How can I format the time elapsed from seconds to hours, mins, seconds?
My code:
start = time.time() ... do something elapsed = (time.time() - start)
Actual Output:
0.232999801636
Desired/Expected output:
00:00:00.23
import time start = time.time() #do something end = time.time() temp = end-start print(temp) hours = temp//3600 temp = temp - 3600*hours minutes = temp//60 seconds = temp - 60*minutes print('%d:%d:%d' %(hours,minutes,seconds))
If you want to include times like 0.232999801636 as in your input:
import time start = time.time() end = time.time() hours, rem = divmod(end-start, 3600) minutes, seconds = divmod(rem, 60) print("{:0>2}:{:0>2}:{:05.2f}".format(int(hours),int(minutes),seconds))
Example:
In [12]: def timer(start,end): ....: hours, rem = divmod(end-start, 3600) ....: minutes, seconds = divmod(rem, 60) ....: print("{:0>2}:{:0>2}:{:05.2f}".format(int(hours),int(minutes),seconds)) ....: In [13]: timer(12345.242,12356.434) 00:00:11.19 In [14]: timer(12300.242,12600.5452) 00:05:00.30 In [19]: timer(0.343,86500.8743) 24:01:40.53 In [16]: timer(0.343,865000.8743) 240:16:40.53 In [17]: timer(0,0.232999801636) 00:00:00.23
You could exploit timedelta:
timedelta
>>> from datetime import timedelta >>> str(timedelta(seconds=elapsed)) '0:00:00.233000'
The strftime function of time itself can be (ab)used with limitations (no millisec and <24 hr)
strftime
time
elapsed = 4*3600 + 13*60 + 6 # 15186 s time.strftime("%Hh%Mm%Ss", time.gmtime(elapsed)) # '04h13m06s'
If you want one line of code without import any other library, that worked for me (Python v3.7.11):
print("Elapsed time: " + time.strftime("%H:%M:%S.{}".format(str(elapsed % 1)[2:])[:15], time.gmtime(elapsed)))
Output:
Elapsed time: 00:38:01.357318
You can control the milliseconds to be displayed by modifying "[:15]" to "[:11]", then you will get the desired result:
Elapsed time: 00:45:18.65