确定从哪里调用函数

有没有办法知道 PHP 中的函数是从哪里调用的? 例如:

function epic()
{
fail();
}


function fail()
{
//at this point, how do i know, that epic() has called this function?
}
65699 次浏览

Use debug_backtrace():

function fail()
{
$backtrace = debug_backtrace();


// Here, $backtrace[0] points to fail(), so we'll look in $backtrace[1] instead
if (isset($backtrace[1]['function']) && $backtrace[1]['function'] == 'epic')
{
// Called by epic()...
}
}

You can use debug_backtrace().

Example:

<?php


function epic( $a, $b )
{
fail( $a . ' ' . $b );
}


function fail( $string )
{
$backtrace = debug_backtrace();


print_r( $backtrace );
}


epic( 'Hello', 'World' );

Output:

Array
(
[0] => Array
(
[file] => /Users/romac/Desktop/test.php
[line] => 5
[function] => fail
[args] => Array
(
[0] => Hello World
)


)


[1] => Array
(
[file] => /Users/romac/Desktop/test.php
[line] => 15
[function] => epic
[args] => Array
(
[0] => Hello
[1] => World
)


)


)
function findFunction($function, $inputDirectory=""){
//version 0.1
$docRoot = getenv("DOCUMENT_ROOT");
$folderArray = null;
$dirArray = null;


// open directory
$directory = opendir($docRoot.$inputDirectory);


// get each entry
while($entryName = readdir($directory)) {
if(is_dir($entryName) && $entryName != "." && $entryName != ".."){
$folderArray[] = str_replace($inputDirectory, "", $entryName);
}
$ext = explode(".", $entryName);
if(!empty($ext[1])){
$dirArray[] = $docRoot.$inputDirectory."/".$entryName;
}
}


// close directory
closedir($directory);
$found = false;


if(is_array($dirArray)){
foreach($dirArray as $current){
$myFile = file_get_contents($current);
$myFile = str_replace("<?php", "", $myFile);
$myFile = str_replace("?>", "", $myFile);
if(preg_match("/function ".$function."/", $myFile)){
$found = true;
$foundLocation = $current;
break;
}
}
}
if($found){
echo $foundLocation;
exit;
} else if(is_array($folderArray)){
foreach($folderArray as $folder){
if(!isset($return)){
$return = findFunction($function, $inputDirectory."/".$folder);
} else if($return == false){
$return = findFunction($function, $inputDirectory."/".$folder);
}
}
} else {
return false;
}
}


findFunction("testFunction", "rootDirectory");

Hope it helps somebody. If the actual function is outside httpdocs then it can not be found because the server will be setup to not allow it. Only tested it one folder deep too but the recursive methodology should work in theory.

This is like version 0.1 but I don't intend on continuing development on it so if someone updates it feel free to repost it.

So if you still REALLY don't know how, than here is solution:

$backtrace = debug_backtrace();
echo 'Mu name is '.$backtrace[1]['function'].', and I have called him! Muahahah!';

Try below code.

foreach(debug_backtrace() as $t) {
echo $t['file'] . ' line ' . $t['line'] . ' calls ' . $t['function'] . "()<br/>";
}

Fastest and simplest solution as I found

public function func() { //function whose call file you want to find
$trace = debug_backtrace(DEBUG_BACKTRACE_IGNORE_ARGS, 1);
}


$trace: Array
(
[0] => Array
(
[file] => C:\wamp\www\index.php
[line] => 56
[function] => func
[class] => (func Class namespace)
[type] => ->
)


)

I test the speed on Lenovo laptop: Intel Pentiom CPU N3530 2.16GHz, RAM 8GB

global $times;
$start = microtime(true);
$trace = debug_backtrace(DEBUG_BACKTRACE_IGNORE_ARGS, 1);
$times[] = microtime(true) - $start;

Results:

count($times):  97
min:    2.6941299438477E-5
max:   10.68115234375E-5
avg:    3.3095939872191E-5
median: 3.0517578125E-5
sum:  321.03061676025E-5


the same results with notation without E-5
count($times):  97
min:    0.000026941299438477
max:    0.0001068115234375
avg:    0.000033095939872191
median: 0.000030517578125
sum:    0.0032103061676025

If you want to trace the exact origin of the call at the top of the stack you can use the following code:

$call_origin = end(debug_backtrace(DEBUG_BACKTRACE_IGNORE_ARGS));

This will ignore chained functions and get only the most relevant call info (relevant is used loosely as it depends what your are trying to accomplish).