获取所有相关的 Django 模型对象

如何获得所有模型对象的列表,这些模型对象都有一个 ForeignKey 指向一个对象?(类似于 DELETE CASCADE 之前 Django 管理员中的删除确认页面)。

我正在尝试提出一种在数据库中合并重复对象的通用方法。基本上,我希望所有的对象,有 ForeignKeys 指向对象“ B”被更新为指向对象“ A”,这样我就可以删除“ B”而不丢失任何重要的东西。

谢谢你的帮助!

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Give this a try.

class A(models.Model):
def get_foreign_fields(self):
return [getattr(self, f.name) for f in self._meta.fields if type(f) == models.fields.related.ForeignKey]

Django <= 1.7

This gives you the property names for all related objects:

links = [rel.get_accessor_name() for rel in a._meta.get_all_related_objects()]

You can then use something like this to get all related objects:

for link in links:
objects = getattr(a, link).all()
for object in objects:
# do something with related object instance

I spent a while trying to figure this out so I could implement a kind of "Observer Pattern" on one of my models. Hope it's helpful.

Django 1.8+

Use _meta.get_fields(): https://docs.djangoproject.com/en/1.10/ref/models/meta/#django.db.models.options.Options.get_fields (see reverse in the _get_fields() source also)

for link in links:
objects = getattr(a, link).all()

Works for related sets, but not for ForeignKeys. Since RelatedManagers are created dynamically, looking at the class name is easier than doing an isinstance()

objOrMgr = getattr(a, link)
if objOrMgr.__class__.__name__ ==  'RelatedManager':
objects = objOrMgr.all()
else:
objects = [ objOrMgr ]
for object in objects:
# Do Stuff

The following is what django uses to get all related objects

from django.db.models.deletion import Collector
collector = Collector(using="default")
collector.collect([a])


print collector.data

@digitalPBK was close... here is probably what you are looking for using Django's built-in stuff that is used in Django admin for displaying related objects during deletion

from django.contrib.admin.utils import NestedObjects
collector = NestedObjects(using="default") #database name
collector.collect([objective]) #list of objects. single one won't do
print(collector.data)

this allows you to create what the Django admin displays - the related objects to be deleted.

Here is another way to get a list of fields (names only) in related models.

def get_related_model_fields(model):
fields=[]
related_models = model._meta.get_all_related_objects()
for r in related_models:
fields.extend(r.opts.get_all_field_names())
return fields

Django 1.9
get_all_related_objects() has been deprecated

#Example:
user = User.objects.get(id=1)
print(user._meta.get_fields())

Note: RemovedInDjango110Warning: 'get_all_related_objects is an unofficial API that has been deprecated. You may be able to replace it with 'get_fields()'

Unfortunately, user._meta.get_fields() returns only relations accessible from user, however, you may have some related object, which uses related_name='+'. In such case, the relation would not be returned by user._meta.get_fields(). Therefore, if You need generic and robust way to merge objects, I'd suggest to use the Collector mentioned above.

links = [rel.get_accessor_name() for rel in a._meta.get_all_related_objects()]

You can then use something like this to get all related objects:

for link in links:
objects = getattr(a, link.name).all()
for object in objects:
# do something with related object instance

From Django 1.10 offical docs:

MyModel._meta.get_all_related_objects() becomes:

[
f for f in MyModel._meta.get_fields()
if (f.one_to_many or f.one_to_one)
and f.auto_created and not f.concrete
]

So by taking the approved example we would use:

links = [
f for f in MyModel._meta.get_fields()
if (f.one_to_many or f.one_to_one)
and f.auto_created and not f.concrete
]


for link in links:
objects = getattr(a, link.name).all()
for object in objects:
# do something with related object instance