更现代的 C + + 数组循环方式

In C/C++ sizeof. always gives the number of bytes in the entire object, and arrays are treated as one object. Note: sizeof a pointer--to the first element of an array or to a single object--gives the size of the pointer, not the object(s) pointed to. Either way, sizeof does not give the number of elements in the array (its length). To get the length, you need to divide by the size of each element. eg.,

for( unsigned int a = 0; a < sizeof(texts)/sizeof(texts[0]); a = a + 1 )

As for doing it the C++11 way, the best way to do it is probably

for(const string &text : texts)
cout << "value of text: " << text << endl;

This lets the compiler figure out how many iterations you need.

as others have pointed out, std::array is preferred in C++11 over raw arrays; however, none of the other answers addressed why sizeof is failing the way it is, so I still think this is the better answer.

sizeof tells you the size of a thing, not the number of elements in it. A more C++11 way to do what you are doing would be:

#include <array>
#include <string>
#include <iostream>


int main()
{
std::array<std::string, 3> texts { "Apple", "Banana", "Orange" };
for (auto& text : texts) {
std::cout << text << '\n';
}
return 0;
}

ideone demo: http://ideone.com/6xmSrn

string texts[] = {"Apple", "Banana", "Orange"};
for( unsigned int a = 0; a < sizeof(texts); a = a + 1 )
{
cout << "value of a: " << texts[a] << endl;
}

Nope. Totally a wrong way of iterating through an array. sizeof(texts) is not equal to the number of elements in the array!

The modern, C++11 ways would be to:

• use std::array if you want an array whose size is known at compile-time; or
• use std::vector if its size depends on runtime

Then use range-for when iterating.

#include <iostream>
#include <array>




int main() {
std::array<std::string, 3> texts = {"Apple", "Banana", "Orange"};
// ^ An array of 3 elements with the type std::string


for(const auto& text : texts) {   // Range-for!
std::cout << text << std::endl;
}
}

Live example

You may ask, how is std::array better than the ol' C array? The answer is that it has the additional safety and features of other standard library containers, mostly closely resembling std::vector. Further, The answer is that it doesn't have the quirks of decaying to pointers and thus losing type information, which, once you lose the original array type, you can't use range-for or std::begin/end on it.

sizeof(texts) on my system evaluated to 96: the number of bytes required for the array and its string instances.

As mentioned elsewhere, the sizeof(texts)/sizeof(texts[0]) would give the value of 3 you were expecting.

Add a stopping value to the array:

#include <iostream>
using namespace std;


int main ()
{
string texts[] = {"Apple", "Banana", "Orange", ""};
for( unsigned int a = 0; texts[a].length(); a = a + 1 )
{
cout << "value of a: " << texts[a] << endl;
}


return 0;
}

If you have a very short list of elements you would like to handle, you could use the std::initializer_list introduced in C++11 together with auto:

#include <iostream>


int main(int, char*[])
{
for(const auto& ext : { ".slice", ".socket", ".service", ".target" })
std::cout << "Handling *" << ext << " systemd files" << std::endl;


return 0;
}

How about:

#include <iostream>
#include <array>
#include <algorithm>


int main ()
{
std::array<std::string, 3> text = {"Apple", "Banana", "Orange"};
std::for_each(text.begin(), text.end(), [](std::string &string){ std::cout << string << "\n"; });


return 0;
}

Compiles and works with C++ 11 and has no 'raw' looping :)

you need to understand difference between std::array::size and sizeof() operator. if you want loop to array elements in conventional way then you could use std::array::size. this will return number of elements in array but if you keen to use C++11 then prefer below code

for(const string &text : texts)
cout << "value of text: " << text << endl;

You can do it as follow:

#include < iostream >


using namespace std;


int main () {


string texts[] = {"Apple", "Banana", "Orange"};


for( unsigned int a = 0; a < sizeof(texts) / 32; a++ ) { // 32 is the size of string data type


cout << "value of a: " << texts[a] << endl;


}




return 0;


}

Feels like illegal but this works:

So basically it is dynamic multidimensional array iteration termination case and it differs a bit from one dimensional solution, last element is -1 and it is stop value for cycle (I am new to C++ but this method me likes)

int arr[][3] = \{\{164, 0, 0}, {124, 0, 0}, {92, 4, 0}, {68, 4, 0}, -1};


for(int i = 0; arr[i][0]!=-1; i++)
{
cout << i << "\n";
}

In my point of view:
It is because the sizeof() operator returns the size
of a type in bytes.
So, Simply we can use size() instead of sizeof(). If
we need or must use sizeof() we have to divide it
with sizeof(dataType):




First way:
#include <iostream>
using namespace std;


int main ()
{
string texts[] = {"Apple", "Banana", "Orange"};
for(int a = 0; a < size(texts); a++){
cout << "value of a: " << texts[a] << endl;
}


return 0;
}


Second way:
#include <iostream>
using namespace std;


int main ()
{
string texts[] = {"Apple", "Banana", "Orange"};
for(int a=0; a<sizeof(texts)/sizeof(string); a++)
{
cout << "value of a: " << texts[a] << endl;
}


return 0;
}