使用 C # 中的 XDocument 创建 XML 文件

我有一个 List<string>“ sampleList”，其中包含

Data1
Data2
Data3...

文件结构就像

<file>
<name filename="sample"/>
<date modified ="  "/>
<info>
<data value="Data1"/>
<data value="Data2"/>
<data value="Data3"/>
</info>
</file>

我目前正在使用 XmlDocument 来完成这项工作。

例如:

List<string> lst;
XmlDocument XD = new XmlDocument();
XmlElement root = XD.CreateElement("file");
XmlElement nm = XD.CreateElement("name");
nm.SetAttribute("filename", "Sample");
root.AppendChild(nm);
XmlElement date = XD.CreateElement("date");
date.SetAttribute("modified", DateTime.Now.ToString());
root.AppendChild(date);
XmlElement info = XD.CreateElement("info");
for (int i = 0; i < lst.Count; i++)
{
XmlElement da = XD.CreateElement("data");
da.SetAttribute("value",lst[i]);
info.AppendChild(da);
}
root.AppendChild(info);
XD.AppendChild(root);
XD.Save("Sample.xml");

如何使用 XDocument 创建相同的 XML 结构？

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最佳答案

LINQ to XML allows this to be much simpler, through three features:

You can construct an object without knowing the document it's part of
You can construct an object and provide the children as arguments
If an argument is iterable, it will be iterated over

So here you can just do:

void Main()
{
List<string> list = new List<string>
{
"Data1", "Data2", "Data3"
};


XDocument doc =
new XDocument(
new XElement("file",
new XElement("name", new XAttribute("filename", "sample")),
new XElement("date", new XAttribute("modified", DateTime.Now)),
new XElement("info",
list.Select(x => new XElement("data", new XAttribute("value", x)))
)
)
);


doc.Save("Sample.xml");
}

I've used this code layout deliberately to make the code itself reflect the structure of the document.

If you want an element that contains a text node, you can construct that just by passing in the text as another constructor argument:

// Constructs <element>text within element</element>
XElement element = new XElement("element", "text within element");