在数字列表中找出最大的数字

有没有简单的方法或函数来确定 python 列表中的最大值？我可以只编码它，因为我只有三个数字，但是如果我可以用一个内置的函数或其他东西来判断最大值的话，它会使代码少很多冗余。

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最佳答案

What about max()

highest = max(1, 2, 3)  # or max([1, 2, 3]) for lists
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Use max()

>>> l = [1, 2, 5]
>>> max(l)
5
>>>
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You can use the inbuilt function max() with multiple arguments:

print max(1, 2, 3)

or a list:

list = [1, 2, 3]
print max(list)

or in fact anything iterable.

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    #Ask for number input
first = int(raw_input('Please type a number: '))
second = int(raw_input('Please type a number: '))
third = int(raw_input('Please type a number: '))
fourth = int(raw_input('Please type a number: '))
fifth = int(raw_input('Please type a number: '))
sixth = int(raw_input('Please type a number: '))
seventh = int(raw_input('Please type a number: '))
eighth = int(raw_input('Please type a number: '))
ninth = int(raw_input('Please type a number: '))
tenth = int(raw_input('Please type a number: '))


#create a list for variables
sorted_list = [first, second, third, fourth, fifth, sixth, seventh,
eighth, ninth, tenth]
odd_numbers = []


#filter list and add odd numbers to new list
for value in sorted_list:
if value%2 != 0:
odd_numbers.append(value)
print 'The greatest odd number you typed was:', max(odd_numbers)
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This approach is without using max() function

a = [1,2,3,4,6,7,99,88,999]
max_num = 0
for i in a:
if i > max_num:
max_num = i
print(max_num)

Also if you want to find the index of the resulting max,

print(a.index(max_num))

Direct approach by using function max()

max() function returns the item with the highest value, or the item with the highest value in an iterable

Example: when you have to find max on integers/numbers

a = (1, 5, 3, 9)
print(max(a))
>> 9

Example: when you have string

x = max("Mike", "John", "Vicky")
print(x)
>> Vicky

It basically returns the name with the highest value, ordered alphabetically.

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max is a builtin function in python, which is used to get max value from a sequence, i.e (list, tuple, set, etc..)

print(max([9, 7, 12, 5]))


# prints 12
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You can actually sort it:

sorted(l,reverse=True)

l = [1, 2, 3]
sort=sorted(l,reverse=True)
print(sort)

You get:

[3,2,1]

But still if want to get the max do:

print(sort[0])

You get:

3

if second max:

print(sort[1])

and so on...


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