如何使用 Django 获取当前的 URL 名称?

我必须根据当前的 url 动态地构建一个 url。使用 {% url %}标记是最简单的方法,但是我需要当前的 URL 名称来动态地生成新的 URL 名称。

如何获得链接到当前视图的 urlconf 的 URL 名称?

编辑: 我知道我可以使用 get_absolute_url手工制作网址,但我宁愿避免它,因为它是一个讲座的一部分,我想演示只有一种方法来构建网址。

学生们知道如何使用 {% url %}。当他们必须基于当前的 URL 生成一个更完整的 URL 时,他们知道要面对一个问题。最简单的方法是再次使用 {% url %},但有一些变化。因为我们已经命名了 url,我们需要知道如何获取调用当前视图的 URL 的名称。

编辑2: 另一个用例是根据基本模板以不同的方式显示基本模板的各个部分。还有其他方法可以做到这一点(使用 CSS 和{% block% } ,但是有时候,如果视图名称与链接匹配,那么能够删除 base.html 菜单条目的标记就很好了。

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It's a little unclear from your question, but http://docs.djangoproject.com/en/dev/topics/http/urls/ will likely provide an explanation to what you're after.

Especially useful to note how Django processes requests:

When a user requests a page from your Django-powered site, this is the algorithm the system follows to determine which Python code to execute:

  1. Django determines the root URLconf module to use. Ordinarily, this is the value of the ROOT_URLCONF setting, but if the incoming HttpRequest object has an attribute called urlconf (set by middleware request processing), its value will be used in place of the ROOT_URLCONF setting.
  2. Django loads that Python module and looks for the variable urlpatterns. This should be a Python list, in the format returned by the function django.conf.urls.defaults.patterns().
  3. Django runs through each URL pattern, in order, and stops at the first one that matches the requested URL.
  4. Once one of the regexes matches, Django imports and calls the given view, which is a simple Python function. The view gets passed an HttpRequest as its first argument and any values captured in the regex as remaining arguments.

If you're just after the full path, you can try:

http://docs.djangoproject.com/en/dev/ref/request-response/#django.http.HttpRequest.get_full_path

I hope that helps - it indicates how to use the URLconf module, and hopefully will help point you in the right direction.

Clarification of the question: "In a view, how do you get the name of a urlpattern that points to it, assuming there is exactly one such urlpattern."

This may be desirable for the reasons stated: from within the view, we want a DRY way of getting a url to the same view (we don't want to have to know our own urlpattern name).

Short answer: It's not really simple enough to teach your class, but it might be a fun thing for you to do in an hour or two and throw up on GitHub.

If you really wanted to do this, you would have to subclass RegexURLResolver and modify the resolve method to return the matched pattern (from which you can get the pattern name) instead of the view and keyword/value pairs. http://code.djangoproject.com/browser/django/trunk/django/core/urlresolvers.py#L142

You could then create a decorator or perhaps more appropriately middleware that uses this subclass to get the pattern name and store that value somewhere in the request so that views can use it.

If you actually want to do that and you run across some trouble, let me know and I can probably help.

For your class, I would just have them hardcode the pattern name in the view or template. I believe this is the acceptable way of doing it.

Update: The more I think about this, the more I would discourage trying to get a urlpattern name in a view. urlpattern parameters are fairly independent of the parameters of the view they point to. If you want to point to a certain url, you need to know how the urlpattern works, not just how the view works. If you need to know how the urlpattern works, you might as well have to know the name of the urlpattern.

I don't know how long this feature has been part of Django but as the following article shows, it can be achieved as follows in the view:

   from django.core.urlresolvers import resolve
current_url = resolve(request.path_info).url_name

If you need that in every template, writing a template request can be appropriate.

Edit: APPLYING NEW DJANGO UPDATE

Following the current Django update:

Django 1.10 (link)

Importing from the django.core.urlresolvers module is deprecated in favor of its new location, django.urls

Django 2.0 (link)

The django.core.urlresolvers module is removed in favor of its new location, django.urls.

Thus, the right way to do is like this:

from django.urls import resolve
current_url = resolve(request.path_info).url_name

As of Django 1.5, this can be accessed from the request object

current_url = request.resolver_match.url_name

If you would like the url name along with the namespace

current_url = request.resolver_match.view_name

https://docs.djangoproject.com/en/dev/ref/request-response/#django.http.HttpRequest.resolver_match

This can be achieved via:

    request.resolver_match.url_name

Django >1.8

For those who namespace their url patterns, then you may be interested in the namespaced url name of the request. In this case, Django called it view_name instead.

request.resolver_match.view_name


# return: <namespace>:<url name>

Just try request.path. That will get the current path being requested.

To get the absolute URL do like so:

request.build_absolute_uri()

If you want to add something extra at the end of the main ur (not current URL) do as follows:

request.build_absolute_uri("/something/")

If you want to get the only main domain URL do as below:

request.build_absolute_uri("/")