如何在 python 中创建加密安全的随机数？

我在 Python 中做了一个项目，我想创建一个随机数，是加密安全的，我如何做到这一点？我在网上读到，常规随机发生器生成的数字在加密上并不安全，函数 os.urandom(n)返回给我的是字符串，而不是数字。

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最佳答案

You can get a list of random numbers by just applying ord function over the bytes returned by os.urandom, like this

>>> import os
>>> os.urandom(10)
'm\xd4\x94\x00x7\xbe\x04\xa2R'
>>> type(os.urandom(10))
<type 'str'>
>>> map(ord, os.urandom(10))
[65, 120, 218, 135, 66, 134, 141, 140, 178, 25]

Quoting os.urandom documentation,

Return a string of n random bytes suitable for cryptographic use.

This function returns random bytes from an OS-specific randomness source. The returned data should be unpredictable enough for cryptographic applications, though its exact quality depends on the OS implementation. On a UNIX-like system this will query /dev/urandom, and on Windows it will use CryptGenRandom().

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Since you want to generate integers in some specific range, it's a lot easier to use the random.SystemRandom class instead. Creating an instance of that class gives you an object that supports all the methods of the random module, but using os.urandom() under the covers. Examples:

>>> from random import SystemRandom
>>> cryptogen = SystemRandom()
>>> [cryptogen.randrange(3) for i in range(20)] # random ints in range(3)
[2, 2, 2, 2, 1, 2, 1, 2, 1, 0, 0, 1, 1, 0, 0, 2, 0, 0, 0, 0]
>>> [cryptogen.random() for i in range(3)]  # random floats in [0., 1.)
[0.2710009745425236, 0.016722063038868695, 0.8207742461236148]

Etc. Using urandom() directly, you have to invent your own algorithms for converting the random bytes it produces to the results you want. Don't do that ;-) SystemRandom does it for you.

Note this part of the docs:

class random.SystemRandom([seed])

Class that uses the os.urandom() function for generating random numbers from sources provided by the operating system. Not available on all systems. Does not rely on software state and sequences are not reproducible. Accordingly, the seed() and jumpahead() methods have no effect and are ignored. The getstate() and setstate() methods raise NotImplementedError if called.

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If you want an n-bit random number, under Python 2.4+, the easiest method I've found is

import random
random.SystemRandom().getrandbits(n)

Note that SystemRandom uses os.urandom(), so the result of this method is only as good as your system's urandom() implementation.

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Python 3.6 introduces a new secrets module, which "provides access to the most secure source of randomness that your operating system provides." In order to generate some cryptographically secure numbers, you can call secrets.randbelow().

secrets.randbelow(n)

which will return a number between 0 and n.

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To generate a cryptographically secure pseudorandom integer, you can use the following code:

int(binascii.hexlify(os.urandom(n)),16)

Where n is an integer and, the larger n is, the larger the integer generated is.

You will have to import os and binascii first.

The result of this code can vary by platform.


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