如何检查一个字符串是否包含Objective-C中的另一个字符串？

NSString *string = @"hello bla bla";if ([string rangeOfString:@"bla"].location == NSNotFound) {NSLog(@"string does not contain bla");} else {NSLog(@"string contains bla!");}

关键是注意rangeOfString:返回NSRange结构，留档说如果“干草堆”不包含“针”，它返回结构{NSNotFound, 0}。

如果您使用的是iOS8或OS X Yosemite，现在可以执行以下操作：*（注意：如果在iOS7设备上调用此代码，这将使您的应用程序崩溃）。

NSString *string = @"hello bla blah";if ([string containsString:@"bla"]) {NSLog(@"string contains bla!");} else {NSLog(@"string does not contain bla");}

（这也是它在Swift中的工作方式）

对于iOS8.0+和macOS 10.10+，您可以使用NSString的原生#0。

对于旧版本的iOS和macOS，您可以为NSString创建自己的（过时的）类别：

@interface NSString ( SubstringSearch )- (BOOL)containsString:(NSString *)substring;@end
// - - - -
@implementation NSString ( SubstringSearch )
- (BOOL)containsString:(NSString *)substring{NSRange range = [self rangeOfString : substring];BOOL found = ( range.location != NSNotFound );return found;}
@end

注意：观察下面Daniel Galasko关于命名的评论

NSString *myString = @"hello bla bla";NSRange rangeValue = [myString rangeOfString:@"hello" options:NSCaseInsensitiveSearch];
if (rangeValue.length > 0){NSLog(@"string contains hello");}else{NSLog(@"string does not contain hello!");}

//您也可以使用以下选项：

if (rangeValue.location == NSNotFound){NSLog(@"string does not contain hello");}else{NSLog(@"string contains hello!");}

Oneliner（代码量较小。DRY，因为你只有一个NSLog）：

NSString *string = @"hello bla bla";NSLog(@"String %@", ([string rangeOfString:@"bla"].location == NSNotFound) ? @"not found" : @"cotains bla");

P i的解的改进版本，NSString上的一个类别，它不仅会告诉，如果在另一个字符串中找到一个字符串，而且还通过引用获取一个范围，是：

@interface NSString (Contains)-(BOOL)containsString: (NSString*)substringatRange:(NSRange*)range;
-(BOOL)containsString:(NSString *)substring;@end
@implementation NSString (Contains)
-(BOOL)containsString:(NSString *)substringatRange:(NSRange *)range{
NSRange r = [self rangeOfString : substring];BOOL found = ( r.location != NSNotFound );if (range != NULL) *range = r;return found;}
-(BOOL)containsString:(NSString *)substring{return [self containsString:substringatRange:NULL];}
@end

像这样使用它：

NSString *string = @"Hello, World!";
//If you only want to ensure a string contains a certain substringif ([string containsString:@"ello" atRange:NULL]) {NSLog(@"YES");}
// Or simplyif ([string containsString:@"ello"]) {NSLog(@"YES");}
//If you also want to know substring's rangeNSRange range;if ([string containsString:@"ello" atRange:&range]) {NSLog(@"%@", NSStringFromRange(range));}

这是一个复制粘贴函数片段：

-(BOOL)Contains:(NSString *)StrSearchTerm on:(NSString *)StrText{return [StrText rangeOfString:StrSearchTermoptions:NSCaseInsensitiveSearch].location != NSNotFound;}

由于这似乎是Google的高排名结果，我想补充一下：

iOS8和OS X 10.10将#0方法添加到NSString。Dave DeLong针对这些系统的示例的更新版本：

NSString *string = @"hello bla bla";if ([string containsString:@"bla"]) {NSLog(@"string contains bla!");} else {NSLog(@"string does not contain bla");}

对于iOS8和Swift，我们可以使用localizedCaseInsensitiveContainsString方法

 let string: NSString = "Café"let substring: NSString = "É"
string.localizedCaseInsensitiveContainsString(substring) // true

如果你需要这一次写：

NSString *stringToSearchThrough = @"-rangeOfString method finds and returns the range of the first occurrence of a given string within the receiver.";BOOL contains = [stringToSearchThrough rangeOfString:@"occurence of a given string"].location != NSNotFound;

如果不关心区分大小写的字符串。就这一次

NSString *string  = @"Hello World!";
if([string rangeOfString:@"hello" options:NSCaseInsensitiveSearch].location !=NSNotFound){NSLog(@"found");}else{NSLog(@"not found");}

NSString *categoryString = @"Holiday Event";if([categoryString rangeOfString:@"Holiday"].location == NSNotFound){//categoryString does not contains Holiday}else{//categoryString contains Holiday}

请使用此代码

NSString *string = @"hello bla bla";if ([string rangeOfString:@"bla"].location == NSNotFound){NSLog(@"string does not contain bla");}else{NSLog(@"string contains bla!");}

所以就个人而言，我真的很讨厌NSNotFound，但理解它的必要性。

但是有些人可能不理解与NSNotFint进行比较的复杂性

例如，这段代码：

- (BOOL)doesString:(NSString*)string containString:(NSString*)otherString {if([string rangeOfString:otherString].location != NSNotFound)return YES;elsereturn NO;}

有其问题：

1）显然如果otherString = nil这个代码会崩溃。一个简单的测试是：

NSLog(@"does string contain string - %@", [self doesString:@"hey" containString:nil] ? @"YES": @"NO");

结果！！崩溃！！

2）对于刚接触Objective-c的人来说，不太明显的是，当string = nil时，相同的代码不会崩溃。例如，以下代码：

NSLog(@"does string contain string - %@", [self doesString:nil containString:@"hey"] ? @"YES": @"NO");

和这个代码：

NSLog(@"does string contain string - %@", [self doesString:nil containString:nil] ? @"YES": @"NO");

都将导致

does string contains string - YES

这显然不是你想要的。

所以我认为更好的解决方案是使用rangeOfString返回长度为0的事实，所以更好更可靠的代码是这样的：

- (BOOL)doesString:(NSString*)string containString:(NSString*)otherString {if(otherString && [string rangeOfString:otherString].length)return YES;elsereturn NO;}

或简单：

- (BOOL)doesString:(NSString*)string containString:(NSString*)otherString {return (otherString && [string rangeOfString:otherString].length);}

对于1号和2号案件

does string contains string - NO

那是我的2美分；-）

请查看我的要点以获取更多有用的代码。

试试这个，

NSString *string = @"test Data";if ([[string lowercaseString] rangeOfString:@"data"].location == NSNotFound){NSLog(@"string does not contain Data");}else{NSLog(@"string contains data!");}

在Swift的情况下，这可以用来

let string = "Package #23"if string.containsString("Package #") {//String contains substring}else {//String does not contain substring}

最佳解决方案。就这么简单！如果你想找到一个词或字符串的一部分。您可以使用此代码。在此示例中，我们将检查word的值是否包含“acter”。

NSString *word =@"find a word or character here";if ([word containsString:@"acter"]){NSLog(@"It contains acter");} else {NSLog (@"It does not contain acter");}

在Swift 4中：

let a = "Hello, how are you?"a.contains("Hello")   //will return true

第一个字符串包含或不包含第二个字符串，

NSString *first = @"Banana";NSString *second = @"BananaMilk";NSRange range = [first rangeOfString:second options:NSCaseInsensitiveSearch];
if (range.length > 0) {NSLog(@"Detected");}else {NSLog(@"Not detected");}

使用带有rangeOfString的选项NSCaseInSentiveSearch：选项：

NSString *me = @"toBe" ;NSString *target = @"abcdetobe" ;NSRange range = [target  rangeOfString: me options: NSCaseInsensitiveSearch];NSLog(@"found: %@", (range.location != NSNotFound) ? @"Yes" : @"No");if (range.location != NSNotFound) {// your code}

找到输出结果：是

这些选项可以一起“或”，包括：

NS不区分大小写搜索国家搜索算法搜索和更多

Swift 4及以上

let str = "Hello iam midhun"
if str.contains("iam") {//contains substring}else {//doesn't contain substring}

Objective-c

NSString *stringData = @"Hello iam midhun";
if ([stringData containsString:@"iam"]) {//contains substring}else {//doesn't contain substring}

试试这个：

Swift 4.1、4.2：

let stringData = "Black board"
//swift quick way and case sensitiveif stringData.contains("bla") {print("data contains string");}
//case sensitiveif stringData.range(of: "bla",options: .caseInsensitive) != nil {print("data contains string");}else {print("data does not contains string");}

对于Objective-C：

NSString *stringData = @"Black board";
//Quick way and case sensitiveif ([stringData containsString:@"bla"]) {NSLog(@"data contains string");}
//Case Insensitiveif ([stringData rangeOfString:@"bla" options:NSCaseInsensitiveSearch].location != NSNotFound) {NSLog(@"data contains string");}else {NSLog(@"data does not contain string");}