返回 nil

这可能很容易,但我似乎不明白为什么 URLWithString:在这里返回零。

//localisationName is a arbitrary string here
NSString* webName = [localisationName stringByAddingPercentEscapesUsingEncoding:NSUTF8StringEncoding];
NSString* stringURL = [NSString stringWithFormat:@"http://maps.google.com/maps/geo?q=%@,Montréal,Communauté-Urbaine-de-Montréal,Québec,Canadae&output=csv&oe=utf8&sensor=false&key=", webName];
NSURL* url = [NSURL URLWithString:stringURL];
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I guess you need to use -[NSString stringByAddingPercentEscapesUsingEncoding:]. See Apple doc.

Another comment is that, as an old timer, I find it a bit uneasy to put non-ASCII characters in a source file. That said, this Apple doc says, starting from 10.4, UTF-16 strings are OK inside @"...". Somehow GCC seems to correctly convert the source file in Latin-1 into UTF-16 in the binary, but I think it's safest to use 7-bit ASCII characters only inside the source code, and use NSLocalizedString.

I think your accented characters are throwing things off; they won't be handled by -stringByAddingPercentEscapesUsingEncoding:.

You need to escape the non-ASCII characters in your hardcoded URL as well:

//localisationName is a arbitrary string here
NSString* webName = [localisationName stringByAddingPercentEscapesUsingEncoding:NSUTF8StringEncoding];
NSString* stringURL = [NSString stringWithFormat:@"http://maps.google.com/maps/geo?q=%@,Montréal,Communauté-Urbaine-de-Montréal,Québec,Canadae&output=csv&oe=utf8&sensor=false", webName];
NSString* webStringURL = [stringURL stringByAddingPercentEscapesUsingEncoding:NSUTF8StringEncoding];
NSURL* url = [NSURL URLWithString:webStringURL];

You can probably remove the escaping of the localisationName since it will be handled by the escaping of the whole string.

The URLWithString: call will return a nil if the string passed to it is malformed. Since NSURL returns nil for malformed urls, NSLog your string and set breakpoints to see exactly what is being passed to your NSURL creation method. If your URLWithString works with a hard coded value, that's further proof that whatever you are passing is malformed.see

You can use NSURL directly without NSString.

//.h file

@interface NewsBrowser : UIViewController {


UIWebView *webView;
NSURL *NewsUrl;


}


@property (nonatomic, retain) IBOutlet UIWebView *webView;


@property(nonatomic,assign)NSURL *NewsUrl;


@end

//.m file

[webView loadRequest:[NSURLRequest requestWithURL:NewsUrl]];

And I pass the URL from another view (using NewsUrl variable) to this view.

Try it.

Use This Function if you deal with file saved on file manager.

NSURL *_url = [NSURL fileURLWithPath:path];

NSURL URLWithString:@"" will return nil if the URL does not conform to RFC 2396 and they must be escaped

If you read through rfc2396 in the link you will get loads of details

A great site I found for checking where the offending character is, choose the path option for URL

http://www.websitedev.de/temp/rfc2396-check.html.gz

UPDATE: Since stringByAddingPercentEscapesUsingEncoding:NSUTF8StringEncoding is deprecated now, you should use stringByAddingPercentEncodingWithAllowedCharacters

[stringURL stringByAddingPercentEncodingWithAllowedCharacters:[NSCharacterSet URLQueryAllowedCharacterSet]];

Here's the list of allowed characters set depending on your case.

+ (NSCharacterSet *)URLUserAllowedCharacterSet;
+ (NSCharacterSet *)URLPasswordAllowedCharacterSet;
+ (NSCharacterSet *)URLHostAllowedCharacterSet;
+ (NSCharacterSet *)URLPathAllowedCharacterSet;
+ (NSCharacterSet *)URLQueryAllowedCharacterSet;
+ (NSCharacterSet *)URLFragmentAllowedCharacterSet;

Reference: https://developer.apple.com/reference/foundation/nsstring/1411946-stringbyaddingpercentencodingwit