在 PHP JSON 对象中处理数据

来自 JSON Twitter 搜索 API 的趋势数据。

使用以下方法获取文件:

$jsonurl = "http://search.twitter.com/trends.json";
$json = file_get_contents($jsonurl,0,null,null);
$json_output = json_decode($json);

如何处理来自此对象的数据。作为一个数组？只需要从[ name ]值中提取数据即可。

JSON 对象包含:

stdClass Object
(
[trends] => Array
(
[0] => stdClass Object
(
[name] => Vote
[url] => http://search.twitter.com/search?q=Vote
)


[1] => stdClass Object
(
[name] => Halloween
[url] => http://search.twitter.com/search?q=Halloween
)


[2] => stdClass Object
(
[name] => Starbucks
[url] => http://search.twitter.com/search?q=Starbucks
)


[3] => stdClass Object
(
[name] => #flylady
[url] => http://search.twitter.com/search?q=%23flylady
)


[4] => stdClass Object
(
[name] => #votereport
[url] => http://search.twitter.com/search?q=%23votereport
)


[5] => stdClass Object
(
[name] => Election Day
[url] => http://search.twitter.com/search?q=%22Election+Day%22
)


[6] => stdClass Object
(
[name] => #PubCon
[url] => http://search.twitter.com/search?q=%23PubCon
)


[7] => stdClass Object
(
[name] => #defrag08
[url] => http://search.twitter.com/search?q=%23defrag08
)


[8] => stdClass Object
(
[name] => Melbourne Cup
[url] => http://search.twitter.com/search?q=%22Melbourne+Cup%22
)


[9] => stdClass Object
(
[name] => Cheney
[url] => http://search.twitter.com/search?q=Cheney
)


)


[as_of] => Mon, 03 Nov 2008 21:49:36 +0000
)

php
json

174922 次浏览

小开

最佳答案

You mean something like this?

<?php


$jsonurl = "http://search.twitter.com/trends.json";
$json = file_get_contents($jsonurl,0,null,null);
$json_output = json_decode($json);


foreach ( $json_output->trends as $trend )
{
echo "{$trend->name}\n";
}

小开

Just use it like it was an object you defined. i.e.

$trends = $json_output->trends;

小开

If you use json_decode($string, true), you will get no objects, but everything as an associative or number indexed array. Way easier to handle, as the stdObject provided by PHP is nothing but a dumb container with public properties, which cannot be extended with your own functionality.

$array = json_decode($string, true);


echo $array['trends'][0]['name'];