How to call super in PHP?

I have a classB which extends classA.

In both classA and classB I define the method fooBar().

In fooBar() of classB I want to call fooBar() of classA at the beginning.

Just the way I'm used to, from Objective-C. Is that possible in PHP? And if so, how?

71913

<?php class MyClass { protected function myFunc() { echo "MyClass::myFunc()\n"; } } class OtherClass extends MyClass { // Override parent's definition public function myFunc() { // But still call the parent function parent::myFunc(); echo "OtherClass::myFunc()\n"; } } $class = new OtherClass(); $class->myFunc(); ?>

小开

Just a quick note because this doesn't come up as easy on Google searches, and this is well documented in php docs if you can find it. If you have a subclass that needs to call the superclass's constructor, you can call it with:

parent::__construct(); // since PHP5

An example would be if the super class has some arguments in it's constructor and it's implementing classes needs to call that:

class Foo {


public function __construct($lol, $cat) {
// Do stuff specific for Foo
}


}


class Bar extends Foo {


public function __construct()(
parent::__construct("lol", "cat");
// Do stuff specific for Bar
}


}

You can find a more motivating example here.

最佳答案

parent::fooBar();

Straight from the manual:

The ... double colon, is a token that allows access to ... overridden properties or methods of a class.

...

Example #3 Calling a parent's method
<?php
class MyClass
{
protected function myFunc() {
echo "MyClass::myFunc()\n";
}
}


class OtherClass extends MyClass
{
// Override parent's definition
public function myFunc()
{
// But still call the parent function
parent::myFunc();
echo "OtherClass::myFunc()\n";
}
}


$class = new OtherClass();
$class->myFunc();
?>