用 Python 生成一个随机字母

有没有一种在 Python 中生成随机字母的方法(比如 Random. randint,但是对于字母) ?Randint 的范围功能会很好,但是有一个只输出随机字母的生成器总比没有好。

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简单:

>>> import string
>>> string.ascii_letters
'abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ'
>>> import random
>>> random.choice(string.ascii_letters)
'j'

string.ascii_letters 根据当前语言环境返回一个包含小写和大写字母的字符串。

random.choice 返回序列中的一个随机元素。

>>> import random
>>> import string
>>> random.choice(string.ascii_letters)
'g'

完整性的另一种方法:

>>> chr(random.randrange(97, 97 + 26))

使用 ascii‘ a’是97这个事实,字母表中有26个字母。

在确定 random.randrange()函数调用的上界和下界时,请记住 random.randrange()在其上界上是独占的,这意味着它只会生成比提供的值少1个单位的整数。

>>> import random
>>> import string
>>> random.choice(string.ascii_lowercase)
'b'
def randchar(a, b):
return chr(random.randint(ord(a), ord(b)))

也许这个能帮到你:

import random
for a in range(64,90):
h = random.randint(64, a)
e += chr(h)
print e
>>>def random_char(y):
return ''.join(random.choice(string.ascii_letters) for x in range(y))


>>>print (random_char(5))
>>>fxkea

生成 y 个随机字符

在键盘上放一条蟒蛇,让它滚动字母,直到你找到你喜欢的随机组合。开玩笑!

import string #This was a design above but failed to print. I remodled it.
import random
irandom = random.choice(string.ascii_letters)
print irandom
import string
import random


KEY_LEN = 20


def base_str():
return (string.letters+string.digits)
def key_gen():
keylist = [random.choice(base_str()) for i in range(KEY_LEN)]
return ("".join(keylist))

你可以得到这样的随机字符串:

g9CtUljUWD9wtk1z07iF
ndPbI1DDn6UvHSQoDMtd
klMFY3pTYNVWsNJ6cs34
Qgr7OEalfhXllcFDGh2l
import random
def guess_letter():
return random.choice('abcdefghijklmnopqrstuvwxyz')

你可以列个清单:

import random
list1=['a', 'b', 'c', 'd', 'e', 'f', 'g', 'h']
b=random.randint(0,7)
print(list1[b])

您可以使用此选项获取一个或多个随机字母

import random
import string
random.seed(10)
letters = string.ascii_lowercase
rand_letters = random.choices(letters,k=5) # where k is the number of required rand_letters


print(rand_letters)


['o', 'l', 'p', 'f', 'v']

这就是我的答案!效果很好。只要把你想要的随机字母的数量放在‘ number’中... (Python 3)

import random


def key_gen():
keylist = random.choice('abcdefghijklmnopqrstuvwxyz')
return keylist


number = 0
list_item = ''
while number < 20:
number = number + 1
list_item = list_item + key_gen()


print(list_item)
import string
import random


def random_char(y):
return ''.join(random.choice(string.ascii_letters+string.digits+li) for x in range(y))
no=int(input("Enter the number of character for your password=  "))
li = random.choice('!@#$%^*&( )_+}{')
print(random_char(no)+li)
def create_key(key_len):
key = ''
valid_characters_list = string.letters + string.digits
for i in range(key_len):
character = choice(valid_characters_list)
key = key + character
return key


def create_key_list(key_num):
keys = []
for i in range(key_num):
key = create_key(key_len)
if key not in keys:
keys.append(key)
return keys

前面的所有答案都是正确的,如果你正在寻找各种类型的随机字符(即字母数字和特殊字符) ,那么这里有一个脚本,我创建来演示创建随机函数的各种类型,它有三个函数,一个用于数字,字母字符和特殊字符。该脚本只是生成密码,并且只是演示生成随机字符的各种方法的一个示例。

import string
import random
import sys


#make sure it's 3.7 or above
print(sys.version)


def create_str(str_length):
return random.sample(string.ascii_letters, str_length)


def create_num(num_length):
digits = []
for i in range(num_length):
digits.append(str(random.randint(1, 100)))


return digits


def create_special_chars(special_length):
stringSpecial = []
for i in range(special_length):
stringSpecial.append(random.choice('!$%&()*+,-.:;<=>?@[]^_`{|}~'))


return stringSpecial


print("how many characters would you like to use ? (DO NOT USE LESS THAN 8)")
str_cnt = input()
print("how many digits would you like to use ? (DO NOT USE LESS THAN 2)")
num_cnt = input()
print("how many special characters would you like to use ? (DO NOT USE LESS THAN 1)")
s_chars_cnt = input()
password_values = create_str(int(str_cnt)) +create_num(int(num_cnt)) + create_special_chars(int(s_chars_cnt))


#shuffle/mix the values
random.shuffle(password_values)


print("generated password is: ")
print(''.join(password_values))

结果:

enter image description here

我过于复杂的代码:

import random


letter = (random.randint(1,26))
if letter == 1:
print ('a')
elif letter == 2:
print ('b')
elif letter == 3:
print ('c')
elif letter == 4:
print ('d')
elif letter == 5:
print ('e')
elif letter == 6:
print ('f')
elif letter == 7:
print ('g')
elif letter == 8:
print ('h')
elif letter == 9:
print ('i')
elif letter == 10:
print ('j')
elif letter == 11:
print ('k')
elif letter == 12:
print ('l')
elif letter == 13:
print ('m')
elif letter == 14:
print ('n')
elif letter == 15:
print ('o')
elif letter == 16:
print ('p')
elif letter == 17:
print ('q')
elif letter == 18:
print ('r')
elif letter == 19:
print ('s')
elif letter == 20:
print ('t')
elif letter == 21:
print ('u')
elif letter == 22:
print ('v')
elif letter == 23:
print ('w')
elif letter == 24:
print ('x')
elif letter == 25:
print ('y')
elif letter == 26:
print ('z')

它基本上是从26中随机生成一个数,然后转换成相应的字母。这可以大胆地改进,但我只是一个初学者,我为这段代码感到自豪。

你可以用

map(lambda a : chr(a),  np.random.randint(low=65, high=90, size=4))
import random
def Random_Alpha():
l = ['A','B','C','D','E','F','G','H','I','J','K','L','M','N','O','P','Q','R','S','T','U','V','W','X','Y','Z']
return l[random.randint(0,25)]


print(Random_Alpha())

部分答案的总结与改进。

import numpy as np
n = 5
[chr(i) for i in np.random.randint(ord('a'), ord('z') + 1, n)]
# ['b', 'f', 'r', 'w', 't']
#*A handy python password generator*

这是输出

 import random
letters = ['a', 'b', 'c', 'd', 'e', 'f', 'g', 'h', 'i', 'j', 'k', 'l', 'm', 'n', 'o', 'p', 'q', 'r', 's', 't', 'u', 'v', 'w', 'x', 'y', 'z', 'A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z']
numbers = ['0', '1', '2', '3', '4', '5', '6', '7', '8', '9']
symbols = ['!', '#', '$', '%', '&', '(', ')', '*', '+']
        

print("Welcome to the Python Password Generator!")
l= int(input("How many letters would you like in your password?\n"))
s = int(input(f"How many symbols would you like?\n"))
n = int(input(f"How many numbers would you like?\n"))
        

sequence = random.sample(letters,l)
num      = random.sample(numbers,n)
sym      = random.sample(symbols,s)
sequence.extend(num)
sequence.extend(sym)
         

random.shuffle(sequence)
password = ''.join([str(elem) for elem in sequence])#listToStr
print(password)

它不使用任何花哨的模块,但工作正常:

    ''.join(chr(random.randrange(65,90)) for i in range(10))

另外,如果你更喜欢 numpy而不是 random:

import numpy as np
import string
np.random.choice(list(string.ascii_letters))