Write(c);
}

char[] alphabet = Enumerable.Range('A', 26).Select(x => (char)x).ToArray();

var alphabets = Enumerable.Range('A', 26).Select((num) => ((char)num).ToString()).ToList();

4 ways get English alphabet in Console:

public void ShowEnglishAlphabet()
{
var firstLetter = 'a';
var endLetter = 'z';
for (var letter = firstLetter; letter <= endLetter; letter++)
{
Console.WriteLine($"{letter}-{letter.ToString().ToUpper()}");
}
}


public void ShowEnglishAlphabetFromUnicodeTableDecNumber()
{
var firstLetter = 97;
var endLetter = 122;
for (var letterNumberUnicodeTable = firstLetter;
letterNumberUnicodeTable <= endLetter; letterNumberUnicodeTable++)
{
Console.WriteLine($"{(char)letterNumberUnicodeTable}-
{((char)letterNumberUnicodeTable).ToString().ToUpper()}");
}
}


public void ShowEnglishAlphabetUnicodeTableEscapeSequence()
{
var firstLetter = '\u0061';
var endLetter = '\u007A';
for (var letterNumberUnicodeTable = firstLetter;
letterNumberUnicodeTable <= endLetter; letterNumberUnicodeTable++)
{
Console.WriteLine($"{letterNumberUnicodeTable}-
{letterNumberUnicodeTable.ToString().ToUpper()}");
}
}


public void ShowEnglishAlphabetUnicodeTableLinq()
{
var alphabets = Enumerable.Range('a', 26).Select(letter =>
((char)letter).ToString()).ToList();
foreach (var letter in alphabets)
{
Console.WriteLine($"{letter}-{letter.ToUpper()}");
}
}

Unfortunately there is no ready-to-use way.

You can use; char[] characters = "ABCDEFGHIJKLMNOPQRSTUVWXYZ".ToCharArray();