jQuery: Selecting all elements where attribute is greater than a value

I know that to filter an element with an atttribute called attrName which has value attrValue I do:

filter("[attrName='attrValue']")

but looking at the docs http://api.jquery.com/category/selectors/ I can't see an option to select all elements s.t. attrName>attrValue

Will this work

   filter("[attrName>'attrValue']")

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最佳答案

You can do this using the function overload of .filter(), like this:

.filter(function() {
return $(this).attr("attrName") > "someValue";
})

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The solution is jQuery.filter():

$("selector").filter(function() {
return  $(this).attr("my-attr") > 123;
});

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Be careful, if you are playing with integers make sure you are using parseInt().

$("selector").filter(function() {
return parseInt($(this).attr("my-attr")) > 123;
});

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For ES6 arrow function

$("selector").filter((index, el) => {
return parseInt($(el).attr("attrName")) > 123;
});