最佳答案
似乎可以在构造函数中嵌套一个类,然后可以从该类中的任何地方实例化该类,这是正式的吗?
例如:
class C {
constructor() {
class D {
constructor() { }
}
}
method() {
var a = new D(); // works fine
}
}
//var a = new D(); // fails in outer scope
Traceur 生成了 JS https://google.github.io/traceur-compiler/demo/repl.html
$traceurRuntime.ModuleStore.getAnonymousModule(function() {
"use strict";
var C = function C() {
var D = function D() {};
($traceurRuntime.createClass)(D, {}, {});
};
($traceurRuntime.createClass)(C, {method: function() {
var a = new D();
}}, {});
return {};
});
//# sourceURL=traceured.js