How to convert time in milliseconds to hours, min, sec format in JavaScript?
I have a time as a number of milliseconds and I want to convert it to a HH:MM:SS format. It should wrap around, with milliseconds = 86400000 I want to get 00:00:00.
I had the same problem, this is what I ended up doing:
function parseMillisecondsIntoReadableTime(milliseconds){
//Get hours from milliseconds
var hours = milliseconds / (1000*60*60);
var absoluteHours = Math.floor(hours);
var h = absoluteHours > 9 ? absoluteHours : '0' + absoluteHours;
//Get remainder from hours and convert to minutes
var minutes = (hours - absoluteHours) * 60;
var absoluteMinutes = Math.floor(minutes);
var m = absoluteMinutes > 9 ? absoluteMinutes : '0' + absoluteMinutes;
//Get remainder from minutes and convert to seconds
var seconds = (minutes - absoluteMinutes) * 60;
var absoluteSeconds = Math.floor(seconds);
var s = absoluteSeconds > 9 ? absoluteSeconds : '0' + absoluteSeconds;
return h + ':' + m + ':' + s;
}
var time = parseMillisecondsIntoReadableTime(86400000);
alert(time);
var sunriseMills = 1517573074000; // sunrise in NewYork on Feb 3, 2018 - UTC time
var offsetCityMills = -5 * 3600 * 1000; // NewYork delay to UTC
var offsetDeviceMills = new Date().getTimezoneOffset() * 60 * 1000 ; // eg. I live in Romania (UTC+2) >> getTimezoneOffset() = 120
var textTime = new Date(sunriseMills + offsetCityMills + offsetDeviceMills)
.toLocaleTimeString('en-US', { hour: 'numeric', minute: 'numeric' });
Based on @Chand answer. This is the implementation in Typescript. A bit safer than coercing types in JS. If you remove the type annotation should be valid JS. Also using new string functions to normalise the time.
The above snippets don't work for cases with more than 1 day (They are simply ignored).
For this you can use:
function convertMS(ms) {
var d, h, m, s;
s = Math.floor(ms / 1000);
m = Math.floor(s / 60);
s = s % 60;
h = Math.floor(m / 60);
m = m % 60;
d = Math.floor(h / 24);
h = h % 24;
h += d * 24;
return h + ':' + m + ':' + s;
}
This solution uses one function to split milliseconds into a parts object, and another function to format the parts object.
I created 2 format functions, one as you requested, and another that prints a friendly string and considering singular/plural, and includes an option to show milliseconds.
function parseDuration(duration) {
let remain = duration
let days = Math.floor(remain / (1000 * 60 * 60 * 24))
remain = remain % (1000 * 60 * 60 * 24)
let hours = Math.floor(remain / (1000 * 60 * 60))
remain = remain % (1000 * 60 * 60)
let minutes = Math.floor(remain / (1000 * 60))
remain = remain % (1000 * 60)
let seconds = Math.floor(remain / (1000))
remain = remain % (1000)
let milliseconds = remain
return {
days,
hours,
minutes,
seconds,
milliseconds
};
}
function formatTime(o, useMilli = false) {
let parts = []
if (o.days) {
let ret = o.days + ' day'
if (o.days !== 1) {
ret += 's'
}
parts.push(ret)
}
if (o.hours) {
let ret = o.hours + ' hour'
if (o.hours !== 1) {
ret += 's'
}
parts.push(ret)
}
if (o.minutes) {
let ret = o.minutes + ' minute'
if (o.minutes !== 1) {
ret += 's'
}
parts.push(ret)
}
if (o.seconds) {
let ret = o.seconds + ' second'
if (o.seconds !== 1) {
ret += 's'
}
parts.push(ret)
}
if (useMilli && o.milliseconds) {
let ret = o.milliseconds + ' millisecond'
if (o.milliseconds !== 1) {
ret += 's'
}
parts.push(ret)
}
if (parts.length === 0) {
return 'instantly'
} else {
return parts.join(' ')
}
}
function formatTimeHMS(o) {
let hours = o.hours.toString()
if (hours.length === 1) hours = '0' + hours
let minutes = o.minutes.toString()
if (minutes.length === 1) minutes = '0' + minutes
let seconds = o.seconds.toString()
if (seconds.length === 1) seconds = '0' + seconds
return hours + ":" + minutes + ":" + seconds
}
function formatDurationHMS(duration) {
let time = parseDuration(duration)
return formatTimeHMS(time)
}
function formatDuration(duration, useMilli = false) {
let time = parseDuration(duration)
return formatTime(time, useMilli)
}
console.log(formatDurationHMS(57742343234))
console.log(formatDuration(57742343234))
console.log(formatDuration(5423401000))
console.log(formatDuration(500))
console.log(formatDuration(500, true))
console.log(formatDuration(1000 * 30))
console.log(formatDuration(1000 * 60 * 30))
console.log(formatDuration(1000 * 60 * 60 * 12))
console.log(formatDuration(1000 * 60 * 60 * 1))
msToTime(milliseconds) {
//Get hours from milliseconds
var hours = milliseconds / (1000*60*60);
var absoluteHours = Math.floor(hours);
var h = absoluteHours > 9 ? absoluteHours : '0' + absoluteHours;
//Get remainder from hours and convert to minutes
var minutes = (hours - absoluteHours) * 60;
var absoluteMinutes = Math.floor(minutes);
var m = absoluteMinutes > 9 ? absoluteMinutes : '0' + absoluteMinutes;
//Get remainder from minutes and convert to seconds
var seconds = (minutes - absoluteMinutes) * 60;
var absoluteSeconds = Math.floor(seconds);
var s = absoluteSeconds > 9 ? absoluteSeconds : '0' + absoluteSeconds;
return h == "00" ? m + ':' + s : h + ':' + m + ':' + s;
}
let h,m,s;
h = Math.floor(timeInMiliseconds/1000/60/60);
m = Math.floor((timeInMiliseconds/1000/60/60 - h)*60);
s = Math.floor(((timeInMiliseconds/1000/60/60 - h)*60 - m)*60);
// to get time format 00:00:00
s < 10 ? s = `0${s}`: s = `${s}`
m < 10 ? m = `0${m}`: m = `${m}`
h < 10 ? h = `0${h}`: h = `${h}`
console.log(`${s}:${m}:${h}`);
Human-readable code for human-readable output and you can extend this to light years or nanoseconds or what have you very intuitively. Obviously you'd want to convert this to a function and re-use some of those intermediate modulo calls.
second = 1000
minute = second * 60
hour = minute * 60
day = hour * 24
test = 3 * day + 2 * hour + 11 * minute + 58 * second
console.log(Math.floor(test / day))
console.log(Math.floor(test % day / hour))
console.log(Math.floor(test % day % hour / minute))
console.log(Math.floor(test % day % hour % minute / second))
I works for me as i get milliseconds=1592380675409 using javascript method getTime() which returns the number of milliseconds between midnight of January 1, 1970 and the specified date.
var d = new Date();//Wed Jun 17 2020 13:27:55 GMT+0530 (India Standard Time)
var n = d.getTime();//1592380675409 this value is store somewhere
//function call
console.log(convertMillisecToHrMinSec(1592380675409));
var convertMillisecToHrMinSec = (time) => {
let date = new Date(time);
let hr = date.getHours();
let min = date.getMinutes();
let sec = date.getSeconds();
hr = (hr < 10) ? "0"+ hr : hr;
min = (min < 10) ? "0"+ min : min;
sec = (sec < 10) ? "0"+ sec : sec;
return hr + ':' + min + ":" + sec;//01:27:55
}
There are probably better ways to do that, but this naive solution gets the job done.
Test:
let asSeconds = 59.5219;
let seconds = Math.floor(asSeconds);
console.log(`${pad(seconds)}${(asSeconds % 1).toFixed(3).substring(1)}`);
// Equivalent to above, without using `pad()`:
//console.log(`${String(seconds).padStart(2, '0')}${(asSeconds % 1).toFixed(3).substring(1)}`);
// Output: 59.522
/**
* Converts milliseconds into greater time units as possible
* @param {int} ms - Amount of time measured in milliseconds
* @return {?Object} Reallocated time units. NULL on failure.
*/
function timeUnits( ms ) {
if ( !Number.isInteger(ms) ) {
return null
}
/**
* Takes as many whole units from the time pool (ms) as possible
* @param {int} msUnit - Size of a single unit in milliseconds
* @return {int} Number of units taken from the time pool
*/
const allocate = msUnit => {
const units = Math.trunc(ms / msUnit)
ms -= units * msUnit
return units
}
// Property order is important here.
// These arguments are the respective units in ms.
return {
// weeks: allocate(604800000), // Uncomment for weeks
days: allocate(86400000),
hours: allocate(3600000),
minutes: allocate(60000),
seconds: allocate(1000),
ms: ms // remainder
}
}
It's written in such a way so that you can easily implement other units (for example, where I commented out implementation for weeks) so long as you know their worth in milliseconds.
A Date object can be constructed from milliseconds:
const date = new Date(0, 0, 0, 0, 0, 0, milliseconds);
In your question you say milliseconds seconds should 'wrap around' at 86400000. Since we know there are 86400000 milliseconds in a day, we can simply take the time from the date object, and ignore every other part of the date as irrelevant.
The time can then be obtained in any number of formats. The one you require matches that used in the United Kingdom, localeen-GB: