小开

For your case, you may use regex:

boolean isValidFormat = input.matches("([0-9]{2})/([0-9]{2})/([0-9]{4})");

For a larger scope or if you want a flexible solution, refer to MadProgrammer's answer.

Edit

Almost 5 years after posting this answer, I realize that this is a stupid way to validate a date format. But i'll just leave this here to tell people that using regex to validate a date is unacceptable

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Disclaimer

Parsing a string back to date/time value in an unknown format is inherently impossible (let's face it, what does 3/3/3 actually mean?!), all we can do is "best effort"

Important

This solution doesn't throw an Exception, it returns a boolean, this is by design. Any Exceptions are used purely as a guard mechanism.

2018

Since it's now 2018 and Java 8+ has the date/time API (and the rest have the ThreeTen backport). The solution remains basically the same, but becomes slightly more complicated, as we need to perform checks for:

date and time
date only
time only

This makes it look something like...

public static boolean isValidFormat(String format, String value, Locale locale) {
LocalDateTime ldt = null;
DateTimeFormatter fomatter = DateTimeFormatter.ofPattern(format, locale);


try {
ldt = LocalDateTime.parse(value, fomatter);
String result = ldt.format(fomatter);
return result.equals(value);
} catch (DateTimeParseException e) {
try {
LocalDate ld = LocalDate.parse(value, fomatter);
String result = ld.format(fomatter);
return result.equals(value);
} catch (DateTimeParseException exp) {
try {
LocalTime lt = LocalTime.parse(value, fomatter);
String result = lt.format(fomatter);
return result.equals(value);
} catch (DateTimeParseException e2) {
// Debugging purposes
//e2.printStackTrace();
}
}
}


return false;
}

This makes the following...

System.out.println("isValid - dd/MM/yyyy with 20130925 = " + isValidFormat("dd/MM/yyyy", "20130925", Locale.ENGLISH));
System.out.println("isValid - dd/MM/yyyy with 25/09/2013 = " + isValidFormat("dd/MM/yyyy", "25/09/2013", Locale.ENGLISH));
System.out.println("isValid - dd/MM/yyyy with 25/09/2013 12:13:50 = " + isValidFormat("dd/MM/yyyy", "25/09/2013  12:13:50", Locale.ENGLISH));
System.out.println("isValid - yyyy-MM-dd with 2017-18--15 = " + isValidFormat("yyyy-MM-dd", "2017-18--15", Locale.ENGLISH));

output...

isValid - dd/MM/yyyy with 20130925 = false
isValid - dd/MM/yyyy with 25/09/2013 = true
isValid - dd/MM/yyyy with 25/09/2013 12:13:50 = false
isValid - yyyy-MM-dd with 2017-18--15 = false

Original Answer

Simple try and parse the String to the required Date using something like SimpleDateFormat

Date date = null;
try {
SimpleDateFormat sdf = new SimpleDateFormat(format);
date = sdf.parse(value);
if (!value.equals(sdf.format(date))) {
date = null;
}
} catch (ParseException ex) {
ex.printStackTrace();
}
if (date == null) {
// Invalid date format
} else {
// Valid date format
}

You could then simply write a simple method that performed this action and returned true when ever Date was not null...

As a suggestion...

Updated with running example

I'm not sure what you are doing, but, the following example...

import java.text.ParseException;
import java.text.SimpleDateFormat;
import java.util.Date;


public class TestDateParser {


public static void main(String[] args) {
System.out.println("isValid - dd/MM/yyyy with 20130925 = " + isValidFormat("dd/MM/yyyy", "20130925"));
System.out.println("isValid - dd/MM/yyyy with 25/09/2013 = " + isValidFormat("dd/MM/yyyy", "25/09/2013"));
System.out.println("isValid - dd/MM/yyyy with 25/09/2013 12:13:50 = " + isValidFormat("dd/MM/yyyy", "25/09/2013  12:13:50"));
}


public static boolean isValidFormat(String format, String value) {
Date date = null;
try {
SimpleDateFormat sdf = new SimpleDateFormat(format);
date = sdf.parse(value);
if (!value.equals(sdf.format(date))) {
date = null;
}
} catch (ParseException ex) {
ex.printStackTrace();
}
return date != null;
}


}

Outputs (something like)...

java.text.ParseException: Unparseable date: "20130925"
isValid - dd/MM/yyyy with 20130925 = false
isValid - dd/MM/yyyy with 25/09/2013 = true
isValid - dd/MM/yyyy with 25/09/2013 12:13:50 = false
at java.text.DateFormat.parse(DateFormat.java:366)
at javaapplication373.JavaApplication373.isValidFormat(JavaApplication373.java:28)
at javaapplication373.JavaApplication373.main(JavaApplication373.java:19)

Not correct. For isValidFormat("yyyy-MM-dd", "2017-18--15"); not throw any Exception.

isValid - yyyy-MM-dd", "2017-18--15 = false

Seems to work as expected for me - the method doesn't rely on (nor does it throw) the exception alone to perform it's operation

小开

You can try this to simple date format valdation

 public Date validateDateFormat(String dateToValdate) {


SimpleDateFormat formatter = new SimpleDateFormat("dd-MM-yyyy HHmmss");
//To make strict date format validation
formatter.setLenient(false);
Date parsedDate = null;
try {
parsedDate = formatter.parse(dateToValdate);
System.out.println("++validated DATE TIME ++"+formatter.format(parsedDate));


} catch (ParseException e) {
//Handle exception
}
return parsedDate;
}

小开

DateFormat formatter = new SimpleDateFormat("dd/MM/yyyy");
formatter.setLenient(false);
try {
Date date= formatter.parse("02/03/2010");
} catch (ParseException e) {
//If input date is in different format or invalid.
}

formatter.setLenient(false) will enforce strict matching.

If you are using Joda-Time -

private boolean isValidDate(String dateOfBirth) {
boolean valid = true;
try {
DateTimeFormatter formatter = DateTimeFormat.forPattern("dd/MM/yyyy");
DateTime dob = formatter.parseDateTime(dateOfBirth);
} catch (Exception e) {
valid = false;
}
return valid;
}

小开

A combination of the regex and SimpleDateFormat is the right answer i believe. SimpleDateFormat does not catch exception if the individual components are invalid meaning, Format Defined: yyyy-mm-dd input: 201-0-12 No exception will be thrown.This case should have been handled. But with the regex as suggested by Sok Pomaranczowy and Baby will take care of this particular case.

小开

Here's a simple method:

public static boolean checkDatePattern(String padrao, String data) {
try {
SimpleDateFormat format = new SimpleDateFormat(padrao, LocaleUtils.DEFAULT_LOCALE);
format.parse(data);
return true;
} catch (ParseException e) {
return false;
}
}

小开

Regex can be used for this with some detailed info for validation, for example this code can be used to validate any date in (DD/MM/yyyy) format with proper date and month value and year between (1950-2050)

    public Boolean checkDateformat(String dateToCheck){
String rex="([0]{1}[1-9]{1}|[1-2]{1}[0-9]{1}|[3]{1}[0-1]{1})+
\/([0]{1}[1-9]{1}|[1]{1}[0-2]{2})+
\/([1]{1}[9]{1}[5-9]{1}[0-9]{1}|[2]{1}[0]{1}([0-4]{1}+
[0-9]{1}|[5]{1}[0]{1}))";


return(dateToCheck.matches(rex));
}

小开

For example, if you want the date format to be "03.11.2017"

 if (String.valueOf(DateEdit.getText()).matches("([1-9]{1}|[0]{1}[1-9]{1}|[1]{1}[0-9]{1}|[2]{1}[0-9]{1}|[3]{1}[0-1]{1})" +
"([.]{1})" +
"([0]{1}[1-9]{1}|[1]{1}[0-2]{1}|[1-9]{1})" +
"([.]{1})" +
"([20]{2}[0-9]{2})"))
checkFormat=true;
else
checkFormat=false;


if (!checkFormat) {
Toast.makeText(getApplicationContext(), "incorrect date format! Ex.23.06.2016", Toast.LENGTH_SHORT).show();
}

Java: 检查当前字符串的日期格式是否符合要求的格式

Edit

Disclaimer

Important

2018

Original Answer