What is the most elegant way to do the next stuff:
int i = oneOrZero; if (i == 0) { i = 1; } else { i = 0; }
You can assume that i can have only 1 or 0 value.
i
subtraction?
i = 1 - i;
i ^= 1;
XOR the value with 1. This gives you both ways (in case you need to flip 0 <--> 1 either way):
0 <--> 1
0 ^ 1 = 1 1 ^ 1 = 0
i = (i == 0)?1:0 is one way, though I like @Jimmy's and @Yuval's versions better.
i = (i == 0)?1:0
Use Bitwise XOR operator:
i = ( i + 1 ) % 2, though I think we all agree the subtraction or xor method is better! (Though it has the added benefit of "flipping the switch" for more than binary.)
i = ( i + 1 ) % 2
int x = 0; x=(int)Math.cos(x); System.out.println("X value "+x);