通过正则表达式进行过滤

有人能给 Google Chrome 开发工具栏提供一个正则表达式过滤器的例子吗?

我特别需要排除。我尝试了很多正则表达式,但是不知怎么它们似乎不起作用:

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Your expression should not contain the forward slashes and /s, these are not needed for crafting a filter.

I believe your regex should finally read:

!(appl)

Depending on what exactly you want to filter. The regex above will filter out all lines without the string "appl" in them.

edit: apparently exclusion is not supported?

It turned out that Google Chrome actually didn't support this until early 2015, see Google Code issue. With newer versions it works great, for example excluding everything that contains banners:

/^(?!.*?banners)/

It's possible -- at least in Chrome 58 Dev. You just need to wrap your regex with forward-slashes: /my-regex-string/

For example, this is one I'm currently using: /^(.(?!fallback font))+$/

It successfully filters out any messages that contain the substring "fallback font".

EDIT

Something else to note is that if you want to use the ^ (caret) symbol to search from the start of the log message, you have to first match the "fileName.js?someUrlParam:lineNumber " part of the string.

That is to say, the regex is matching against not just the log message, but also the stack-entry for the line which made the log.

So this is the regex I use to match all log messages where the actual message starts with "Dog":

/^.+?:[0-9]+ Dog/

The negative or exclusion case is much easier to write and think about when using the DevTool's native syntax. To provide the exclusion logic you need, simply use this:

-/app/ -/some\sother\sregex/

The "-" prior to the regex makes the result negative.