Python 迭代对象属性

如何在 Python 中迭代对象的属性？

我有课:

class Twitt:
def __init__(self):
self.usernames = []
self.names = []
self.tweet = []
self.imageurl = []


def twitter_lookup(self, coordinents, radius):
cheese = []
twitter = Twitter(auth=auth)
coordinents = coordinents + "," + radius
print coordinents
query = twitter.search.tweets(q="", geocode=coordinents, rpp=10)
for result in query["statuses"]:
self.usernames.append(result["user"]["screen_name"])
self.names.append(result['user']["name"])
self.tweet.append(h.unescape(result["text"]))
self.imageurl.append(result['user']["profile_image_url_https"])

现在我可以通过这样做来获得我的信息:

k = Twitt()
k.twitter_lookup("51.5033630,-0.1276250", "1mi")
print k.names

我希望能够做的就是迭代 for 循环中的属性，如下所示:

for item in k:
print item.names

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最佳答案

UPDATED

For python 3, you should use items() instead of iteritems()

PYTHON 2

for attr, value in k.__dict__.iteritems():
print attr, value

PYTHON 3

for attr, value in k.__dict__.items():
print(attr, value)

This will print

'names', [a list with names]
'tweet', [a list with tweet]

小开

Iterate over an objects attributes in python:

class C:
a = 5
b = [1,2,3]
def foobar():
b = "hi"


for attr, value in C.__dict__.iteritems():
print "Attribute: " + str(attr or "")
print "Value: " + str(value or "")

Prints:

python test.py
Attribute: a
Value: 5
Attribute: foobar
Value: <function foobar at 0x7fe74f8bfc08>
Attribute: __module__
Value: __main__
Attribute: b
Value: [1, 2, 3]
Attribute: __doc__
Value:

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You can use the standard Python idiom, vars():

for attr, value in vars(k).items():
print(attr, '=', value)