&#39；类型ID&#39；与&#39；类型&#39；在C++中

我想知道在C++中typeid和typeof之间有什么区别。我知道的是：

另外，下面是我创建的测试代码test，其中我发现__abc0没有返回我所期望的结果。为什么？

main.CPP

#include <iostream>
#include <typeinfo>  //for 'typeid' to work


class Person {
public:
// ... Person members ...
virtual ~Person() {}
};


class Employee : public Person {
// ... Employee members ...
};


int main () {
Person person;
Employee employee;
Person *ptr = &employee;
int t = 3;


std::cout << typeid(t).name() << std::endl;
std::cout << typeid(person).name() << std::endl;   // Person (statically known at compile-time)
std::cout << typeid(employee).name() << std::endl; // Employee (statically known at compile-time)
std::cout << typeid(ptr).name() << std::endl;      // Person * (statically known at compile-time)
std::cout << typeid(*ptr).name() << std::endl;     // Employee (looked up dynamically at run-time
// because it is the dereference of a pointer
// to a polymorphic class)
}

输出:

bash-3.2$ g++ -Wall main.cpp -o main
bash-3.2$ ./main
i
6Person
8Employee
P6Person
8Employee
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The primary difference between the two is the following

  • typeof is a compile time construct and returns the type as defined at compile time
  • typeid is a runtime construct and hence gives information about the runtime type of the value.

typeof Reference: http://www.delorie.com/gnu/docs/gcc/gcc_36.html

typeid Reference: https://en.wikipedia.org/wiki/Typeid

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typeid can operate at runtime, and return an object describing the run time type of the object, which must be a pointer to an object of a class with virtual methods in order for RTTI (run-time type information) to be stored in the class. It can also give the compile time type of an expression or a type name, if not given a pointer to a class with run-time type information.

typeof is a GNU extension, and gives you the type of any expression at compile time. This can be useful, for instance, in declaring temporary variables in macros that may be used on multiple types. In C++, you would usually use templates instead.

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Answering the additional question:

my following test code for typeid does not output the correct type name. what's wrong?

There isn't anything wrong. What you see is the string representation of the type name. The standard C++ doesn't force compilers to emit the exact name of the class, it is just up to the implementer(compiler vendor) to decide what is suitable. In short, the names are up to the compiler.

These are two different tools. typeof returns the type of an expression, but it is not standard. In C++0x there is something called decltype which does the same job AFAIK.

decltype(0xdeedbeef) number = 0; // number is of type int!
decltype(someArray[0]) element = someArray[0];

Whereas typeid is used with polymorphic types. For example, lets say that cat derives animal:

animal* a = new cat; // animal has to have at least one virtual function
...
if( typeid(*a) == typeid(cat) )
{
// the object is of type cat! but the pointer is base pointer.
}
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最佳答案

C++ language has no such thing as typeof. You must be looking at some compiler-specific extension. If you are talking about GCC's typeof, then a similar feature is present in C++11 through the keyword decltype. Again, C++ has no such typeof keyword.

typeid is a C++ language operator which returns type identification information at run time. It basically returns a type_info object, which is equality-comparable with other type_info objects.

Note, that the only defined property of the returned type_info object has is its being equality- and non-equality-comparable, i.e. type_info objects describing different types shall compare non-equal, while type_info objects describing the same type have to compare equal. Everything else is implementation-defined. Methods that return various "names" are not guaranteed to return anything human-readable, and even not guaranteed to return anything at all.

Note also, that the above probably implies (although the standard doesn't seem to mention it explicitly) that consecutive applications of typeid to the same type might return different type_info objects (which, of course, still have to compare equal).

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You can use Boost demangle to accomplish a nice looking name:

#include <boost/units/detail/utility.hpp>

and something like

To_main_msg_evt ev("Failed to initialize cards in " + boost::units::detail::demangle(typeid(*_IO_card.get()).name()) + ".\n", true, this);
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typeid provides the type of the data at runtime, when asked for. Typedef is a compile time construct that defines a new type as stated after that. There is no typeof in C++ Output appears as (shown as inscribed comments):

std::cout << typeid(t).name() << std::endl;  // i
std::cout << typeid(person).name() << std::endl;   // 6Person
std::cout << typeid(employee).name() << std::endl; // 8Employee
std::cout << typeid(ptr).name() << std::endl;      // P6Person
std::cout << typeid(*ptr).name() << std::endl;     //8Employee

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