将 int 转换为具有零填充(前导零)的 QString

我想“字符串化”一个数字并添加零填充，就像如果数字小于5位，printf("%05d")会添加前导零一样。

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最佳答案

Use this:

QString number = QStringLiteral("%1").arg(yourNumber, 5, 10, QLatin1Char('0'));

5 here corresponds to 5 in printf("%05d"). 10 is the radix, you can put 16 to print the number in hex.

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I was trying this (which does work, but cumbersome). 

QString s;
s.setNum(n,base);
s = s.toUpper();
presision -= s.length();
while(presision>0){
s.prepend('0');
presision--;
}
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Try:

QString s = s.sprintf("%08X",yournumber);

EDIT: According to the docs at http://qt-project.org/doc/qt-4.8/qstring.html#sprintf:

Warning: We do not recommend using QString::sprintf() in new Qt code. Instead, consider using QTextStream or arg(), both of which support Unicode strings seamlessly and are type-safe. Here's an example that uses QTextStream:

QString result;
QTextStream(&result) << "pi = " << 3.14;
// result == "pi = 3.14"

Read the other docs for features missing from this method.

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The Short Example:

int myNumber = 9;


//Arg1: the number
//Arg2: how many 0 you want?
//Arg3: The base (10 - decimal, 16 hexadecimal - if you don't understand, choose 10)
//      It seems like only decimal can support negative numbers.
QString number = QString("%1").arg(myNumber, 2, 10, QChar('0'));


Output will be: 09
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I use a technique since VB 5

QString theStr=QString("0000%1").arg(theNumber).right(4);
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QString QString::rightJustified ( int width, QChar fill = QLatin1Char( ' ' ), bool truncate = false ) const

int myNumber = 99;
QString result;
result = QString::number(myNumber).rightJustified(5, '0');

result is now 00099


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