Regex pattern inside SQL Replace function?

SELECT REPLACE('<strong>100</strong><b>.00 GB', '%^(^-?\d*\.{0,1}\d+$)%', '');

I want to replace any markup between two parts of the number with above regex, but it does not seem to work. I'm not sure if it is regex syntax that's wrong because I tried simpler one such as '%[^0-9]%' just to test but it didn't work either. Does anyone know how can I achieve this?

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小开

In a general sense, SQL Server does not support regular expressions and you cannot use them in the native T-SQL code.

You could write a CLR function to do that. See here, for example.

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最佳答案

You can use PATINDEX to find the first index of the pattern (string's) occurrence. Then use STUFF to stuff another string into the pattern(string) matched.

Loop through each row. Replace each illegal characters with what you want. In your case replace non numeric with blank. The inner loop is if you have more than one illegal character in a current cell that of the loop.

DECLARE @counter int


SET @counter = 0


WHILE(@counter < (SELECT MAX(ID_COLUMN) FROM Table))
BEGIN


WHILE 1 = 1
BEGIN
DECLARE @RetVal varchar(50)


SET @RetVal =  (SELECT Column = STUFF(Column, PATINDEX('%[^0-9.]%', Column),1, '')
FROM Table
WHERE ID_COLUMN = @counter)


IF(@RetVal IS NOT NULL)
UPDATE Table SET
Column = @RetVal
WHERE ID_COLUMN = @counter
ELSE
break
END


SET @counter = @counter + 1
END

Caution: This is slow though! Having a varchar column may impact. So using LTRIM RTRIM may help a bit. Regardless, it is slow.

Credit goes to this StackOverFlow answer.

EDIT Credit also goes to @srutzky

Edit (by @Tmdean) Instead of doing one row at a time, this answer can be adapted to a more set-based solution. It still iterates the max of the number of non-numeric characters in a single row, so it's not ideal, but I think it should be acceptable in most situations.

WHILE 1 = 1 BEGIN
WITH q AS
(SELECT ID_Column, PATINDEX('%[^0-9.]%', Column) AS n
FROM Table)
UPDATE Table
SET Column = STUFF(Column, q.n, 1, '')
FROM q
WHERE Table.ID_Column = q.ID_Column AND q.n != 0;


IF @@ROWCOUNT = 0 BREAK;
END;

You can also improve efficiency quite a lot if you maintain a bit column in the table that indicates whether the field has been scrubbed yet. (NULL represents "Unknown" in my example and should be the column default.)

DECLARE @done bit = 0;
WHILE @done = 0 BEGIN
WITH q AS
(SELECT ID_Column, PATINDEX('%[^0-9.]%', Column) AS n
FROM Table
WHERE COALESCE(Scrubbed_Column, 0) = 0)
UPDATE Table
SET Column = STUFF(Column, q.n, 1, ''),
Scrubbed_Column = 0
FROM q
WHERE Table.ID_Column = q.ID_Column AND q.n != 0;


IF @@ROWCOUNT = 0 SET @done = 1;


-- if Scrubbed_Column is still NULL, then the PATINDEX
-- must have given 0
UPDATE table
SET Scrubbed_Column = CASE
WHEN Scrubbed_Column IS NULL THEN 1
ELSE NULLIF(Scrubbed_Column, 0)
END;
END;

If you don't want to change your schema, this is easy to adapt to store intermediate results in a table valued variable which gets applied to the actual table at the end.

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Instead of stripping out the found character by its sole position, using Replace(Column, BadFoundCharacter, '') could be substantially faster. Additionally, instead of just replacing the one bad character found next in each column, this replaces all those found.

WHILE 1 = 1 BEGIN
UPDATE dbo.YourTable
SET Column = Replace(Column, Substring(Column, PatIndex('%[^0-9.-]%', Column), 1), '')
WHERE Column LIKE '%[^0-9.-]%'
If @@RowCount = 0 BREAK;
END;

I am convinced this will work better than the accepted answer, if only because it does fewer operations. There are other ways that might also be faster, but I don't have time to explore those right now.

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Wrapping the solution inside a SQL function could be useful if you want to reuse it. I'm even doing it at the cell level, that's why I'm putting this as a different answer:

CREATE FUNCTION [dbo].[fnReplaceInvalidChars] (@string VARCHAR(300))
RETURNS VARCHAR(300)
BEGIN
DECLARE @str VARCHAR(300) = @string;
DECLARE @Pattern VARCHAR (20) = '%[^a-zA-Z0-9]%';
DECLARE @Len INT;
SELECT @Len = LEN(@String);
WHILE @Len > 0
BEGIN
SET @Len = @Len - 1;
IF (PATINDEX(@Pattern,@str) > 0)
BEGIN
SELECT @str = STUFF(@str, PATINDEX(@Pattern,@str),1,'');
END
ELSE
BEGIN
BREAK;
END
END
RETURN @str
END

A more speedy approach for large strings would look something like this:

CREATE FUNCTION [dbo].[fnReplaceInvalidChars] (@string VARCHAR(MAX))
RETURNS VARCHAR(MAX)
BEGIN
DECLARE @str VARCHAR(MAX) = @string;
DECLARE @Pattern VARCHAR (MAX) = '%[^a-zA-Z0-9]%';
WHILE PATINDEX(@Pattern,@str) > 0
BEGIN
SELECT @str = STUFF(@str, PATINDEX(@Pattern,@str),1,'');
END
RETURN @str
END
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If you are doing this just for a parameter coming into a Stored Procedure, you can use the following:

declare @badIndex int
set @badIndex = PatIndex('%[^0-9]%', @Param)
while @badIndex > 0
set @Param = Replace(@Param, Substring(@Param, @badIndex, 1), '')
set @badIndex = PatIndex('%[^0-9]%', @Param)
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Here is a function I wrote to accomplish this based off of the previous answers.

CREATE FUNCTION dbo.RepetitiveReplace
(
@P_String VARCHAR(MAX),
@P_Pattern VARCHAR(MAX),
@P_ReplaceString VARCHAR(MAX),
@P_ReplaceLength INT = 1
)
RETURNS VARCHAR(MAX)
BEGIN
DECLARE @Index INT;


-- Get starting point of pattern
SET @Index = PATINDEX(@P_Pattern, @P_String);


while @Index > 0
begin
--replace matching charactger at index
SET @P_String = STUFF(@P_String, PATINDEX(@P_Pattern, @P_String), @P_ReplaceLength, @P_ReplaceString);
SET @Index = PATINDEX(@P_Pattern, @P_String);
end


RETURN @P_String;
END;

[Gist][1] [1]: https://gist.github.com/jkdba/ca13fe8f2a9855c4bdbfd0a5d3dfcda2

Edit:

Originally I had a recursive function here which does not play well with sql server as it has a 32 nesting level limit which would result in an error like the below any time you attempt to make 32+ replacements with the function. Instead of trying to make a server level change to allow more nesting (which could be dangerous like allow never ending loops) switching to a while loop makes a lot more sense.

Maximum stored procedure, function, trigger, or view nesting level exceeded (limit 32).

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I stumbled across this post looking for something else but thought I'd mention a solution I use which is far more efficient - and really should be the default implementation of any function when used with a set based query - which is to use a cross applied table function. Seems the topic is still active so hopefully this is useful to someone.

Example runtime on a few of the answers so far based on running recursive set based queries or scalar function, based on 1m rows test set removing the chars from a random newid, ranges from 34s to 2m05s for the WHILE loop examples and from 1m3s to {forever} for the function examples.

Using a table function with cross apply achieves the same goal in 10s. You may need to adjust it to suit your needs such as the max length it handles.

Function:

CREATE FUNCTION [dbo].[RemoveChars](@InputUnit VARCHAR(40))
RETURNS TABLE
AS
RETURN
(
WITH Numbers_prep(Number) AS
(
SELECT 1 UNION ALL SELECT 1 UNION ALL SELECT 1 UNION ALL SELECT 1 UNION ALL SELECT 1 UNION ALL SELECT 1 UNION ALL SELECT 1
)
,Numbers(Number) AS
(
SELECT TOP (ISNULL(LEN(@InputUnit),0))
row_number() OVER (ORDER BY (SELECT NULL))
FROM Numbers_prep a
CROSS JOIN Numbers_prep b
)
SELECT
OutputUnit
FROM
(
SELECT
substring(@InputUnit,Number,1)
FROM  Numbers
WHERE substring(@InputUnit,Number,1) like '%[0-9]%'
ORDER BY Number
FOR XML PATH('')
) Sub(OutputUnit)
)

Usage:

UPDATE t
SET column = o.OutputUnit
FROM ##t t
CROSS APPLY [dbo].[RemoveChars](t.column) o
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I think a simpler and faster approach is iterate by each character of the alphabet:

DECLARE @i int
SET @i = 0


WHILE(@i < 256)
BEGIN


IF char(@i) NOT IN ('0', '1', '2', '3', '4', '5', '6', '7', '8', '9', '.')


UPDATE Table SET Column = replace(Column, char(@i), '')


SET @i = @i + 1


END
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I've created this function to clean up a string that contained non numeric characters in a time field. The time contained question marks when they did not added the minutes, something like this 20:??. Function loops through each character and replaces the ? with a 0 :

 CREATE FUNCTION [dbo].[CleanTime]
(
-- Add the parameters for the function here
@intime nvarchar(10)
)
RETURNS nvarchar(5)
AS
BEGIN
-- Declare the return variable here
DECLARE @ResultVar nvarchar(5)
DECLARE @char char(1)
-- Add the T-SQL statements to compute the return value here
DECLARE @i int = 1
WHILE @i <= LEN(@intime)
BEGIN
SELECT @char =  CASE WHEN substring(@intime,@i,1) like '%[0-9:]%' THEN substring(@intime,@i,1) ELSE '0' END
SELECT @ResultVar = concat(@ResultVar,@char)
set @i  = @i + 1
END;
-- Return the result of the function
RETURN @ResultVar


END
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For those looking for a performant and easy solution and are willing to enable CLR:

CREATE database TestSQLFunctions
go
use TestSQLFunctions
go
ALTER database TestSQLFunctions set trustworthy on


EXEC sp_configure 'clr enabled', 1
RECONFIGURE WITH OVERRIDE
go


CREATE ASSEMBLY [SQLFunctions]
AUTHORIZATION [dbo]
FROM 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
0000001E01000100540216577261704E6F6E457863657074696F6E5468726F7773010801000200000000001101000C53514C46756E6374696F6E73000005010000000017010012436F7079726967687420C2A920203230323000002901002434346436386231632D393735312D343938612D396665352D32316666333934303738303900000C010007312E302E302E3000004D01001C2E4E45544672616D65776F726B2C56657273696F6E3D76342E352E320100540E144672616D65776F726B446973706C61794E616D65142E4E4554204672616D65776F726B20342E352E32808F010001005455794D6963726F736F66742E53716C5365727665722E5365727665722E446174614163636573734B696E642C2053797374656D2E446174612C2056657273696F6E3D342E302E302E302C2043756C747572653D6E65757472616C2C205075626C69634B6579546F6B656E3D623737613563353631393334653038390A4461746141636365737301000000000000982700000000000000000000B2270000002000000000000000000000000000000000000000000000A4270000000000000000000000005F436F72446C6C4D61696E006D73636F7265652E646C6C0000000000FF25002000100000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000001001000000018000080000000000000000000000000000001000100000030000080000000000000000000000000000001000000000048000000584000003C03000000000000000000003C0334000000560053005F00560045005200530049004F004E005F0049004E0046004F0000000000BD04EFFE00000100000001000000000000000100000000003F000000000000000400000002000000000000000000000000000000440000000100560061007200460069006C00650049006E0066006F00000000002400040000005400720061006E0073006C006100740069006F006E00000000000000B0049C020000010053007400720069006E006700460069006C00650049006E0066006F0000007802000001003000300030003000300034006200300000001A000100010043006F006D006D0065006E007400730000000000000022000100010043006F006D00700061006E0079004E0061006D006500000000000000000042000D000100460069006C0065004400650073006300720069007000740069006F006E0000000000530051004C00460075006E006300740069006F006E00730000000000300008000100460069006C006500560065007200730069006F006E000000000031002E0030002E0030002E003000000042001100010049006E007400650072006E0061006C004E0061006D0065000000530051004C00460075006E006300740069006F006E0073002E0064006C006C00000000004800120001004C006500670061006C0043006F007000790072006900670068007400000043006F0070007900720069006700680074002000A90020002000320030003200300000002A00010001004C006500670061006C00540072006100640065006D00610072006B00730000000000000000004A00110001004F0072006900670069006E0061006C00460069006C0065006E0061006D0065000000530051004C00460075006E006300740069006F006E0073002E0064006C006C00000000003A000D000100500072006F0064007500630074004E0061006D00650000000000530051004C00460075006E006300740069006F006E00730000000000340008000100500072006F006400750063007400560065007200730069006F006E00000031002E0030002E0030002E003000000038000800010041007300730065006D0062006C0079002000560065007200730069006F006E00000031002E0030002E0030002E0030000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000002000000C000000C43700000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000
000000000
WITH PERMISSION_SET = SAFE


go


CREATE FUNCTION RegexReplace(
@input nvarchar(max),
@pattern nvarchar(max),
@replacement nvarchar(max)
) RETURNS nvarchar  (max)
AS EXTERNAL NAME SQLFunctions.[SQLFunctions.Regex].Replace;


go


-- outputs This is a test
SELECT dbo.RegexReplace('This is a test 12345','[0-9]','')

Content of the DLL: enter image description here

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I think this solution is faster and simple. I use always CTE/recursive because WHILE is so slow on SQL Server. I use it in projects I work with and large databases.

/*
Function:           dbo.kSql_ReplaceRegExp
Create Date:        20.02.2021
Author:             Karcan Ozbal


Description:        The given string value will be replaced according to the given regexp/pattern.


Parameter(s):       @Value       : Value/Text to REPLACE.
@RegExp      : The regexp/pattern to be used for REPLACE operation.


Usage:              select dbo.kSql_ReplaceRegExp('2T3EST5','%[0-9]%')
Output:             'TEST'
*/
ALTER FUNCTION [dbo].[kSql_ReplaceRegExp](
@Value nvarchar(max),
@RegExp nvarchar(50)
)
RETURNS nvarchar(max)
AS
BEGIN
DECLARE @Result nvarchar(max)


;WITH CTE AS (
SELECT NUM = 1, VALUE = @Value, IDX = PATINDEX(@RegExp, @Value)
UNION ALL
SELECT NUM + 1, VALUE = REPLACE(VALUE, SUBSTRING(VALUE,IDX,1),''), IDX = PATINDEX(@RegExp, REPLACE(VALUE, SUBSTRING(VALUE,IDX,1),''))
FROM CTE
WHERE IDX > 0
)
SELECT TOP(1) @Result = VALUE
FROM CTE
ORDER BY NUM DESC
OPTION (maxrecursion 0)


RETURN @Result
END
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I thought this was clearer:

ALTER FUNCTION [dbo].[func_ReplaceChars](
@Value nvarchar(max),
@Chars nvarchar(50)
)
RETURNS nvarchar(max)
AS
BEGIN
DECLARE @cLen int = len(@Chars);
DECLARE @curChar int = 0;


WHILE @curChar<@cLen
BEGIN
set @Value = replace(@Value,substring(@Chars,@curChar,1),'');


set @curChar = @curChar + 1;
END;


RETURN @Value
END
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Please vote to have a function added to SQL Server https://feedback.azure.com/d365community/idea/d44017f4-8adb-ec11-a81b-0022484ee92d


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