使用 jQuery 获取鼠标点击图像的 X/Y 坐标

You can use ABC0 and pageY to get the position of the mouse in the window. You can also use jQuery's offset to get the position of an element.

So, it should be pageX - offset.left for how far from the left of the image and pageY - offset.top for how far from the top of the image.

Here is an example:

$(document).ready(function() {
$('img').click(function(e) {
var offset = $(this).offset();
alert(e.pageX - offset.left);
alert(e.pageY - offset.top);
});
});

I've made a live example here and here is the source.

To calculate how far from the bottom or right, you would have to use jQuery's width and height methods.

note! there is a difference between e.clientX & e.clientY and e.pageX and e.pageY

try them both out and make sure you are using the proper one. clientX and clientY change based on scrolling position

Take a look at http://jsfiddle.net/TroyAlford/ZZEk8/ for a working example of the below:

<img id='myImg' src='/my/img/link.gif' />


<script type="text/javascript">
$(document).bind('click', function () {
// Add a click-handler to the image.
$('#myImg').bind('click', function (ev) {
var $img = $(ev.target);


var offset = $img.offset();
var x = ev.clientX - offset.left;
var y = ev.clientY - offset.top;


alert('clicked at x: ' + x + ', y: ' + y);
});
});
</script>

Note that the above will get you the x and the y relative to the image's box - but will not correctly take into account margin, border and padding. These elements aren't actually part of the image, in your case - but they might be part of the element that you would want to take into account.

In this case, you should also use $div.outerWidth(true) - $div.width() and $div.outerHeight(true) - $div.height() to calculate the amount of margin / border / etc.

Your new code might look more like:

<img id='myImg' src='/my/img/link.gif' />


<script type="text/javascript">
$(document).bind('click', function () {
// Add a click-handler to the image.
$('#myImg').bind('click', function (ev) {
var $img = $(ev.target);


var offset = $img.offset(); // Offset from the corner of the page.
var xMargin = ($img.outerWidth() - $img.width()) / 2;
var yMargin = ($img.outerHeight() - $img.height()) / 2;
// Note that the above calculations assume your left margin is
// equal to your right margin, top to bottom, etc. and the same
// for borders.


var x = (ev.clientX + xMargin) - offset.left;
var y = (ev.clientY + yMargin) - offset.top;


alert('clicked at x: ' + x + ', y: ' + y);
});
});
</script>

Here is a better script:

$('#mainimage').click(function(e)
{
var offset_t = $(this).offset().top - $(window).scrollTop();
var offset_l = $(this).offset().left - $(window).scrollLeft();


var left = Math.round( (e.clientX - offset_l) );
var top = Math.round( (e.clientY - offset_t) );


alert("Left: " + left + " Top: " + top);


});

The below code works always even if any image makes the window scroll.

$(function() {
$("#demo-box").click(function(e) {


var offset = $(this).offset();
var relativeX = (e.pageX - offset.left);
var relativeY = (e.pageY - offset.top);


alert("X: " + relativeX + "  Y: " + relativeY);


});
});

Ref: http://css-tricks.com/snippets/jquery/get-x-y-mouse-coordinates/