Python 是否有一种更简洁的方式来表达“如果 x 包含一个 | b | c

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最佳答案

The Pythonic approach would be to use any():

if any(s in x for s in (a,b,c,d,e,f,g)):

From the linked documentation:

any(iterable)

Return True if any element of the iterable is true. If the iterable is empty, return False. Equivalent to:
def any(iterable):
for element in iterable:
if element:
return True
return False

Also, notice that I've used a tuple instead of a list here. If your a-g values are pre-defined, then a tuple would indeed be preferred. See: Are tuples more efficient than lists in Python?

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if any(q in x for q in [a,b,c,d,e,f,g]):

I think that's about as short & Pythonic as you can get it.

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without using any but simply max

def is_in(symbol, lst):
return max([symbol in x for x in lst])


print is_in('a',['ae','br','tl'])
print is_in('c',['ae','br','tl'])

gives

>>>
True
False

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A bit late to the party, but

not frozenset(x).isdisjoint(frozenset(y))

would work, and may be faster (algorithmically, but maybe not for smaller test cases).

Python 是否有一种更简洁的方式来表达“如果 x 包含一个 | b | c | d...”？