熊猫数据框在多索引中选择列

我有以下 pd.DataFrame:

Name    0                       1                      ...
Col     A           B           A            B         ...
0       0.409511    -0.537108   -0.355529    0.212134  ...
1       -0.332276   -1.087013    0.083684    0.529002  ...
2       1.138159    -0.327212    0.570834    2.337718  ...

它具有具有 names=['Name', 'Col']和分层级别的 MultiIndex 列。Name标签从0到 n，对于每个标签，有两个 A和 B列。

我想再次选择此 DataFrame 的所有 A(或 B)列。

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最佳答案

There is a get_level_values method that you can use in conjunction with boolean indexing to get the the intended result.

In [13]:


df = pd.DataFrame(np.random.random((4,4)))
df.columns = pd.MultiIndex.from_product([[1,2],['A','B']])
print df
1                   2
A         B         A         B
0  0.543980  0.628078  0.756941  0.698824
1  0.633005  0.089604  0.198510  0.783556
2  0.662391  0.541182  0.544060  0.059381
3  0.841242  0.634603  0.815334  0.848120
In [14]:


print df.iloc[:, df.columns.get_level_values(1)=='A']
1         2
A         A
0  0.543980  0.756941
1  0.633005  0.198510
2  0.662391  0.544060
3  0.841242  0.815334

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EDIT* Best way now is to use indexSlice for multi-index selections

idx = pd.IndexSlice
A = df.loc[:,idx[:,'A']]
B = df.loc[:,idx[:,'B']]

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Method 1:

df.xs('A', level='Col', axis=1)

for more refer to http://pandas.pydata.org/pandas-docs/stable/advanced.html#cross-section

Method 2:

df.loc[:, (slice(None), 'A')]

Caveat: this method requires the labels to be sorted. for more refer to http://pandas.pydata.org/pandas-docs/stable/advanced.html#the-need-for-sortedness-with-multiindex