C + + 抽象类: 构造函数是或否?

具有一个(或多个)虚纯函数的类是抽象的,它不能用于创建新对象,因此它没有构造函数。

我正在读一本书,书中提供了以下例子:

class Employee {
public:
Employee(const char*, const char*);
~Employee();
const char* getFirstName() const;
const char* getLastName() const;




virtual double earnings() const=0  // pure virtual => abstract class
virtual void print() const


private:
char* firstName, lastName;
};

如果类是抽象的,为什么我们有一个构造函数?它稍后使用这个类(Boss是从 Employee派生的公共类) :

void Boss::Boss (const char* first, const char* last, double s)
: Employee (first, last)
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The Employee class has data and this data needs to be initialized somehow. Constructor is a good way to do that.

firstName and lastName are private members, not accessible to Boss. All the interface to those has to be present in the Employee class, including initialization.

To initialize firstName and lastName. Otherwise you will have to write a code to initilze them in each derived classes' constructors

You're correct when you say that a class that has a pure virtual function is abstract and can't be instantiated. But you're wrong when you say that it can't have a constructor.

Indeed, as your example show, an abstract class can have private members, that may be used by member functions of this class. And these members must be initialized. A constructor is a way to do that (e.g. with an initialization list in the derived class, as your second sample shows), better in my opinion than an init() function for example.

Editing my comment in the answer: An abstract class can have member variables and potentially non-virtual member functions, so that every derived class from the former implements specific features.

Then, the responsibility for the initialization of these members variables may belong to the abstract class (at least always for private members, because the derived class wouldn't be able to initialize them, yet could use some inherited member functions that may use/rely on these members). Thus, it makes it perfectly reasonable for abstract classes to implement constructors.

"An abstract class contains at least one pure virtual function. You declare a pure virtual function by using a pure specifier (= 0) in the declaration of a virtual member function in the class declaration."

regarding:

void Boss::Boss (const char* first, const char* last, double s)
: Employee (first, last)

first and last are defined in the base class, therefore, in order to initialize them, we need to make a call to the constructor of the base class : Employee (first, last)

A class with a pure virtual function can't be instantiated. It is expected to have sub-classes that will extend it and provide the missing functionality.

These sub-classes will construct the base class when they are instantiated, they will call the constructor of their super class which is why abstract classes have constructors in c++.

So you can't create an instance directly and call the constructor directly but future sub-classes will.

The purpose of Abstract class is that you want to extend some functionality by derived classes. Can it have constructor? Yes it can and the purpose is to initialize local variables from the base class. You should avoid using public constructor in Abstract and use protected only.

The example you have is not a good example. Not sure what book it is but that the bad example. Its like defining int variable with name of variable "iAmString" :).

int iAmString = 12;

Cheers

If The base abstract class does not have a constructor, how would you assign values to firstname , lastname members for any derived class, when you are creating an object of the derived class?

Suppose there is a Manager Class derived from Employee which adds Salary data and implements earning(). Now Employee is an abstract class but Manager is a concrete class and hence you can have an object of Manager. But when you are instantialting Manager, you need to initialize/assign values to members inherited from base class i.e. Employee. One way is that you can have Employee0 in the base class for this purpose and you can use them in the constructor for Employee1 or more convenient way would be to have a constructor in your Employee2.

See the code below:

#include <iostream>
#include <cstring>
#include <cstdlib>


using namespace std;




class Employee {
public:
Employee(const char*, const char*);
~Employee();
const char* getFirstName() const;
const char* getLastName() const;




virtual double earnings() const=0;  // pure virtual => abstract class
virtual void print() const;


private:
char* firstname;
char* lastname;
};


Employee::Employee(const char* first, const char* last){
firstname= (char*) malloc((strlen(first)+1)*sizeof(char));
lastname= (char*) malloc((strlen(last)+1)*sizeof(char));
strcpy(firstname,first);
strcpy(lastname,last);
}


Employee::~Employee(){
free(firstname);
free(lastname);
cout << "Employee destructed" << endl;
}


const char* Employee::getFirstName() const{ return firstname;}
const char* Employee::getLastName() const{ return lastname; }
void Employee::print() const{
cout << "Name: " << getFirstName() << " " << getLastName() << endl;
}






class Manager:public Employee{
public:
Manager(char* firstname,char* lastname,double salary):
Employee(firstname,lastname),salary(salary){}


~Manager(){}


double earnings() const {return salary;}


private:
double salary;
};


int main(){


Manager Object("Andrew","Thomas",23000);
Object.print();
cout << " has Salary : " << Object.earnings() << endl;


return 0;
}

An Abstract class is a class which have at least one pure virtual function in it. We cannot instantiate an abstract class. But it can have constructors. see the below example. If we not override the virtual function in derived class, it also become an abstract class,

class Abstract {
private:
int x, y;
public:
virtual void a() = 0;//pure virtual function
Abstract(int x1, int y1) {
x = x1;
y = y1;
}
};


class Base :public Abstract {
private:
int z;
public:
Base(int x, int y, int z1) :Abstract(x, y) {
z = z1;
}
void a() {
}
};


int main() {
Base b(1, 2, 3);
}