是否存在无重复 List 实现？

Why not encapsulate a set with a list, sort like:

new ArrayList( new LinkedHashSet() )

This leaves the other implementation for someone who is a real master of Collections ;-)

The documentation for collection interfaces says:

Set — a collection that cannot contain duplicate elements.
List — an ordered collection (sometimes called a sequence). Lists can contain duplicate elements.

So if you don't want duplicates, you probably shouldn't use a list.

There's no Java collection in the standard library to do this. LinkedHashSet<E> preserves ordering similarly to a List, though, so if you wrap your set in a List when you want to use it as a List you'll get the semantics you want.

Alternatively, the Commons Collections (or commons-collections4, for the generic version) has a List which does what you want already: SetUniqueList / SetUniqueList<E>.

Off the top of my head, lists allow duplicates. You could quickly implement a UniqueArrayList and override all the add / insert functions to check for contains() before you call the inherited methods. For personal use, you could only implement the add method you use, and override the others to throw an exception in case future programmers try to use the list in a different manner.

So here's what I did eventually. I hope this helps someone else.

class NoDuplicatesList<E> extends LinkedList<E> {
@Override
public boolean add(E e) {
if (this.contains(e)) {
return false;
}
else {
return super.add(e);
}
}


@Override
public boolean addAll(Collection<? extends E> collection) {
Collection<E> copy = new LinkedList<E>(collection);
copy.removeAll(this);
return super.addAll(copy);
}


@Override
public boolean addAll(int index, Collection<? extends E> collection) {
Collection<E> copy = new LinkedList<E>(collection);
copy.removeAll(this);
return super.addAll(index, copy);
}


@Override
public void add(int index, E element) {
if (this.contains(element)) {
return;
}
else {
super.add(index, element);
}
}
}

You should seriously consider dhiller's answer:

1. Instead of worrying about adding your objects to a duplicate-less List, add them to a Set (any implementation), which will by nature filter out the duplicates.
2. When you need to call the method that requires a List, wrap it in a new ArrayList(set) (or a new LinkedList(set), whatever).

I think that the solution you posted with the NoDuplicatesList has some issues, mostly with the contains() method, plus your class does not handle checking for duplicates in the Collection passed to your addAll() method.

I needed something like that, so I went to the commons collections and used the SetUniqueList, but when I ran some performance test, I found that it seems not optimized comparing to the case if I want to use a Set and obtain an Array using the Set.toArray() method.

The SetUniqueTest took 20:1 time to fill and then traverse 100,000 Strings comparing to the other implementation, which is a big deal difference.

So, if you worry about the performance, I recommend you to use the Set and Get an Array instead of using the SetUniqueList, unless you really need the logic of the SetUniqueList, then you'll need to check other solutions...

Testing code main method:

public static void main(String[] args) {




SetUniqueList pq = SetUniqueList.decorate(new ArrayList());
Set s = new TreeSet();


long t1 = 0L;
long t2 = 0L;
String t;




t1 = System.nanoTime();
for (int i = 0; i < 200000; i++) {
pq.add("a" + Math.random());
}
while (!pq.isEmpty()) {
t = (String) pq.remove(0);
}
t1 = System.nanoTime() - t1;


t2 = System.nanoTime();
for (int i = 0; i < 200000; i++) {
s.add("a" + Math.random());
}


s.clear();
String[] d = (String[]) s.toArray(new String[0]);
s.clear();
for (int i = 0; i < d.length; i++) {
t = d[i];


}
t2 = System.nanoTime() - t2;


System.out.println((double)t1/1000/1000/1000); //seconds
System.out.println((double)t2/1000/1000/1000); //seconds
System.out.println(((double) t1) / t2);        //comparing results

}

Regards, Mohammed Sleem

I just made my own UniqueList in my own little library like this:

package com.bprog.collections;//my own little set of useful utilities and classes


import java.util.HashSet;
import java.util.ArrayList;
import java.util.List;
/**
*
* @author Jonathan
*/
public class UniqueList {


private HashSet masterSet = new HashSet();
private ArrayList growableUniques;
private Object[] returnable;


public UniqueList() {
growableUniques = new ArrayList();
}


public UniqueList(int size) {
growableUniques = new ArrayList(size);
}


public void add(Object thing) {
if (!masterSet.contains(thing)) {
masterSet.add(thing);
growableUniques.add(thing);
}
}


/**
* Casts to an ArrayList of unique values
* @return
*/
public List getList(){
return growableUniques;
}


public Object get(int index) {
return growableUniques.get(index);
}


public Object[] toObjectArray() {
int size = growableUniques.size();
returnable = new Object[size];
for (int i = 0; i < size; i++) {
returnable[i] = growableUniques.get(i);
}
return returnable;
}
}

I have a TestCollections class that looks like this:

package com.bprog.collections;
import com.bprog.out.Out;
/**
*
* @author Jonathan
*/
public class TestCollections {
public static void main(String[] args){
UniqueList ul = new UniqueList();
ul.add("Test");
ul.add("Test");
ul.add("Not a copy");
ul.add("Test");
//should only contain two things
Object[] content = ul.toObjectArray();
Out.pl("Array Content",content);
}
}

Works fine. All it does is it adds to a set if it does not have it already and there's an Arraylist that is returnable, as well as an object array.

in add method, why not using HashSet.add() to check duplicates instead of HashSet.consist(). HashSet.add() will return true if no duplicate and false otherwise.

Here is what I did and it works.

Assuming I have an ArrayList to work with the first thing I did was created a new LinkedHashSet.

LinkedHashSet<E> hashSet = new LinkedHashSet<E>()

Then I attempt to add my new element to the LinkedHashSet. The add method does not alter the LinkedHasSet and returns false if the new element is a duplicate. So this becomes a condition I can test before adding to the ArrayList.

if (hashSet.add(E)) arrayList.add(E);

This is a simple and elegant way to prevent duplicates from being added to an array list. If you want you can encapsulate it in and override of the add method in a class that extends the ArrayList. Just remember to deal with addAll by looping through the elements and calling the add method.

My lastest implementation: https://github.com/marcolopes/dma/blob/master/org.dma.java/src/org/dma/java/util/UniqueArrayList.java

import java.util.ArrayList;
import java.util.Arrays;
import java.util.Collection;
import java.util.LinkedHashSet;


/**
* Extends <tt>ArrayList</tt> and guarantees no duplicate elements
*/
public class UniqueArrayList<T> extends ArrayList<T> {


private static final long serialVersionUID = 1L;


public UniqueArrayList(int initialCapacity) {
super(initialCapacity);
}


public UniqueArrayList() {
super();
}


public UniqueArrayList(T[] array) {
this(Arrays.asList(array));
}


public UniqueArrayList(Collection<? extends T> col) {
addAll(col);
}




@Override
public void add(int index, T e) {
if (!contains(e)) super.add(index, e);
}


@Override
public boolean add(T e) {
return contains(e) ? false : super.add(e);
}


@Override
public boolean addAll(Collection<? extends T> col) {
Collection set=new LinkedHashSet(this);
set.addAll(col);
clear();
return super.addAll(set);
}


@Override
public boolean addAll(int index, Collection<? extends T> col) {
Collection set=new LinkedHashSet(subList(0, index));
set.addAll(col);
set.addAll(subList(index, size()));
clear();
return super.addAll(set);
}


@Override
public T set(int index, T e) {
return contains(e) ? null : super.set(index, e);
}


/** Ensures element.equals(o) */
@Override
public int indexOf(Object o) {
int index=0;
for(T element: this){
if (element.equals(o)) return index;
index++;
}return -1;
}




}

What about this? Just check the list before adding with a contains for an already existing object

while (searchResult != null && searchResult.hasMore()) {
SearchResult nextElement = searchResult.nextElement();
Attributes attributes = nextElement.getAttributes();


String stringName = getAttributeStringValue(attributes, SearchAttribute.*attributeName*);
   

if(!List.contains(stringName)){
List.add(stringName);
}
}